I get the basics of black body radiation and the Plank curve. But how does an IR thermometer see a wall that's 20 meters away when the air is the same temperature?
@yongtuition3 ай бұрын
Good question. As you noticed that an object is immersed in air, the diplayed temperature on an IR thermometer is close to the interface temperature where air has almost the same temperature as the object surface.
@tony3785 Жыл бұрын
I've also read that amore plausible source of the increase in Earth's Temperature is the excess UVB radiation penetrating the Stratosphere due to a depleted O3 . Using Planks law E=hf, The IR radiation at 15 microns has only an E= 0.04 ev/photon while UVB at 300 nanometers has an E=4 ev/photon. That 50 times more energy than the IR from CO2 ! Also read that the Effusive volcanos emit tons of Halogens (Chlorine, bromine etc ) into the atmosphere. (1 atom Chlorine destroys 100,000 molecules of O3) I'd love to hear your comments on that also..
@qwas79013 жыл бұрын
Great video
@brendawilliams80623 жыл бұрын
Very nice. Thankyou
@helgecatoaamodt50 Жыл бұрын
Ver clear presentation- By the way what is emissivity of CO2 ? molecyle ?
@yongtuition Жыл бұрын
Good question. In gas form, someone had used 0.2-0.3, but other argued to be 0.8, for the emissivity of CO2. In general, emissivity is defined a relative ratio to that of a blackbody. In my opinion, the emissvity should be proportional to the gas density.
@sagesage6952 жыл бұрын
Thank you so much sir ,but I have a question what's the role of black body in the detection of temperature by the infrared thermometer?
@yongtuition2 жыл бұрын
It acts as a standard or reference, namely it has the maximum emissivity.
@ramsaha79402 жыл бұрын
Blue light has a higher frequency & carries more energy than red light, however, IR image Red color portion more heater than blue color why? please reply, thank you
@yongtuition2 жыл бұрын
IR ray is invisible. The colors, known as "false colors", in an IR image are merely used to visualize the image. In other words, you can use any color to represent the IR intensity detected.
@trivikramaraju2 жыл бұрын
good sir
@Fr3shBoiKim2 жыл бұрын
Say for instance you measure something at 1.0 emissivity, and got a temperature reading of 250 degree F. But later you found out the actual emissivity of the object was 0.75. How do you re-calculate the temperature only knowing the information from the first reading?
@yongtuition2 жыл бұрын
1.0*sigma* (T_1)^4 = 0.75*sigma*(T_true)^4 where T_1 is (250°F − 32) × 5/9 + 273.15 = 394.261K, sigma is the StefanBoltzmann constant.
@ramsaha79402 жыл бұрын
@@yongtuition Finally, we get T actual=423.66 K=309.19F right?, thank you
@yongtuition2 жыл бұрын
@@ramsaha7940 I think so, but you can doubly chech the result.
@pyepaing53603 жыл бұрын
Thank you very much
@mahsaamini8555 Жыл бұрын
Just great great great
@yongtuition Жыл бұрын
Thank you. I am glad you can understand the principle now.
@mustafanashwan59322 жыл бұрын
Hello, is Stephen Boltzmann and Wien's law of displacement used in this device on humans?
@yongtuition2 жыл бұрын
Only the Stefan-Boltzmann law is used as the total radiation intensity is detected.
@mustafanashwan59322 жыл бұрын
@@yongtuition Well because I read in several sources that the temperature is measured by calculating the wavelength of infrared rays and substituting it with Wiens' law to extract the temperature through the law temperature×wave length=0.0029 is that true?
@yongtuition2 жыл бұрын
@@mustafanashwan5932 To apply the Wein's displacement law, you need to use a spectrometer, or FTI.R, which is too expensive >$800,000. The product I used is less than $100.,
@maxmustermann53533 жыл бұрын
Nice video, but how does the sensor determines the temperature? If it would by detecting the amount of infrared radiation, it would also decrease with distance. How is it possible to measure the same temperature with different distances?
@yongtuition3 жыл бұрын
By definition, radiation intensity is the detected power per unit area of the radiator. So, it can be done by selecting a larger area while the distance increases. For a large object, such as clouds, the intensity is almost independent of the distance because it can be treated as a plane source rather than a point source.
@maxmustermann53533 жыл бұрын
@@yongtuition Thank you so much! Now I finally got it. In hindsight it's so obvious. You helped me a lot :-) Thanks. I would like to build a low cost, relatively high resolution, thermal camera. I want to use a mirror telescope to measure a small area and scan a large area with it, to generate a large picture. Now I at least understand how the principle behind the measurement works. 👍
@ramsaha7940 Жыл бұрын
Why do we set emissivity 1.0 when we measure Reflected Ambient Temperature (Trefl) with Aluminium foil? Please feedback me, thank you
@yongtuition Жыл бұрын
Ideally, you would choose a measured emissivity for a IR source instead of 1.0.
@ramsaha7940 Жыл бұрын
@@yongtuition Thank you so much, have a great holiday
@bekind72112 жыл бұрын
Does this thermometer works on zeroth law
@yongtuition2 жыл бұрын
No. it merely detects the radiation intensity of an object.