Graphing Sine and Cosine with Transformations

Graph y = Asin(B(x-D))+C and y = Acos(B(x-d))+C
mathispower4u.w...

[@Mathispower4u]

Thank you for commenting. I annotated where I misspoke. I apologize for that.

[@thesmalfvoyager8946]

So is there a difference between phase shift and horizontal shift? I found some web pages that saying there are different standard forms in physics and math. Please advise. Thanks in advance. @Mathispower4u

[@sofzhuk1188]

you just saved my math grade, thank you

[@kir1026]

This helped me so much! Thank you for posting this.

[@YoungFlyAmbitious]

Oh, but I must say this was a great video nonetheless. You were very clear and it definitely resolved some of my issues. Thanks for contributing! :)

[@xBorderSauce]

thank you! :D you just saved me from an F on my pre-calc test. :D thanks a bunch!

[@luisdfernandez2601]

Based on your first definitions, aren't we suppose to shift D to the right if D > 0. Since π/4 is greater than 0, why are we shifting the left???

[@mathrovert]

x + pi/4 = 0 x = - pi/4 (Here D < 0 ; Shift Left by pi/4)

[@sampoulin9198]

Thanks for this! Helped a bunch.

[@YoungFlyAmbitious]

@ 1:38 he says the original sin graph goes from the intervals 0 to pi/ 2. That was an error. It actually goes from 0 to 2pi.

[@manuelyanez2759]

thanks

[@numba1spazzet]

Thank you soo much!! You really helped clear up alot of my question:)

[@akhilgajjala6018]

Thank you for the amazing explanation!

[@Majuuub]

how did you know that -pi/4 plus pi equal 3pi/4?

[@prexci6423]

Why you make me take notes of this Mr. Parra

[@tiffanymorales6392]

Im doing the same thing!!!!

[@yabseraberhe850]

why is that the first point starts at NEGATIVE 1/4 i thought the horizontal shift is a posiive 1/4 (+ 1/4) ????????? i understand why we would shift down 1 unit down but why would we need to go negative horizontally to start our point?????????

[@jamessousa5301]

It is a bit counter intuitive, by think about the function value when x = 0. With the x + pi/4, it takes a -pi/4 to make the input (x) equal to 0.

[@yabseraberhe850]

ohhh okey so anytime the the (D) is positive but the (C) is negative you are shifting horizontally negative as well?

[@willmeyer8602]

this help much me you like for math

[@sainthunny]

Thank you so much!

[@milkbread9044]

i love you