(Graph) Newton's Law of Cooling And find Cooling Constant. |XII PHY Experiments| (Urdu/Hindi)

[@vaiebhavpatil2340]

Anyone for 2020 practicals?

[@hellboygaming1387]

2024

[@trgraza4038]

Kon kon practicals ke lie aaya h 🤣 angootha lagao 😅😅

[@rabiyajameel5287]

Seriously a man with zero percent attitude .....may Allah Bless you ♥️

[@husbanburney2789]

You have clearly put in alot of effort over this video.... And explained it in a really amazing way.. Hats off!

[@nidamaahi4822]

You explained so well .its really clear all the concepts of mine .thanks alot

[@faizanhassan4829]

24:52 this is a mistake this is 56.5°C not 51.5°C

[@archanasalalkar5479]

You are right. I was also telling him

[@khan_affan]

Yup thank you, for correction... I will look into it another time & will add your pointed correction in description... Thanks again

[@kinzasyed520]

sir agr hum temperature axis me 1 small box equals to one centi hi len or 0.5 ki value kpo s,mall box k beech me lgaden to thk hoga?

[@kinzasyed520]

plz reply fast sir kl practical h

[@khan_affan]

@@kinzasyed520 🙏🙏🙏🙏 Sorry agar practical guzar gya, baqi ye hai k jo aap ne bataya hai wo chal jata hai lekin behtar ye hai k least count k hisab se ek small box ko 0.5 degree celsius hi lein.

[@AmmarSports]

Sir zruri hai k line points me hoti hui hi jaye ?

[@AmmarSports]

sir graph plot krne k lie temperature ko room temperature se minus krvana hai ya aese hi bnaaden jese nikala tha ??

[@Esloques]

No simple Jo readings ayi thi 70 ,69 wo plot karni hai

[@AmmarSports]

@@Esloques pakka ? kch aur to ni krna ?? Bs time k sth Jo readings nikaali hain bs unka graph ?

[@Esloques]

@@AmmarSports yes

[@AmmarSports]

@@Esloques Thank u

[@a.khalique149]

Brother thank you for this but there are 3 graphs we have to draw...

[@khan_affan]

Kindly let us know which Board you are following so we may guide further.... Sorry for being late...

[@RECITOR_HJ]

Assalamualikum sir yeh kahri wali reading mein masla lagra hai ?? pls reply

[@Vivek-uu2gq]

Use black pen on graph for better ....clear vision

[@alizayzaheer1124]

hum graph ki valur ka diff but karaingay ya obs table se fall of temp mai?

[@khan_affan]

اپنا سوال تھوڑا کلیئر کریں، میں نہیں سمجھ سکا۔ اور یہ بھی بتائیں ویڈیو میں کس پوائنٹ پر؟

[@meghnashukla3973]

Thank you so much it helped a lot!!!keep going sir😀

[@introvert911]

Mujhe ya practical mila h or graph smjh ni aarhi thi thank you...or sir agr hamne reading jo pehle likhi ho practical class ma agr wahi same ajaye tw koi msla ni hoga?

[@khan_affan]

aisa koi masla to nahi, but same aati nahi hain... variation ajata hai

[@naziashaikh8420]

plz sir, explain, Zener diode ki reading with graph (1.5)

[@cuteangel3048]

Yes sir plzzzzz

[@ashimano8120]

You did perfect

[@rahulkhilchi7803]

ASSALAMVALEKUM BHaiya mera exam 11 bje se shuru ho jaega aur aapki video dekh kr lg rha h ek no jaega tqqqqqqq love u bhaiyAAAA

[@khan_affan]

Kaisa raha exam?

[@rahulkhilchi7803]

Op rha,27/30 thanks

[@gulamna731]

Jo Physics ka First Practical hai jismein Heat Capacity Of Metal Bob Find Out karni hoti hai , usmein Theory ke andar kiya kiya likhenge ??? Plzz Mention It Here 🙏🏻🙏🏻🙏🏻

[@alishbafayyaz9082]

Assalam alikum sir your explanation is very helpful for me and other students thank you so much sir 😁

[@ramlakamran2024]

If cooling constant will be 0.02 then will it be oky?

[@khan_affan]

Yess

[@mahmedkhan4123]

Aoa sir kal practical hai thanks for help ❤

[@khan_affan]

🙏🏽❤️... Good Luck dear ...

