Germany ~ Can you solve this ?? | Math Olympiad

[@Ernesto1317]

It is nice explanation but that problem could never be a Math Olympiad problem!!

[@spicythewy1383]

9^(x+2) =36 log36 base 9 = x+2 log 9 base 9 + log 4 base 9 =x + 2 1+ log 4 base 9 =x+2 log4 base 9 - 1= x

[@MrKaydo-zc8tq]

Great detail. However, you could make the verification easier if you stopped at log(4)/log(9)=log_9(4) since the equation uses a 9 base. 9^(log_9(4)-1+2)=9^(log_9(4)+1)=4*9=36

[@aruntiwari5714]

Happy learning 🎉

[@harshpathak2359]

Nice solution

[@satyadev3848]

nice solution

[@karm76]

9^(x+2) = 36 divide by 9 9^(x+2-1) = 4 3^2(x+1) = 2^2 2(x+1) log 3 = 2 log 2 x + 1 = 2 log 2 / 2 log 3 x = log 2/log 3 - 1

[@brachinusGT]

x + 2 = log 9 (36) first line, nearly finished. Your solution is just nonsense.

[@ioannisimansola7115]

Does not deserve any Olympiad level , just basic highschool stuff

[@KeshavKulkarni-x1w]

Well explained

[@DarshChouhan-r6g]

Great learning

[@VermaRajinder]

Interesting!!! 😂

[@manojchaugule794]

you deseve great things

[@LaxmanKumar-yi4cv]

Perfect learning

[@KhushiTtripathi]

WOnderful explaination

[@NithyaGhumare]

It's great pleasure

[@harikishan1900]

Great things

[@vincentr.9354]

No se entiende nada, no se entendió un coño.

[@arvindkulkarni6580]

Nice solution