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[@manojchaugule794]

its very nice to watch this problem

[@NithyaGhumare]

❤❤❤❤

[@LaxmanKumar-yi4cv]

Simplification is correctly done

[@aruntiwari5714]

Nice explanation

[@harikishan1900]

Very well explained

[@satyadev3848]

nice question here

[@KeshavKulkarni-x1w]

All steps are correct

[@harshpathak2359]

It's genuine one b trusted on solution

[@allislandbestcombinedmathe6149]

Superb

[@RealQinnMalloryu4]

❤(x^4)^2 ➖ (72)^2 ➖ 17 {x^16 ➖51 82} ➖ 17=5166 ➖( 17)^2={5166 ➖ 289}= 4877 6^8000^77 6^877^1 6^8^1^1 3^2^2^3 3^1^1^1^2 32(x ➖ 3x+2).

[@arvindkulkarni6580]

All the steps are explained in very detailed manner, thanks

[@barryzeeberg3672]

4:08 not sure why b^2 - 4 a c is set to 0? That will simplify the quadratic formula, but not sure why we can assume this is true?

[@sameerchughani5463]

b²-4ac is set to zero because, The value 2x²n+72x+17+n² is obtained from the square of (x²+n). Since the value arises from the square of an expression the roots will be real and equal. I can't figure out a better way to explain you, hope this is useful

[@Maheshkumar-cw6un]

Good teaching method