[@judy_op2245]

Thanks alot sir 🙂

[@gauravjha1061]

Sir you are genius you have cleary put a lot of efforts. Thankyu sir

[@ksamirakhan]

Sir mery pass graph m cooling constant ki value 0.07 a rhi hai to kya ye thk hogi

[@khan_affan]

thora dur hai... try again, then discuss

[@mylittleworld1668]

Sir ap boht acha samjhaty hai sary points clear hogay thank you so much😊

[@huzaifaawais9274]

Good Work there :D

[@sarazahid4496]

Thank you Soo Much 🌟 Sir very well explained 💯🎀🥺👌

[@kurbanalishaikh]

mirror wala used nhi hua cooling constat ke liye? & nice video please use scatch pen because pencil dikh nhi rahi bahut zagah par.

[@khan_affan]

Sorry for inconvenience... Didn't realize this while recording... Try to increase the brightness of device, this might help... And we will consider this factor in further recordings...

[@muhammadfahadqazi8529]

Sir agar temp axis per 10 small box consider kreyingey tou phir plotting kese hoji

[@khan_affan]

Same pattern hoga... Bus aap ke points height wise qareeb qareeb hojayeingy... Just try to locate correct temperature at given time... Like 1 min wali vertical line ko dekho or jo temperature ho uspe us horizontal line ko dekho, un dono lines k jahan mil rahi houn wo point mark kardo, similarly for all other values...

[@khan_affan]

Hope its clear to you, you can ask if it is still confusing...

[@m_arman_sheikh]

Sir ye straight nhi banega graf?

[@isabelledharia8067]

Kl practical hy Mera

[@sirmuhammadahsan4826]

sir graph mai , apny 60 se phly 55 tw consider kiya but temperature chnge 51.5 or 52.5 kyn consider q kiya h ??

[@khan_affan]

Yup you are correct bus counting me thori mistake hogai... 56.5 and 57.5 hoga... JzakAllahu Khairan for correction...

[@aalapvedpathak6672]

Sir, in our book cooling constant is not written but rate of fall of d theta/dt is written. Can you explain it please fast.

[@prathamraut6014]

Sir Maharashtra board ka bhi newtons law of cooling with using mirror bana do . Plss sir

[@dhairyadave1806]

allahu akbar💣

[@darshan9311]

Thanx sir ...very helpful kal mera practical hai ....thaNxxxxxxxxxxxxxx

[@khan_affan]

Let me know... How was your Practical?

[@nisarkhankhan227]

Jazakallah sir

[@aimiikhan1616]

Thankx .❤

[@魔鬼似的]

great finally found what i was scearching for

[@Sarikadevi-4]

Thank u sir 😊🙏

[@alishbaafroz4146]

Jazak Allah sir ❤️

[@MuhammadZohaib-w1j]

👍👍

[@malihajaved6512]

Thank u .....that helps me alot💖💖💖

[@chetanainakar2483]

But in my college,mirror is used to plot graph

[@bogo_indian]

MARVEL Entertain same here

[@prathamraut6014]

Same here bro . 😅😎

[@aliakhan2351]

Yes

[@pravinmirashi1046]

Same here😪😪

[@cleopatra8734]

Okay is there a way to plot so that there is a linear relationship?

[@khan_affan]

I guess log se ho shaid, I am not confirm, but I believe there must be...

[@anuragtiwari2098]

Sir Thank You very much for both the videos on Newtons laws of Cooling. they have immensely helped me in my project. keep making videos on ISC & CBSE practical videos . thanks again

[@areebarao847]

Thank you sir for the amazing video

[@areebarana6184]

Sir i appreciate you aapne students ki bhhhht help kia hai thank you so much

[@HamzaKhan-ti7su]

Love you sir you clear my donuts❤️

[@SWAPTECH20]

Sir plz new syllabus maise physics ke jo tin graph kaise nikale uski video banakar daale plz plz

[@khan_affan]

Dear aap ka board konsa hai?

[@artilonare1712]

Thanks sir ji 🙏🏻

[@shardaeducare]

KINDLY SHOW HOW TO PLOT d theta by dt

[@khan_affan]

You can discuss it here... facebook.com/PhyWithKhan/

[@heee302]

how can we find out the slope of tangent?

