Horizontal and Vertical Asymptote of Rational Function | General Mathematics

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hi sir, thankyou po ng sobra sa tutorial n'yo. ang bilis sundan at maintindihan, grabe ang lito ko sa module kung pa'no, kakatamad sundan aa. pero ang sarap niyo po magturo, nakakagana. Godbless, sir. 😩😩❤️❤️❤️

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Wow...thank you po...😊😊❤️

[@superidoldexiaorongdoumein9725]

f(x)=2/2x+3 V.A. 2x/2=-3/2 x=-3/2 Thus, the vertical asymptote is x=-3/2 H.A. n=0 m=1 n

[@emmanph8565]

Mali

[@aokifuji1134]

hi sir, exam namin sa monday and stress na talaga ako kanina dahil wala akong alam sa math topic namin, i'm so lucky na nahanap ko tong channel mo, ambilis ko nagets and medyo nawala yung takot ko for my exam in gen math, nawiwili na ako sa math kanina pa ko nanonood ng mga vids mo na abt sa topic namin hehe, tysm!!

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Whooa... Good luck and God bless sa exam... keep it up

[@johnservidad9663]

3.Given F(x) = 2/2x+3 V.A Equate 2x+1=0 2x=-1 Devide both by 2 ÷ 2x=-1 2 2 x=-1/2 Our V.A is -1/2 H.A n=0 m=1 n < m H.A is y=0

[@johnservidad9663]

Hi sir im grade 11 this year po tama po ba yung sagot ko? Kung tama man po pacorrect po ng answer ko para makita din po ng mga grade 11 students ngayon

[@chelceecapinpin2921]

Bakit naging 1?

[@windadingal3013]

Big help..galing tlga ni sir mag explain..

[@MathTeacherGon]

Whoaa..salamat...😊😊

[@JoseRaymondDamianSalvador]

f(x)=2/2x+3 V.A. 2x+3 = 0 2x/2 =-3/2 x=-3/2 Thus, the vertical asymptote is x=-3/2 H.A. n=0 m=1 n

[@camreston5997]

sir napaka galing niyo mag turo kahit naka mute po naiintindihan ko po thankyou sir

[@MathTeacherGon]

Welcome po

[@jovenerafa5395]

may exam narin kami nextweek buti nlg nahanap ko channel mo sir salamt po

[@joshuaalbello3548]

Salamat sir na gets ko agad huhu dugo na utak ko kakabasa HAHAHAH hirap po kase sa self study

[@Laxman_dahiya55]

I am from India ❤

[@johncristo337]

Thank you sir

[@MathTeacherGon]

Welcome... Keep on learning Math...😊 Marami kaming mga youtubers ang tutulong sa inyo..

[@marycilortegavlogs2.076]

VERY GOOD EXPLANATION

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thank you so much sir

[@MathTeacherGon]

Welcome po...

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thank you po sir pina dali nyo buhay ko ^_^

[@MathTeacherGon]

Whoaa. Keep it up!

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Sir thank you! 🙏🏼

[@MathTeacherGon]

Welcome po mam...

[@MathTeacherGon]

Welcome po mam

[@_faithdeleonaquino8158]

Thank you sir.

[@michaelguiron5197]

Nice sir

[@MathTeacherGon]

Thank you.

[@GooEnoki-dg8uh]

V.A. x=-3/2 H.A. no asymptote (numerator do not have a degree)

[@ronaldelcarte5907]

My Answer V.A #3.x=-2,-3 H.A#3.y=3 Ok batung answer ko sir?

[@jovenerafa5395]

mas naiintindihan ko pagturo nyo sir mabagal lang e, sa sir namin ang bilis magturo, thankyouuuu sir gon na nasa hunter x hunter HAHAHAHA jk lgpo, ty poo

[@SaripWari-xq2lm]

hi sir pano po mag report ng vertical and horizontal asymptotes

[@HanahRepompo]

PAANO PO ISOLVE TONG Find the vertical asymptote of the graph of each rational function. Gx=x²-9 over x²+4x-21 Need ko na po iexplain kopo sa lunes ihhh diko po masagot kasi di pa nadiscuss ang teacher namin 😭😢

[@SabSarrah]

Vertical asymptote: X= -3 X= 7

[@lambswkswkswk1007]

what if hindi po ma factor ang trinomial?

[@marycilortegavlogs2.076]

my answer is VA ( 2,-3) Y=0 LET ME HERE YOUR COMMENT

[@ErlindaAboy-he2ok]

V.A x=1 H.A y=1 Tama po ba to?

[@jaspherquinto7003]

Sir pano po Kung Hindi perfect square of binomial?

[@artbrylie7134]

Magiging dalawa po yata ang H.A non

[@artbrylie7134]

V.A X=1.5 H.H Y=0

[@jithrenejoycepamaybayluzon324]

Good morning po sir paano po Kong x+2 over 2x+3 sir

[@lutchienedera]

Hi sir😊

[@MathTeacherGon]

Hello po...😊

[@ladyrider36]

1

[@artbrylie7134]

Wala po ba ser para sa obliuqe/slant asymptotes?

[@johnella9329]

3.) f(x) = 2/ 2x+3 V.A. 2x+3=0 Transpose 3 2x=(-3) Divide both sides by 2 2x/2 = (-3)/ 2 Cancel x= -3/2 Therefore, the vertical asymptote is x= -3/2. H.A. f(x)=2/2x+3 n=0, m=1 n

[@xyrajin4660]

D kopo na gets kong saan po nakuha yung (X-3)(X-3) (sorry po masyadong slow si brain)

[@samuelclavite5820]

factoring

[@giftokereke3145]

y=0 h.a

[@synxestrella7393]

Thank you sir

[@MathTeacherGon]

Welcome po

[@cristiesacki5324]

Thank you sir