How to draw a regular pentagon knowing the length of one side

[@enma_nexa]

I got scared looking the intro , i though it was the actual construction😂

[@meghanworkman6449]

I'm glad it wasn't just me lol.

[@ericwu6571]

lol

[@mickelplays9386]

Lol good one

[@collinsusiade4054]

Heptagon

[@fredricholst5362]

Shaikh Shoeb HAHAHAHA i agree

[@deckiedeckie]

Great.....to see how KZbin can be utilized to do useful stuff....

[@D_Mff_gamer]

Thank you sir apne mere submission me help ki 🤗

[@indranilkundu9101]

I have to draw all the polygons from 3 sides to 8 sides for my project. Your videos really helped me. I couldn't have asked for a better tutorial. Thank You sir.

[@mildmanneredmercifulmouse1839]

This is BETTER than watching a Hollywood blockbuster movie.!!

[@FUNKINETIK]

So interesting, I can see how this works now. From the line AB you have determined the point Q. The line AQ is the golden ratio (Phi) of AB. The opposing corners of a pentagon e.g. line AD is the result of multiplying the side length of the pentagon by Phi (1.618....)

[@ochembachinwendu7113]

Bruh🙄

[@rhqstudio4107]

Thanks!

[@KeeperofTheMountain]

I am building a 5 sided cupola to go on a pentagon shaped gazebo. It is an inverted radius conical cupola. I needed this one formula to lay it out. Thank you.

[@Aman_Gamer_10-s8r]

🙏💕 thank you you help all students👦📖🎒👦📖🎒👦📖🎒

[@bibibacchus4059]

Oh wow, it turned out great. Thank you so much !!

[@tugalgito]

OMG! this type of videos are amazing for do arts homeworks.

[@dorcaslagracetiche4639]

Wowwwwww. It actually works. It's like magic.😮. May God bless you😇 and Thank you sir.😋

[@Jacobballeez]

Im doing technical drawings and I missed this class so thank you

[@stephonramsaran7704]

awesome video helped me so much god bless ya bro

[@noxie_nay]

Let me guess you're here because you have an EGD exam coming soon I know...I know same reason

[@deathwalker8730]

Thank u so much have a test tomorrow and this helped me loads fam thanks

[@xx_cuddlyclouds_xx5733]

Thank you Aurther Geomitry!!!You helped me with my module in my math!it was so hard until I saw this!!😄😄😄

[@jacklinemmaduagwu8037]

Omg so simple and easy. I got it on the first try. Thanks.🤗🤗

[@bhupeshshah272]

This help me a lot in my submissions

[@rosaliavadeliveiwase613]

Thank you so much sir....26/10/2021....Really help me with my school work

[@starkiller1228]

Thanks man, your better than my teacher

[@billyspencer7325]

This was a tough one kept getting confused over the changing radius and where to put the compass point, had to rewatch a fair few times

[@Kitsomia]

That's Awesome, I always wanted to draw a pentagon without using a protractor.

[@olliegibbons843]

A god amongst men,thank you

[@goldenadhd3149]

4 years later and you're helping me pass my last year of school

[@Satoru_Gojo36817]

Thanks for your tutorial.

[@KarimiChelsea]

Was stuck on an assignment and this helped me out. Gracious 😇

[@marc_0]

I've been saved Thank youuuuu

[@elim.8315]

THANK YOU SO MUCH u explained it so well

[@idlanbruhanuddin9447]

thnx......i actually know a method tht can draw a pentagon too easier though...but i cannot remember.....it all starts w/ cross and circle.....but urs are a bit complex but still easy to understand....

[@Narja23]

thanks you, it's so helpful

[@sfisosmall6226]

Thank you this will help me on my drawing s

[@chrystopherluke1261]

I have a hmwrk assessment to do and this helped a lot

[@rhy4551]

Phyc Ward SAME.

[@ratulhasan7136]

Sir, Thank you so much. Because I was badly in need of a Pentagon. This video is easier than others.

[@sumitabasak9244]

Right

[@sumitabasak9244]

You say right

[@Konijvis]

thank you, keep up the good work in teaching and helping students.

[@robertoyllia8373]

you are the best one

[@arthurgrunwald3859]

Thank you very much for your wonderful video! it is so brilliant! Since not all methods are exact, I was curious to find out whether the angle QBC is indeed 72 degrees. So, I tried to proof it as follows: First, use the right-angle triangle MBP to compute the length MP. For clarity, denote the base AB = b. This yields MP=0.5*b*sqrt(5). We now compute the length AC which equals AQ. Since AQ = MP + 0.5*b, it follows that AC = 0.5*b*(sqrt(5) + 1)). The triangle ABC has a base length of AC and two equal sides of length b. Using the cosine rule: AC^2 = 2*b^2 - 2*b^2*cos(gamma), where gamma is the angle ABC. This yield cos(gamma) = 0.25*(1 - sqrt(5)).= -0.3090. gamma = acos(0.3090) = 108 degrees. The angle QBC is then 180 - 108 = 72 degrees. It remains to be proved that point D is indeed the top of the pentagon. This is proved by the fact that the triangles ABC and BCD are congruent and thus BC = CD. Arthur, in contrast to other methods, your method is exact! Thank you again for your crystal-clear video which inspired me to do this exercise with tools we learned 50 years ago. Let me know if I missed out on something.

[@6rw1b]

Finally found one that works, much appreciated thank you so much!

[@M_R_H_Rokib]

Please give us a video on "Drawing Pentagon Using Perpendicular bisector method"

[@ArthurGeometry]

Copy that. Thanks!

[@M_R_H_Rokib]

@@ArthurGeometry Welcome 🥰

[@uevankhell]

Ah seriously, thank you so much. I've already watched two of your videos and it's been going great! Taking Tech Draft class was probably a bad one on my side but I can't help but try to widen my knowledge at some point.

