HILL CIPHER 3X3 Matrix Example Encryption and decryption

[@tabindakhan3913]

in the key matrice g= 6 but sometimes u have written 16 and some times 6 in the key matrice

[@AbhishekSharmaDit]

Wo 6 hi hoga by mistake 16 likhdia hoga ✌️

[@riyaalok2424]

6 sae answer nahi aa raha bhai

[@Viralvlogvideos]

its is 6 but u wrote 16 and then u againe changed it

[@AbdulRafay-vi6hz]

because sometimes the value is 16 that means you decryption could be wrong but the method is correct...so Thank you

[@abhinavs03]

Saale G is 6

[@shrayansjain9176]

This was very helpful especially the whole process to find inverse(k). Thanks a lot

[@jananiebalaji3698]

Thank you sir. Kal mera exam hai. bacha liya aapke video ne mujhe. :)

[@mayurighosh7487]

You really put some hard work , other channels just leave the calculation and write answers directly

[@shilpahr45]

ur expressing method is nice and we can get things easily thank you sir do have notes soft copy

[@sriramff7047]

😘😘😘

[@gauravsharma5584]

Tip : skip this question.

[@zohaibshakeel6045]

Thanks brother lots of love from Pakistan 🇵🇰

[@arunkc9147]

What if determinant of key matrix is - ve? Should we add 26 ro make it +ve too?

[@s.nageshwari6896]

Tq so much bro,you make it , easy to understand

[@saroshahmed7097]

Thank you brother love from Pakistan ❤

[@harshitabinwal4226]

Nice explanation 🥰🥰

[@simpykumari7025]

Very precise and useful... Thank you

[@anitathakur4303]

Loved your video😍🥳

[@manikantaananthoja]

In Adj(k) you wrote n=7 in -197+26(n) .... But n=8 just correct that one...that's all bhai

[@shristiuniyal6792]

hey abhishek can you tell me what to do if the determinent is negative?

[@enzo9299]

determinant can never be negative, because we always take mod of the value, which is eventually positive.

[@chinni438]

Very very nice explanation superb

[@lakshsinghania]

abhishek sir what if the plain text is SAFEMESSAGE or SAFEMESSAG instead of SAFEMESSAGES ? it doesnt make exact 3x1 matrices then what to do ?

[@jarvis9263]

very useful in life

[@achalrajyaguru7644]

What if our PT is of size l and key is of size m. how to do lxm?. Also what if our PT doesn't have enough characters to form a matrix?

[@Rahul-s3p5n]

hey what to do if there's whitespace between plaintext for e.g. i am ciphertext , so when encrypting do i need to ignore the whitespace?

[@Night_Rider5242]

(ATM) I think there is a miss calculation. 196+26(7) When 26*7=182 and remainder is -15 If I do 26*8=204 and remainder is 7. Sir Please clearify

[@puneetyadav65]

26*8=208 There is a miss calculation

[@jisanahmed4780]

is the determinant right? my ans is 763

[@WHATMAKESMONEY369]

16:00 the whole matrix & k inverse is wrong….appreciate your method sir bit don’t miss guide us wrong calculations. Students please correct the matrix.

[@ankursingh-mo2ok]

what happens if the mod exceeds 25 what am i supposed to do , reverse count from 'A' taking it as 26?

[@suhast.s9498]

hello, sir loved your explaination have some doubts if you dont mind clarifying

[@muhammadbahrozshamim2099]

Is repeating letter allowed e.g if my plain text is "HEll". When i will divide it for 2x2 key matrix, will the repeating letter will be allowed?

[@UtkarshNayan-cf1zp]

Hello boss , The value of determinant comes out to be 763

[@abdulrashid4734]

Sir g agr inverse ma determinent ki value minus ma ajaye PIR kya krengy

[@sultanalikhan7286]

sir uper key me ap ne N=13 LIKHA HE OR NECHE MARTIX ME WO 3 KESE HU GYA CAN U EXPLIAN IT PLZ?

[@renukachowdary709]

Can u say any easy process to find the multiple for getting 1243*5 mod 26=1

[@abhishekgautamoberoi9678]

Yeah please tell it's very complex process

[@abhishekgautamoberoi9678]

please suggest it

[@WHATMAKESMONEY369]

@ 12:44 the product is -157 not -197 pls correct it sir

[@suriyajan3597]

Thankyou sir!

[@rohannagshiva5971]

thanks a lot sir

[@akhilpanwar6974]

what if agar hamara plain text "SAFEMESSAGE" hota to, vacant space mai kya dalte?

[@sohomchowdhury192]

Add x if plain text is of odd number of characters

[@Viralvlogvideos]

14:49 error yeh bro for 2nd Element it is 7*16 not 7*6 u wrote wrong so correct answer is 7*16-8*17= - 24 --> - ( - 24) = + 24

[@hiteshmanjunath5511]

Bro..if we get 0 as determinant in decryption process??

[@Computer_Info]

nice tutorial i like it. i have a question which is 'when u use 3x3 matrix , if u have left one letter and how to encrypt it ? for example the plain text is UNSAFEMESSAGE and the key is z same u use one tutorial.'

[@sohomchowdhury192]

add x

[@beone888]

at 12:38 how 4*16 - 13*17 = -197(it should be -157) there are more calculation mistake in your video

[@faizamanzoor4279]

in reversing( -ve) the value of n = 8

[@allinone_747]

Sir is repeated letters allowed in plain text?

