Houston we have a problem. the diode blob works in one direction. ???

[@afurryferret]

post high res images of your circuit so passers-by can do some debugging as a fun little community activity!

[@DennisMurphey]

That's a great idea! I will but in this case I rebuild the circuit on a breadboard with fresh diodes and it worked perfectly. ??

[@DennisMurphey]

Thank You so much for the feedback and offer of ideas. I know this works I build one before, I must have a bad circuit. I built a second set up on a breadboard and it does work. One think I don't like is the power loss using these diodes. If any has a idea for lower loss parts that would be great. I have faith in the systems. I know they all work. My ability to reproduce reliably is not so good. That is why I need someone to take this group of parts over and hopefully convert to SMD for lower cost, less space and better reliability. I appreciate the comment immensely, Thank You all for watching and subscribing. When i get to 1,000 I plan to release all ny .STLs to the public. Dennis

[@-private8214]

the 1 volt is close to the backwards leakage voltage of a diode, my assumption is that one of your diodes is either broken or not correctly soldered in, you propably reversed one, the 1v is the voltage coming through a diode backwards

[@DennisMurphey]

I know i thought that too, but, I inspected the parts very closely they were installed in order I think it's the type of board and the quality of the jumpers caused a drop. My breadboard worked perfectly. I would like to find a lower loss component. D

[@freakyjason477]

​@@DennisMurphey One of your diodes has failed (mostly) open and the 1-2v you're seeing is however much your powersupply is able to push into it despite the short-circuit. if 'forward' means positive on white, negative on black then either one of your top or bottom diodes has failed. otherwise it's one of the middle two. even though it's a new package, diodes can fail like this if you apply a too high reverse voltage to them. inductive loads that get switched off/disconnected can do this (such as a dc-motor or switching relay getting shut off). think about how if you connect an electromagnet to a battery and then disconnect the wires at the battery, you'll see a spark. if that spark happens inside your diode, it's dead. also, rectifying a circuit using diodes will always cause roughly about ~1.4 volts drop (~0.7 per diode it passes). if voltage drop is really an issue, then you could use schottky diodes which have a voltage drop of 0.4 volts per diode. (there are 'active rectifier' circuits using mosfets and what not, but those are much more costly and complicated.)

[@DennisMurphey]

I heard about Schottky but no clue what it is used for and how. Just not in my kit. I will check them out I like the idea of low volt drop. Thanks For Helping, Dennis

[@kingcosworth2643]

1.2 volts is the drop of two diodes in series

[@DennisMurphey]

If you have a better component, Rectifier chips? Do they drop the same or more , I hate to lose power from the Magna Rossa Motors.

[@foogod4237]

@@DennisMurphey Schottky diodes are often used when low voltage drop is required. They typically have a voltage drop between 0.15 and 0.45 volts (as compared to a typical silicon diode which is usually 0.6V or more). They are generally more expensive and can have some higher reverse leakage, though (but in this kind of circuit, that's probably not a big deal). If you want to get really fancy, you could make use of what are known as "ideal diodes", which are basically active switching circuits with very low voltage drop, but they involve a lot more circuitry, and generally require their own power supply lines (to power the switching circuitry), etc, so I suspect they may be overkill for this sort of application.