Algorithms: Sort An Array with Comparator

[@LilMomo7777]

This is a great tip, but it comes with a few caveats. If your numbers can be extremely large or small, you can run into integer overflow which can result in a wrong answer. Make sure you ask your interview about the domain of the numbers you'll be comparing before considering this method. This is only a problem if your number data-types allow overflow.

[@tythedev9582]

Can't use the b.score - a.score trick if negative values are included although.

[@dahui58]

So the y value maps to parameter b? Seems to me the x and y are opposite to the ordering of the params of the method

[@RayRay-oi1cc]

Be careful with subtractions if values can be negative. An if else check to see which is lesser, greater or equal will reduce the likelihood of bugs .

[@johnaweiss]

2:06 I understand why the sign alone will tell you which one is bigger, but doesn't the caller need to interpret the sign? Would be helpful if the video showed the use of `compare`. Equally simple, i think, would be `return a.score > b.score` which, instead of positive or negative return, would give a true or false return. I wonder if that might use fewer CPU cycles or less RAM, since you're not doing any calculation.

[@karimzuniverse]

Shouldn't this be a.score - b.score?

[@sauravsamant1023]

i guess she is sorting in descending order, even in which case it should be -1*a.name.compareTo(b.name).

[@BrajeshKumar-np1br]

@@sauravsamant1023 @0.41 the scores appear in descending order but the names do appear in the ascending order so she didn't multiply a.name.compareTo(b.name) by -1.

[@akashpalanisamy5659]

Thanks for this... Was stuck here during Practise and this really helped me

[@Najibway]

what language is this in? C#?

[@nandhannatarajan2127]

Java

[@johnaweiss]

What sort of syntax is `Player a`?

[@vamsikrishna-vz7yy]

Player is a user defined data type

[@avideosomeday3913]

I think this is comparing not sorting? Thanks anyway

[@Andrezito917]

Is there to do this in python?

[@toniok.4726]

you can do these thing in any lang just a little bit diff

[@jaapdebouw7410]

dankeschon

[@deli5777]

my teacher is making me do this with a non alphabetical order 😵 the internet hasn't been helpful

[@CreativeFunction]

Comparator.comparing(Player::getScore).reversed().thenComparing(Player::getName) is how I would write this in java 8. You might need to split that out into a variable for the comparator due to .reversed() returning a comparator of T and not player.

[@jackbenimble99999]

Java 8 is like whole new language to me. Can you break this down?

[@ko-Daegu]

Jack B. Nimble Not exactly first you need to study lambda expressions after check this one out this is not lambda expression though but it’s helpful first to know that ... Also check streams ... Also check new stuff in collection interface .... This is like big stuff in java 8 Also check try with resources You can look it up in youtube like this Try-resources