Germany| Exponential Math question|can you solve this.

[@BrijLalSahu-bb1lu]

Very nice solution

[@JJONLINEMATHSCLASSchannel]

Thanks

[@navodshehan1604]

☺️❤️

[@Amt-p2h]

❤🙋‍♂️👍👍👍👍👍

[@JJONLINEMATHSCLASSchannel]

👍

[@عبدالواسع-س8م]

Great work! Thank you so much!

[@JJONLINEMATHSCLASSchannel]

Our pleasure!

[@RyanLewis-Johnson-wq6xs]

4^(Log[4,1.3 recurring]+2)=24 x=Log[4,1.3 recurring]+2=(3/2)+(1/2)Log[2,3]

[@JJONLINEMATHSCLASSchannel]

Thank you

[@maths01n]

Love the way you keep smiling through out giving us hope even if it is a technical problem keep up my fellow Mathematician that's the spirit ❤❤❤❤❤❤❤❤

[@JJONLINEMATHSCLASSchannel]

Thank you

[@omelelet]

amazing! thank you sm!!!

[@JJONLINEMATHSCLASSchannel]

Glad you like it!

[@garryfrancois2320]

Very good job JJ!

[@JJONLINEMATHSCLASSchannel]

Thanks for listening

[@Amt-p2h]

When will you show us all the formulas related to logarithms ? Thanks so much

[@JJONLINEMATHSCLASSchannel]

U are welcome. Just keep watching, I will keep implementing them when necessary

[@Amt-p2h]

Did u understand what I mean by this request?👆👆

[@Amt-p2h]

@@JJONLINEMATHSCLASSchannel thanks so much 4ur response to my request 😊

[@ZackJRich]

4^x = 24 2^(2x) = 24 / log base 2 2x = log base 2 (24) 2x = log base 2 (8 × 3) 2x = log base 2 (8) + log base 2 (3) 2x = 3 + log base 2 (3) / ÷2 x = [3 + log base 2 (3)]/2 or x = 3/2 + log base 4 (3)

[@JJONLINEMATHSCLASSchannel]

👍👍

[@BN-hy1nd]

Yep

[@JJONLINEMATHSCLASSchannel]

👍