[@anupamagautam1395]

amazing

[@dikshikayeul847]

Sir, can you share your notes that you have made, it will be very helpful.

[@dharma_reddy]

How to find inverse if we get the determinant of the key matrix an even number. I think we cant do the same process if we get determinant an even number where we cannot find inverse using this method. Can you do the same problem using key matrix[1 7;9 3].

[@nilankshadogra6447]

Sir mod 26 kyu kiya ???..

[@2290prime]

In some places you've taken the value 6, in some places you've taken value 16.

[@malharlele195]

well there are mistakes in the key and the multiplications as well due to key being wrong and the modulus somewhere

[@safmaqboolbasha]

minor error in key matrix g is 6 somewhere its written 16 by mistake. also when removing minus signs n is not 7 it is 8 -197+26(8) = 11

[@sheenamaraggun]

how to get d^-1 = 5

[@ShivamCE-yw2uq]

Sir, what if the number of characters are in odd number then how can we define the last vector

[@sohomchowdhury192]

Just add x

[@smdshoaibali5200]

Encryption may aap 13 ki jagah 3 likhaa hai plzz see once and tell me how u wrote that 🙏🙏

[@trishulnaik4234]

Can anyone help What if plain text length is 5,7,etc -> say "Hello pi". What will the key matrix (nXn) be? should we fill p matrix or will it be (7X1)

[@UshaswiniCHERUKULA]

In encryption 2st matix last 8,13,6

[@pavanpreetham7138]

Can you tell me the solution for this . plain text: key secret text :cryptography Encrypt by hill cipher

[@priyanshudarji1923]

Bro for encryption for 1st SAF plzz check the C cause instead of 13 you have written 3, so I guess the answer will change

[@priyanshudarji1923]

Sry it won't be changing cause multiplication will be 0 , I am sorry

[@mamaandi1155]

d-1 d inverse ki value 5 kesy aye hai please help

[@Sam-oo4py]

Adjoint of k is wrong. Check ur numbers. The first element substracted result is wrong. The second element, u said something and u multiplied something else.

[@AbhishekSharmaDit]

It will be 6 everywhere I have written 16 sometimes I have pinned the comment also✌️

[@yadavji_official5548]

Or agr determinants negative aa jaye to kya krenge

[@humanAbsu]

Bro plzz apni calculation shi se kara kro🤯

[@vishnusaitejanagabandi9009]

I am confused wheather i was doing wrong 😑

[@arslanakram7319]

Thanks Boy

[@ouroobatariq4093]

😂

[@prakharkant8225]

Ambiguity in determinant of key confusing............

[@kraghupati]

Too many mistakes in the calculations. Please correct.

[@pankajdhokti9193]

Calculations??

[@ashutoshshukla8186]

Adjoint Matrix calculated is wrong

[@parasjain410]

What if the value of determinant comes out to be negative?

[@suchitathakur5913]

It is always a positive value. If you are getting -3 then convert it into 3 out of the determinant.

[@chinni438]

Can u make vedios on data mining techniques

[@AbhishekSharmaDit]

Will do that in future

[@Bana-hukum-jaisalmer]

Nothing wrong with the calculation, everything is correct, just single mistake and all needs justification

[@mdazam2315]

Pls sir provide the notes...

[@kshetrasrinamburi7986]

Determinent is 1043 check again

[@PujaKumari-yt8sq]

1253

[@kshetrasrinamburi7986]

@@PujaKumari-yt8sq How

[@AceHardy]

✔️

[@rashmisinha7228]

What to do if.. Plain text is not i. The multiple of 3 for above 3X3 key mateix

[@siddharthsoni8784]

n =8

[@mhamza5732]

aby pechy police lgi hai tery?? jo tez tez ja ra ha

[@manngala4425]

sahi hai baki ke toh try kiya hua bhi nhi best ho aap

[@HiMu2324]

Encryption m 13 ki jagah 3 likh diya h...

[@smdshoaibali5200]

Haa yaar merko bhi same doubt hai 😭🙄

[@sohomchowdhury192]

Its a mistake, galti se likh diya hai

[@joewhite7466]

was that supposed to be english?

[@akshay.ppvvtt]

calculator exist

[@mohsinkhan973]

wrong calculations sy shi answer waah bhai waah

[@Sumit_yadav748]

Bro you've done a mistake in key Matrix, you've took 3 instead of 13 for "N", Edit:it doesn't make difference anyway

[@vipulshrma8]

hmm

[@vinayhans2829]

oh bhai es ko solve karne ke liys kaafi time chahiye

[@AbhishekSharmaDit]

Practice se ho jayega ✌️

[@jaideeplobo6096]

This is difficult

[@abdulrashid4734]

Zaror reply dena sir g

[@IgMINATO]

MITS

[@rohithnshetty9574]

Bhai mod karneka method bata dete tho achha hotaa .... Sirf reminder boldiya apne 111% 26 = 15.7 ata he

[@dhanmanichoudhury2759]

determinant is 763 not 1243, yeh meine calculator mein check kia

[@sohomchowdhury192]

No, determinent value is 1243.

[@sohomchowdhury192]

Take the proper values of the key matrix then u will get 1243 as value.

[@فاطمةراضيجبر]

منو عراقي

[@aashutoshpatel8854]

Bhai tu kar kya raha he

[@nabeelnawaz218]

bht mistakes hain ,,not recommended

[@UshaswiniCHERUKULA]

You did mistake

[@KaizokuDOFFY]

encryption is easy but decryption is too complex. if i could get live assissttance.