Getting the input capacitance and input charge of MOSFET gates

  Рет қаралды 3,605

Sam Ben-Yaakov

Sam Ben-Yaakov

Күн бұрын

Пікірлер: 27
@SMV1972
@SMV1972 Ай бұрын
Прекрасный урок! Вы как всегда можете сложное разложить на простое) Именно такой подход к электронике делает ее привлекательной и прекрасной. Спасибо Вам огромное
@sambenyaakov
@sambenyaakov Ай бұрын
спасибо
@BeMuslimOnly
@BeMuslimOnly 2 ай бұрын
As i have watched this video 3 times,now i am confident and Tomorrow i will calculate the total capacitance of my mosfet for the very first time in LTspice. ❤ It was an amazing lecture.
@sambenyaakov
@sambenyaakov 2 ай бұрын
😊👍🙏
@tseckwr3783
@tseckwr3783 3 ай бұрын
Always a pleasure to view your informative videos.
@sambenyaakov
@sambenyaakov 3 ай бұрын
👍🙏
@Blue73ocean
@Blue73ocean 3 ай бұрын
Your efforts are highly appreciated Prof Yaakov, thanks a lot.
@sambenyaakov
@sambenyaakov 3 ай бұрын
Thanks.
@sanjayagrawal6143
@sanjayagrawal6143 3 ай бұрын
Thanks Sir for educating us. All your lectures are loaded with lot of wisdom. Thanks
@sambenyaakov
@sambenyaakov 3 ай бұрын
So nice of you. Thanks.
@LaboussoleNano
@LaboussoleNano 11 күн бұрын
Thanks for this vidéo
@sambenyaakov
@sambenyaakov 10 күн бұрын
So nice of you
@qqb8412
@qqb8412 3 ай бұрын
another question: in 17:53, why Vcin slightly decreases at Vg>4V(miller plateau)? you mentioned small signal but i am still confused.
@sambenyaakov
@sambenyaakov 2 ай бұрын
If Q(V) is sort of exponential and you divide Q/V to get Ct at points along the curve, the value decreases at high voltages.
@LaboussoleNano
@LaboussoleNano 11 күн бұрын
THANKS AGAIN FOR THIS VIDEO? I have some questions: -Why Capacitance Ciss, Coss.. are measured at 1MHz AC signal ? -another one for Qg, does the formula is Qg=Ig*dt ? (dt=1/frequency ----- frequency= what in this case??)
@sambenyaakov
@sambenyaakov 10 күн бұрын
This is how the industry is specifying the capacitances. Just a pointer.
@LaboussoleNano
@LaboussoleNano 8 күн бұрын
@@sambenyaakov THANKS FOR ANSWERING
@qqb8412
@qqb8412 3 ай бұрын
Hi professor, can we do such calculation: For Qgs, we do Qgs=15V*Cgs (normally Cgs is constant in this voltage range). For Qgd, we do Qgd=Cgd(er)*Vb+∫Cgd*Vgs(0-15V) er=energy related Thank you in advance for your education.
@sambenyaakov
@sambenyaakov 2 ай бұрын
Yes indeed. Good thinking.
@doronlola1763
@doronlola1763 3 ай бұрын
Thanks Professor Yaakov
@sambenyaakov
@sambenyaakov 3 ай бұрын
👍🙏
@biswajit681
@biswajit681 3 ай бұрын
21 more to go to reach 500 milestone!!!!
@sambenyaakov
@sambenyaakov 3 ай бұрын
Working on it. Stay tuned.
@SAhellenLily
@SAhellenLily 3 ай бұрын
Thank you 👍
@sambenyaakov
@sambenyaakov 3 ай бұрын
🙏
@tamaseduard5145
@tamaseduard5145 3 ай бұрын
👍🙏❤️
@sambenyaakov
@sambenyaakov 3 ай бұрын
😊👍🙏
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