HOW TO CALCULATE SPEAKER IMPEDANCE

[@klaymoon1]

Great video. When bi-amping, would speaker impedance change? I suppose depending on the speakers, but those where the crossovers are separated, I suppose the effective impedance can be as much as halved? Say a hard to drive 2.8 ohm speaker can be more easily driven by bi-amping?

[@dorian_anna]

I couldn't make it through this video because the background music was too loud. Its such a good and demanding piece of music my brain tunes into it rather than the voice and explanation. I mean demanding in the good way, but this is also not so great because I couldn't make it past 1 minute in the video.

[@XsTwentyOne]

you teach me so much, thank you

[@delerium360]

Wait, what? Where's the inductance of the speaker load?

[@billytucker6759]

Ok........but im interested in the specs of wire size and length to make my own coil. Thanks anyway.

[@chrisgrabowski2678]

I understand the formulas!! ty

[@ShrubPlays]

Great lesson, Brandon! Keep up the great work. :)

[@shredbox8491]

Thanks Shrub! Will do :)

[@MrMongo321]

good job Brandon. However, I only use combo amps now.

[@shredbox8491]

Thanks Den :) This can definitely apply to some combos too. The Fender Hot Rod Deville comes in a 2x12 and a 4x10, twin reverbs have two speakers, and there are tons of other examples. I could see somebody wanting to try out new speakers at some point. And at a bare minimum if you are going to change a speaker in a 1x12, you know to look for an impedance switch on your amp or the same impedance replacement speaker. Thanks for always watching and commenting!

[@MrMongo321]

Good point Brandon. Thanks for the vid!

[@nenadmilic4397]

How do you calculate different impendances in parallel

[@shredbox8491]

+Ned O'Millick Take the inverse of the sum of 1/Z1 + 1/Z2+1/Z3... If you only have two impedances you can use (Z1*Z2)/(Z1+Z2). Let's say you have a 4x12 with all speakers at 8 ohm Z wired in series parallel. Each side is in series (left/right) 8+8=16 ohms. The two sides are in parallel. 8*8/16= 4 ohm total impedance

[@nenadmilic4397]

dont get it..its english and to much exclamation marks :). for example i have two 4 ohm speakers and one 8 ohm in parallel. how do i calculate them.

[@shredbox8491]

Ned O'Millick Your impedance is ((1/4)+(1/4)+(1/8))^-1= 1.6ohm

[@nenadmilic4397]

Got it......and if you have only one 4 ohm and one 8ohm in parallel

[@shredbox8491]

Ned O'Millick you can handle that one two different ways. The first is the same as before ((1/4)+(1/8))^-1=2.66. Because you only have two speakers you could use the other equation also. (4*8)/(4+8)=2.66

[@Roadsurfer2k11]

Wut!!! 6:30 🤣🤣

[@banksybanksy9011]

4 spk 3ohm serious +1 hf 8 ohm = ohm????? (4 spk 3ohm serious + 1 hf 8 ohm)+(4spk 3ohm serious +1hf 8ohm)= ohm ?????

[@-Ace-of-Spades-]

Ironic to share audio knowledge whilst not having the first clue about handling audio levels within video editing !

[@PepeDramaStories]

The superloud music on the background is annoying. Also he struggles calculating impedance in parallel.

[@cemkarakarcayildiz5462]

my god we cannot even listen and focus what you are talking abouth cause of the music. did you think too much for chose this kind of music? bad really bad one...

[@carljung9230]

it's not clear if he is talking about individual drivers ("speakers") or individual 'boxes'.