How to CRACK This Radical Math Problem?

[@RashmiRay-c1y]

E=[101√6 + 241]^1/5. Let x^5= 241 + 101√6 and y^5 = 241- 101√6. Then E =x and (xy)^5=(-5)^5. So, x^5+y^5 = 482 and xy = -5. Łęt x+y=t. This means that t^5+25t^3+125t-482=0. So, t=x+y=2 and xy = -5. Thus, x=E=√6 + 1.

[@潘博宇-k4l]

E=(6)^(1/2)+1

[@Fjfurufjdfjd]

1+(6)^(1/2)

[@Quest3669]

? = √6+(1)

[@RealQinnMalloryu4]

x^5 10^60^6/6+10^20^20^21 x^5 3^3^3^3/3^3+1^1^1 x^2^3 1^1^1^1/1^1 x^2^3 (x ➖ 3x+2).