Heat Transfer: Conduction Heat Diffusion Equation (3 of 26)

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[@sato43]

Whch book is he referring to

[@maxlav742]

TEXT: Introduction to Heat Transfer, By Bergman and Lavine, 6th Edition

[@jackytan819]

Do you have link to download this ebook?

[@bhradramazani]

@@jackytan819 libgen

[@aarifhussain3700]

@@bhradramazani not available over there

[@leonardogaloso1592]

This man is incredible. He helped me ace fluids and now I find he does heat transfer. Rarely do I find myself EXCITED to watch lectures, but when I am, it's when I watch Professor Biddle

[@brocklydoodle]

So happy I found this series! I'm in heat transfer right now and my professor is the nicest guy ever but not the best educator.

[@cylex96]

Love the lectures! camera operator is asleep most of the time though

[@ftmichael1]

Your focus on clearly defining q, q', q", and q dot is so helpful. I had so much confusion from my book calling your q Q, both your q' AND your q dot just "Qdot", and finally your q" qdot. It felt conpletely unintuitive, and made their equations confusing without units. Seeing your scripts and explanation of q" cleared so much up for me conceptually.

[@zayde199]

I love your handwriting!

[@CPPMechEngTutorials]

Years of practice.

[@GuanglinDu]

Dear prof. John, thanks for your fabulous videos which are of great help. Why time t is not a variable in the temperature function T = T(x, y, z)? If not, the general heat diffusion equation (2.19) would be problematic since the right term, the partial derivative of T with respect to t, must ALWAYS be 0. I think it should be T = T(x, y, z, t). However, you DID put time into consideration in the 2D case as is T = T(x, y, t). I googled only to find out that there's no detailed and convincing answer to this question.

[@turk2589]

Yes, if the system is not steady state then T is a function of t, too.

[@brianrodriguez7759]

lol, aliens try to contact at 4:21 (have sound on)

[@CPPMechEngTutorials]

About time!

[@manuboker1]

Wonderful Heat Transfer lectures ! ! !

[@muhammadusama6173]

Holy shit, I didn't know dr. Biddle had HMT courses. Yiss.

[@mustafaaykanuzun192]

for question 2.1 if dt/dx become smaller means that it hasa derivative if it has a derivative conduction should not be steady state according to heat conduction theory d^2T/dx^2=dT/dt can you explain

[@turk2589]

Well, steady state and 1-D heat transfer are actually not good assumptions for that case. For these assumptions d^2T/dx^2=dT/dt does not apply because your infinitesimal element should be taken as a slender element with the whole crossectional area.

[@hehek1536]

Somebody plz help! I dont understand 2:41 Do u know why q(x+dx) = q(x)+d[q(x)dx]/dx?

[@kasperborup8683]

It is a Taylor series approximation and since we are looking at an infitesimally small element, the higher order terms from the Taylor series can be neglected.

[@ruthyang5309]

How I wish I am in Dr. Biddle's heat transfer class...

[@maxlav742]

Thank you Sir! It's a huge help

[@CPPMechEngTutorials]

No problem.

[@fahmiakmal9]

anyone has the answer for 2.31 part b to find h?

[@hi.salman305]

There a copy of solution manual for book he used in internet just search about it

[@Yodavid1]

i think something is strange with the solution of the 2.1 problem, specifically the part where you find the T(x) profile. A(x) * dT/dx is a NEGATIVE constant, so dT/dx decreases in absolute value, but actually INCREASES with x, rather than decreases. therefore its derivative d²T/dx² is positive, therefore T(x) is concave UP. when the professor shows the slope of the profile "decreasing", it is actually decreasing in absolute value but actually moving from a large negative value to a small negative value, i.e. INCREASING.

[@turk2589]

there is a minus sign in that equation

[@batuhancoskun9282]

What kind of a cameramen are you bro. Follow the proffesör dont sleep in the class

[@jackstratif9988]

I actually like that he doesn’t follow his every movement since it allows me time to take a screenshot.

[@raveenapatil1208]

Why is the q coming out of the differential element greater than the q that enters it? Where is that additional heat coming from?

[@CPPMechEngTutorials]

It can be internally generated in the fluid element (maybe chemistry is occurring) or maybe heat entering from multiple directions (say, the left and bottom) flows out through another direction (say, the right).

[@raveenapatil1208]

@@CPPMechEngTutorials Thank you for your response :)

[@runtime_engineer]

Why isn't the E(dot)'' gen included at 52:56 ?

[@WonCast]

he just didnt write it down because its 0

[@erfanacct003]

47:38 , I checked with the book. It does not match with the 2.31 !

[@kc137]

me too

[@oguzbenzet858]

@@kc137 Mine doesn't match too. Ours are probably different editions.

[@PICHITAS666]

Why is one dz in the area?

[@shreyanghosh6663]

JEISSON RODRIGUEZ actually it is a 2D problem that's why where ever u take Z it will get canceled in everywhere that's why its taken as 1 ...cos 2D problem only ..XAnd Y are considerable

[@ChaineTa3lim]

supposed 1

[@aarifhussain3700]

I am still confused by the answers if we are in 2D then why we are considering the dz to be 1,we are in the xy plane only

[@hz-vb6hn]

thank you so much you really help a lot man I wish I got to study in this unversity

[@leonardolopez6843]

ptm lo ocupaba en español

[@asutoshpanda794]

can you plz give the homework questions

[@mro2038]

Book: drive.google.com/file/d/1m77fN_lsk9tvJmVr1RcloH7-thuaTzlj/view?usp=sharing

[@muhammadabubaker3832]

love from Pakistan , Sir

[@nipungupta8846]

pkmkb

[@gggg3914]

محدش هنا بيتكلم عربي يقولي هي ماده ايه ولسنه كام

[@AH-so1op]

ديه heat transfer سنه تالته او رابعه هندسه ميكانيكا

[@hosseiniskr1306]

oh these are waste