How to calculate CT sizing & CT burden

How to select proper CT for electrical power system and how to calculate CT primary current rating and CT accuracy and what is CT burden and how to calculate CT burden also explained in this video
#CTsizing
#CTratio
#CTburden
How CT and PT are working
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[@revathis4513]

perfect explaination. now i undestand very well about ct sizing

[@electricalmastar]

Thanks for your comments and keep support our channel

[@sohailjanjua123]

Hi , I like your video. Thanks

[@concept_and_entertainment]

Superb video

[@pietervdberg7055]

Thanks for the explanation. Should you not include the resistance of the CT (Rct) when calculating resistance of circuit to determine CT burden.

[@davidhamilton2708]

I have a question the ratio that are normally given on single line diagram for a current transformer, is that information normally given or do I as an electrician need to be able to derive that information for myself??

[@ashokar9135]

Hi kindly clarify my doubt as below You have taken 1 A secondary, incase if it is 5 A Secondary. CT; would the burden be 1.0741 x 5^2 = 26.85 VA and accordingly should we select the CT(5 A secondary CT) with 30VA burden for the same application. i would be pleased to see your reply.

[@rakeshshah7395]

How to calculate for mcc of 400a sfu(installed). But load is 200a to 250a.load distributed from mcc at different location.

[@mallikarjunkambalyal670]

For education purpose, the explanation is good. However at all times, the efficiency of motors should always be considered, when calculating the full load Current, The working efficiency of the Motor has to be considered for correctness. 150HP is shaft power output and not Power drawn on full load.

[@vickyart2364]

Small tavut erugu

[@kanthsasi2015]

I think resistance is wrong value sir

[@jixingao398]

the resistance should be 7.41 ohm/kM, so the final calculation should be (2*50*7.41/1000+2*0.5)*1^2=1.741VA

[@vickyart2364]

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[@electricalmastar]

Thanks for your comments brother if you have any dought you can send me through email i will try to solve it [e-mail] Thank you