[@indt1648]

very useful, good job

[@dimplematutino]

Thank you so much!😊✍

[@theopokashimba2897]

Wonderful... this is so helpful, i have been struggle to draw a pentagon now i got it exactly. Thanks more your video helped me out.....

[@pururaj2920]

Very good and easy steps

[@poorvanair3666]

Ommmggg ur a live saver !!

[@andymarkle465]

enjoy this pentagon is very beautiful, thanks very much. cute pentagon!

[@raven1742]

Thank you so much man i love you Fun fact: i am from italy and i understood YOUR explanation and not my teacher one LOL

[@rrkanb]

Love from Nepal

[@ebrimasamba8277]

Nice man

[@tronrevel7751]

Pentagon process is lit

[@sanjeet_art_205]

Thank you so much sir... 👍🏻

[@hrishikeshtambe4332]

Thankz alot....u really explain very well and it's very easy to understand

[@siyasundriyal9543]

Sir...this video is good

[@minalikabra2057]

Thanks alot you helped me in My Project☺️🙏🙏

[@arushiarya2190]

Thanks a lot for this my Pentagon turned out perfect!

[@nerminsejdinovic8696]

Thanks a lot, Sir! Really helpful and easy to learn.

[@splendor10]

Intro🔥🔥🔥🔥🔥

[@christellebosch6008]

Thank you it helped ma a lot

[@hibeelhachasan1232]

Thank you very much ❤

[@spring74light]

A very interesting construction. Thank you for it. Have you a geometrical proof that ED and DC are equal in length to AB?

[@anneludlow]

They were constructed with that length on the compass!

[@spring74light]

Thank you for your Reply. With respect, if you look on from about 3:30 you will see that points C and E are each located of by the intersection of 2 arcs, one of which has radius (AB), and the other an arc of greater but unspecified radius passing through point D. DC and DE are not directly referred to distance AB.

[@spring74light]

@glyn hodges Sorry, I have been 'off-air' for a while and have just discovered your detailed and comprehensive Reply. Thank you. I look forward to following through your reasoning, and will respond in due course.

[@bansalsanitary8885]

kzbin.info/www/bejne/nmbRhmmsZ9Voh9k Please watch like comment

[@daygelguzman944]

Super it helped me a lot

[@seamusmcardle2610]

first class instruction,thank you.

[@marikanaseidu3884]

thanks for this video

[@asamikimura5584]

Thank youuu❤❤

[@harshavarthinisr6240]

Thank you so much ✨

[@garyriegelsberger4208]

Awesome! Thank you for taking the time to create this video and post it. This is the perfect information I was looking for that will allow me to construct my device.

[@Pantydropper8374]

waoooo... thank uuuu sooooo much buddy... great help.... great help....

[@iukaz8682]

LEGEND!!!

[@haydentaylor5250]

this is gonna take a bit to make a dodecahedron for my purposes, but thanks alot!

[@droidguy1571]

the best construction vid ever thnx a looooooooooooooooooooooooot!!!!!! LOL

[@dubdavis407]

technically it is not a construction in the euclidian sense, more a drawing.

[@aqueelahmad7208]

thanks to this i passed my test yesterday

[@swapnilrai1168]

Thanks it was awesome

[@leonardmcoy3001]

Helped a lot thanks

[@tinomutendabrian6777]

Clear information

[@milos-nq1lm]

Thank you

[@tdrawsa]

Great work! Thank you.

[@spole1699]

Very helpful

[@siddharthrevankar3474]

thank you very much for your easy tutorial!

[@TheOriginalKidCoyote]

thanks! worked for me

[@spectrae2817]

Thanks dude , this vid help alot

[@thekoreanspace272]

understandable video, nice

[@shreyashpatil4319]

Nice sir 👌

[@sophiesallows5456]

This was very helpful. thank you :)

[@nkosinathidhlamini2791]

Very helpful thank you

[@jsoren9130]

Is it regular, though? I like it, but you have to check the angles to make sure it's not slightly squashed vertically or horizontally. Many people, showing various methods, are failing to check the angle measurements to make sure they are all 108°. One method gave me two 106°(at the bottom), two 109°, and 110° at the top. Even with the sides all equal, it still can have symmetrical variability in it's angle measurements.

[@jsoren9130]

I saw the other version where you inscribed it in a circle. That would guarantee the angles to all be equal at 108°. So, you'd have to find the center of this Pentagon and draw a circle around it to see if all the corners fall on the line.

[@shubhamsuryavanshi0708]

Thank you very very much sir

[@gurmanjotsinghgrewal4741]

Thanks for video

[@mohitpanchal2023]

Thank you very much sir

[@tronrevel7751]

really helpful

[@Nothing-rg8ev]

YOU SAVES ME THANK U SO MUCHH

[@Jacobballeez]

Rlly appreciate it

[@mesapetr9985]

Thank you sooo much

[@philipalawonde8291]

Am I mistaken, or is this an approximate construction based on the very crude approximation of √5 by √8?

[@gaurav_bora_]

yayy!! i did it thanks to youuu

[@legnd8382]

got you as my school homework

[@brindaparthasarathy7344]

Is there any other alternative method?

[@ArthurGeometry]

+Brinda Parthasarathy Hi please find attached a link to an alternative method called "Inscribed Pentagon" kzbin.info/www/bejne/b3_QgGR4ppKijck

[@generalmalhar6777]

Very helpfull

[@justjona3260]

Sick bro

[@Kholanee]

Oh you GODSEND

[@bryanthebomber7127]

I'm experiencing a problem. My teacher gave me a length of 20cm and my compass can't go that far, what should I do?