Go and solve this math problem

[@kpt123456]

Nice solution

[@fadhlurrahmanal-akbar7786]

Nice

[@MathOrient]

Love your algebra brother :)

[@Mathematica1997]

Thank you 😊

[@kshitijdeshmukh3291]

sir if we got a⁶ common in second eqⁿ and put a²+1=a it'll give a = (-1) (and some imaginary roots) Which will don't satisfy frist equation because it has imaginary roots If we put a = -1 in second eqⁿ it'll give answer 3

[@이용현-z3j]

Without your explanation, how can the general man solve that algebraic problem? Thanks for your posting. 😍

[@Mathematica1997]

😊

[@igorhenrique9319]

Very good, my friend. 👏🏻🗿🍷

[@Mathematica1997]

Thank you 😊

[@igorhenrique9319]

@@Mathematica1997 🇧🇷

[@luisalvarez3063]

a^2 - a + 1 = 0 then a= (1 + - SQRT(1-4))/2 -- then a = (1 + SQRT(3)*i)/2 or a = (1- SQRT(3)*i)/2 a is not a real number, but a^3 = -1 ¿How is possible?

[@nahbro1321]

I did it in 3 min with different method although urs was little better then me..

[@laavanyarajan4444]

I did it immediately as I found it analogous to cube roots of unity

[@Mathematica1997]

Wow nice observation

[@nayankarmakar6541]

May i get that math group link again please sirr??

[@Mathematica1997]

chat.whatsapp.com/IrM1yjoQSNWFra8yv6dp2v

[@nayankarmakar6541]

@@Mathematica1997 thanks sirr🥰

[@sanjaymohankumar6677]

yo u r god

[@aboubachir7286]

I hope that you can help me solving this task from an olympiad. If you know that the number: 11A 111 111 111 111 111 111 111 111 111 111 111 111 111 111 111 104 Is a multiple from the number 2016, What is the value of the number A?💐

[@Mathematica1997]

I'll try to attempt this one