Прекрасный урок! Вы как всегда можете сложное разложить на простое) Именно такой подход к электронике делает ее привлекательной и прекрасной. Спасибо Вам огромное
@sambenyaakovАй бұрын
спасибо
@BeMuslimOnly2 ай бұрын
As i have watched this video 3 times,now i am confident and Tomorrow i will calculate the total capacitance of my mosfet for the very first time in LTspice. ❤ It was an amazing lecture.
@sambenyaakov2 ай бұрын
😊👍🙏
@tseckwr37833 ай бұрын
Always a pleasure to view your informative videos.
@sambenyaakov3 ай бұрын
👍🙏
@Blue73ocean3 ай бұрын
Your efforts are highly appreciated Prof Yaakov, thanks a lot.
@sambenyaakov3 ай бұрын
Thanks.
@sanjayagrawal61433 ай бұрын
Thanks Sir for educating us. All your lectures are loaded with lot of wisdom. Thanks
@sambenyaakov3 ай бұрын
So nice of you. Thanks.
@LaboussoleNano11 күн бұрын
Thanks for this vidéo
@sambenyaakov10 күн бұрын
So nice of you
@qqb84123 ай бұрын
another question: in 17:53, why Vcin slightly decreases at Vg>4V(miller plateau)? you mentioned small signal but i am still confused.
@sambenyaakov2 ай бұрын
If Q(V) is sort of exponential and you divide Q/V to get Ct at points along the curve, the value decreases at high voltages.
@LaboussoleNano11 күн бұрын
THANKS AGAIN FOR THIS VIDEO? I have some questions: -Why Capacitance Ciss, Coss.. are measured at 1MHz AC signal ? -another one for Qg, does the formula is Qg=Ig*dt ? (dt=1/frequency ----- frequency= what in this case??)
@sambenyaakov10 күн бұрын
This is how the industry is specifying the capacitances. Just a pointer.
@LaboussoleNano8 күн бұрын
@@sambenyaakov THANKS FOR ANSWERING
@qqb84123 ай бұрын
Hi professor, can we do such calculation: For Qgs, we do Qgs=15V*Cgs (normally Cgs is constant in this voltage range). For Qgd, we do Qgd=Cgd(er)*Vb+∫Cgd*Vgs(0-15V) er=energy related Thank you in advance for your education.