[@mfawwadali3734]

kon kon practical ki last night yanha pa aaiya hai .like karo👇

[@manhbuivan5572]

Sir plz used any marker plz btw really help full

[@shivrajdaund66]

Thanks 😘 Very helpful

[@tehreemtahir4959]

JazakAllah

[@Mehwish-uq2hi]

Thank you soooo muchhhhhh ... Very helpful 🤍✨

[@manahilahmed39]

thank you so much 👍

[@shehbazkhan2269]

Sir ye point 5 smj nhi araha kese aayega

[@khanabasi1318]

Target audience: BIEK Actual audience: Of india

[@tejitchaudhari4923]

Thank you sir for both videos . But I han an dought That , why graph is plot in forth quadrant ?

[@SPARKcreative]

Tejit Chaudhari because temperature is decreasing

[@khan_affan]

I second @SPARK

[@Fatii388]

Sir please dark pen use keya kejeye ❤

[@khan_affan]

بہت معزرت ۔۔۔ Recommended full HD and maximum brightness 🙏🏽

[@rakeshvalvi5192]

Good

[@mohammadyusuf9124]

sir plzz sonometer first law graph, resonance tube graph plzzzz

[@Foodchnel]

Sir mera first answer 0.07 dusra 0.05 third 0.06 aur fourth 0.04 arha ha tu ye shi ha mtlb ke ans beech mein km zyada hoskta ha jese mera 0.05 ke baad 0.06 agya aur phir 0.04 please btaye??

[@khan_affan]

Readings fluctuate kar rahi hain... Itna variation nahi aana chahiye

[@ritujadhav3626]

It was really helpful thank you

[@laibakamran9269]

Sir ....linear expansion vala nhi h?

[@khan_affan]

Physxone ne bhi videos upload ki hain you can also visit there

[@073.laibakhan7]

Sir mere 5th minute ka 0.03 , 10th minute ka 0.04 aur 15th minute ka 0.02 araha hai.. But mere teacher keh rahay thay k teeno values same ani chahiye.. Sir please explain.

[@khan_affan]

Yup you are right... That variation is due to experimental error... More or less it comes out to be near 0.04, 0.03 with experimental error that is why we are taking average in the end... If there is still any confusion, discuss...

[@073.laibakhan7]

@@khan_affan Sir teeno ka average 0.03 araha hai..theek h? Matlab mere teeno k answers tu theek hain naw?

[@khan_affan]

Itna error is acceptable... Apni values batao jo aap ne college me kiya hai? Teacher ne verify kiya hai usay?

[@073.laibakhan7]

@@khan_affan Sab se pehle walay comment m sari values likhien hain Sir.

[@073.laibakhan7]

5th minute ki 0.04 10th minute ki 0.03 15th minute ki 0.02 20th minute ki 0.02 Aur agar in sab ka average nikalun tu 0.02 araaha h.

[@mariumyousuf4645]

sir you were repeatedly saying, line ko dekhna point ko mat dekhna, which line you were mentioning?

[@khan_affan]

Yup... The curve... Actually when you will be drawing that curve you have to draw a smooth free hand curve due to which you might have to leave some points... Qk if you try to connect those point then you will not be able to draw a smooth curve... Isi liye I said when you are finding cooling constant then you have to connect those projected lines to the curve and not to the points... I hope you got the answer but still if there is anything confusing you can ask again will give you more details in it...

[@_RahulDalvi]

Thanks very helpful

[@mitinamtali3134]

Not visible write and draw it with pen and marker 😓

[@adityapandit1987]

Wa sir Best

[@naziashaikh8420]

very nice sir thnak u

[@zimalshah35]

Lekn mere pass time 25 tk jara hai toh iska graph kese bane ga plz bta den

[@khan_affan]

No problem... Dekho is graph me ek box or hai extra wahan pe usi scale k according 25 min bhi ajayega... Try karo... Then let me know if you find it difficult...

[@zimalshah35]

Khan Muhammad Affan okay sir

[@zimalshah35]

Me apko kaise dekhaun k mera graph sahi nhi banra plz btaen

[@khan_affan]

Send it on FB... Khan Muhammad Affan...

[@zimalshah35]

People or page or kiya likh k search karun

[@memuslimahabdulqadir7762]

value agr 0.04 ya 0.06 aye to answer sahi he?

[@khan_affan]

MeMuslimah Abdul Qadir Yes, acceptable...

