How to do Gravimetric Analysis in Chemistry (with calculations and examples!)

[@asuasonia8085]

You just helped me out right now. Been really confused about gravimetric technique. Plus I really enjoyed watching you talk and wait😅. Thanks a million

[@MariiaEmelianova-s9n]

The best explanation I have ever seen

[@andrewjustin256]

I couldn't agree more! His video is the only video I found on KZbin; there are no other creators creating this lesson.

[@AmnaIsmail-fo8rn]

You explained the calculations very well... Thank you ❤

[@ur_adit]

how the heck are you so underrated

[@SandaraPaera]

I learned a lot. You explained it in a very detailed manner. Thank you so much. This video is a gold.

[@DerekIzzi]

I learned more from this video than I did in my high school chemistry class. Partly me and partly poor presentation methods.

[@andrewjustin256]

7:07 Señor, yo tengo una pregunta. By adding water, it does compute to the memory that we are not changing the number of moles of KI, but aren't we changing the volume and thus molarity because molarity is moles divided by volume?

[@OrdenJust]

This is a really good explanation! What I am wondering about are some tables that I find in the CRC Handbook of Chemistry and Physics, 54th ed., (1973-1974) , that have the title "Gravimetric Factors and Their Logarithms." How do I make a correspondence between this table and what you just did? For example, the CRC table shows Weighed: Al (aluminum, of course) Sought: Al2O3 (aluminum oxide) Factor: 1.88946 Log of Factor +10: 10.27634 Reciprocal of Factor: 0.52925 Log of Reciprocal of Factor +10: 9.72366 Now, some calculation shows that the "Factor" is the ratio of the molecular weight of Al2O3 to the molecular weight of Al2. So that matches nicely with your explanation in the video. What I am wondering about is, why does this table go on to include "log of factor", "reciprocal of factor" and "log of reciprocal of factor"? These seem as if they are not needed for the sort of gravimetric analysis you demonstrated. Are these relics from the days before calculators when one had to do computations by hand?

[@ASHUTOSHKUMAR-oe7xx]

Great teacher , and so thankful to you sir , 🙏

[@PardonNkandu]

Thank you so much...i really needed this.

[@gabrielmcpherson5756]

Thank you so much sir. It is completely clear to me now.

[@jimmyMagdato]

the 0.00369 is the mol of combination for Pbi2 (Lead Iodized). My question is, how come that the 0.00369 is the mol solely for pb?? so supposedly, the mole for Pb is lesser than 0.00369, right?

[@layzymarky7351]

n(PbI2)= nPb + nI let x be the moles of Pb 0.00369= x + 2x 2x

[@Eunice828]

Thank you so much for this

[@ZChrist_jesus]

wow u make it easy to understand ,thank u

[@mivineotnabab9669]

Please make a video about titration method

[@A_person-c]

You better name your channel "Heisenberg".. 🗿

[@Viablepride]

😂😂 that's right

[@danielmwikisa4920]

Thank I needed this

[@rizwankk1551]

Tooooooooo much good

[@tysanameleo5633]

Thank you sir

[@Mmjjap]

If you cut too much talk and camera flirting and get into the procedure with no frills, you can get this video in 5 minutes. Then, your video will be more educational than not. Students are pressed for time; you know that. I learned a lot, great job!