[@SanaKhan-gq2nb]

Sir aap nay 5 or 10 minute k bd ho temperature nkala ha wo smjh nh aa rha..

[@khan_affan]

Matlab usmay kiya samajh nahi araha? Kindly explain... Taakay me clear karoun

[@SanaKhan-gq2nb]

@@khan_affan sir wo jo ap count kr rhay ha 2 lines bd itna temp ha wo... point lgana smjh nh aa rha... andazay say lay sktay ha kiaa point...

[@khan_affan]

Okay now read carefully... Y-axis pe hum ne temperature liya hai... Upper scale agar dekho to usmay likha hai 10 S.B = 5°C... Iska matlab ye hua k agar main 10 small boxes agay barhoun ga to 5° temperature barhay ga Yani k 10 steps pe 5°, to 1° barhanay k liye kitnay steps chahiye hongay? Yes 2 steps? 2 step = 1° Agar main ek step agay barhoun to kiya hoga? Jee 0.5° barhay ga (yani half) Qk 2 step chala to 1° barha to 1 step chaloun ga to aadha ° barhay ga na? Ab clear hogi kuch picture... Agar main 50° pe houn or ek step small box agay jaon to 50.5°, phir ek or step 51°, phir ek or step 51.5°, phir 52 Phir 52.5° Phir 53° Phir 53.5° Is tarhan y-axis ka scale chal rha hai... Ab final baat now suppose me 50° pe khara houn mujheu 54.5° pe jana hai... To batao kitnay boxes agay barhoun ga? I hope clear hoga lekin still koi confusion ho to puch lo

[@SanaKhan-gq2nb]

@@khan_affan ub 50 say 54.5 tk anay k lye 9 boxes agay brhna hoga.. right...

[@khan_affan]

Behtreen...

[@shehbazkhan2269]

Sir hamare 4 box me 20 nhi araha 3 me araha h

[@khan_affan]

Bilkul ye difference aa sakta hai, aap apni readings k according scale set karein...

[@shehbazkhan2269]

@@khan_affan ok sir

[@rayyazakirhusainkhan7814]

Sir second graph

[@bottomfraggergg]

Try writing with pen or marker...literally cannot see properly

[@khan_affan]

Extremely sorry for inconvenience...

[@yasirjan2597]

ABC

[@haniashah6758]

Anyone for 2023 practicals?

[@khan_affan]

I am, not appearing but conducting lol 😁...

[@rohit36910]

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[@kavitaindulkar2141]

Pls try to make ur videos shorter no one wants to invest so much of their time in one exp otherwise everything is nice

[@khan_affan]

Thank you for your feedback... We will try to shorten these videos in next cycle... :)

[@hridyanshu3460]

sir u r awesome thank u sir

[@pravingiri5828]

Anyone for 2023

[@Deepmala_kadam]

But sir aapki writing dikhai nahi rahi so sorry

[@zoyaahmed9869]

Curve mujh se theek nhi bnra

[@sahiltrimukhe8765]

This Video is not clear very dark place not bright light

[@rameshchandrasinghyadav977]

For 10th minutes calculation is wrong

[@someonelivingsomewhere3777]

thanks

[@Aakarsh350]

25.01 !!!! 51 degrees is wrong

[@khan_affan]

Thank you for correction...

[@Aakarsh350]

ek accha sa graph paper khareed leta yaar !!!! Its too light

[@khan_affan]

Extremely sorry for inconvenience...

[@Aakarsh350]

@@khan_affan Bohot jaldi reply diya aapne 😂😂😂 February mei hua mera pracs and abhi I am enjoying my vacations 😂😂#StayHome!! Anyways thank you !!! By the way mujhe newtons law he aaya tha pracs mei

[@khan_affan]

Sorry once again... Well Stay Blessed and Stay Safe... Thank You...

[@Aakarsh350]

@@khan_affan 😃

[@arshankhan8190]

Graph. Paper. Required. h

[@yasirjan2597]

Featureless

[@ratilalvasave9071]

thank you so much

[@Prajwalkalbande2003]

Thanks sir

[@jayashreebera1152]

Clear q nahi aara

[@khan_affan]

Sorry for inconvenience... Didn't realize this while recording... Try to increase the brightness of device, this might help... And we will consider this factor in further recordings...

[@sanskritaekawade3983]

bakwas vedio