How to find Centroid of an Composite Plane | Problem 6 |

[@siddheshpatil5170]

Saviour! !!!🙌 MuchRespect Sir

[@Utkars11]

Thank u sir for making such quality videos . Your teaching style is too good . You are too honest about teaching .You upload videos regularly . If any one will watch your videos regularly then he will be expert in engineering drawing like me . Thank u so much from my heart

[@oguzolcay9813]

i have an engineering mechanics exam 2 days later and i am here to be sure i got everything or not. i am probably gonna watch every single video in this part. thank you so much for doing this.

[@rahulg.c4861]

I didn't knew single thing about centroid untill i watch few of your videos. Thanks alot Manas. You are a legend

[@efilata7854]

I just finished watching all the problems and I would love to thank you!!!

[@katarisankarreddy8017]

Sir really u r giving wonderful teach ,each and every person should get easily. u r way doing problem each and every point u r presenting good .thank q

[@ManasPatnaikofficial]

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[@sriharijavvaji1193]

🙌🙌

[@booshcockappu]

I do not know who you are. You taught me, but my professor said, 'take this as a Homework' and he leave.😞 Thank U sir. Do more videos👍

[@rainasajid6678]

Thank you so much! This is what perfect teaching looks like!

[@nimcaandayib6222]

Dear teacher, I am grateful to you.you have done great job for us.

[@lakialgom2383]

Well explained Now I complete my assignment

[@patpadua3171]

Thanks a lot Sir! You taught way better than my professor! Just done with my classwork. 🙏🙏🙏

[@efu-10]

fantastic video, thanks!

[@lilianmomanyi3464]

very helpful. Thank you for the detailed explanation

[@pavansai2107]

As all sides are equal we need to take it as a square but you took it as a rectangle.

[@yashgoyal1513]

Just take it square from ur side

[@shridharsegdar7164]

Perfectly prepared for Tomorrow's exam ... Thankyou Sir ..😍

[@icaroeleonormolina2157]

X coordinate for A2 isn't 175.5 rather 174.54 U guys should try to solve 200-[4(60)/3π]=174.54 And thats normal getting a different answer because of the discrepancy. I got (x,y) = (97.65 ,96.86)

[@HDocshere]

ofcourse

[@BokagneGildas-vw2mw]

Thanks was of great help

[@abhishekjaiswal7210]

i am very thankful to you for your efforts...pls upload more videos for btech students..thankuh.🙏🙏🙏🙏🙏🙏🙏🙏🙏

[@ManasPatnaikofficial]

Thanks abhishek..............more videos will be uploaded in future..........

[@abhishekjaiswal7210]

thkuh sir..i was afraiding from my mechanics but now through ur videos . mechanics will afraid of me.

[@charishma4567]

Thanku sir.... It's really useful for us😊

[@sgiri2012]

Here, we are intending for finding the centroid of the region where it is shaded. Why we consider the outside region centroid to evaluate the centroid of our interest ? Kindly reply sir

[@rinru5524]

Thank you so much for your help! I got it right away!

[@kherdhruv2947]

Sir here for the triangle, when we find the X position of the centroid, won't we take the measurement b/3 from the vertex between hypotenuse and the adjacent side, and if that is true then we will have to do (80 - b/3), ryt?

[@vidyal5086]

Tq u very much sir I am clearly understood by ur teaching

[@malinim.udayananden9820]

Very very usefulll🥰👍🔥🔥

[@nireekshanathurpati8797]

Much respect to you sir . Thanks a lot

[@mdasifraini4068]

Super sir well teaching like coaching faculty

[@ManasPatnaikofficial]

Which coaching provides Digital Education like this..... Do let me know?

[@mdasifraini4068]

@@ManasPatnaikofficial sir I'm not talking about digital teaching sir rather I'm taking about your way of teaching.

[@mdasifraini4068]

It's the best ways

[@abigaelmwangi1307]

How do u determine which side of the rectangle is the base by just looking at it? The shorter side? ..Thank you for the video...very helpful😃

[@oldmonk006]

sir i have a question , whilw calculating the area of the rectangle (a1) why didn't u subtracted the semi circle and traingle area????

[@bobosamathcee]

Thank u A lot sir🙏🥺 such a big help

[@markkennedy9767]

Can you explain mathematically why we can always find a line through a lamina (eg a horizontal line y=a in some coordinate system on the lamina) such that the moments on either side of this line sum to zero. It's intuitively obvious physically (hanging plumb lines etc) but I just can't prove this mathematically. The mathematics involves the integral of all the moments of every point mass of the lamina on either side of such a line, putting this integral equal to zero and solving for the coordinate of the centre of mass. But why can we always assume we can put such an integral equal to zero in the first place.

[@teja9681]

I really don't know what to say, but I can tell you heartful thanks sir

[@ManasPatnaikofficial]

All the best. 1. Engineering Drawing (English) : kzbin.info/aero/PLIhUrsYr8yHwDUrVYmUNYkEeZgZTvoIfS 2. Engineering Drawing (Hindi) : kzbin.info/aero/PLIhUrsYr8yHx0C3ebAW-FQxTP8ig8-QxU 3. Engineering Mechanics: kzbin.info/aero/PLIhUrsYr8yHxfOmcGIeUThHEr9lQ3IXRS 4. Mechanics of Solids: kzbin.info/aero/PLIhUrsYr8yHzft7ygw5THZo4aDcsxEadP 5. Theory of Machines: kzbin.info/aero/PLIhUrsYr8yHx0aFXSQvT7nm6ivJSMKnAU 6. Machine Drawing: kzbin.info/aero/PLIhUrsYr8yHzwT06rv7u3tqdfmmKOCz1w 7. Engineering Services Examination_Engineering Drawing_Prelims: kzbin.info/aero/PLIhUrsYr8yHwFTNav_k3EEIvztQEQHilU 8. Physics for Class 11: kzbin.info/aero/PLknJ2c9H1euEwtFJLUGZvkjG35OoVvemM 9. Manas Speaks Series: kzbin.info/aero/PLIhUrsYr8yHz9g5V7Lw_BA5UXbAbgVyf0 10. Physics Channel Link: kzbin.info/door/_aqx41HWeOebfL6FqBYU6Q My AMAZON Store - For all you students. www.amazon.in/shop/manaspatnaik

[@salwarad2913]

From morroco you help me thank youu

[@marjoriebayeta6556]

Hi, do I really have to put all the value of the pi? Or can I put 3.14 only?

[@ManasPatnaikofficial]

Its your choice. You can compute the answers in terms of pi. However, i would suggest that you plug in the value and get the answer i.e its numerical value.

[@dosapatiteja1588]

sir can u please find Ixx and Iyy of this question . Thank u for great teaching

[@bobosamathcee]

Life saviour🙏

[@nareshreddy9489]

What happens when I shift the semicircle downwards and I don’t know the projection beyond the edges of semicircle?? Will it be solvable??

[@georgelukama7280]

Is the is 3 coming from when finding x3 on a right angle triangle

[@aliabdlaziz1513]

Brilliant vedio sir

[@ManasPatnaikofficial]

Hi Rahul......... Thanks for appreciating my work and do spread a word about this channel among your friends and classmates so that they can also benefit.

[@praisecharles8446]

Sir ........what if there is a circle inside the square and not a semicircle......how do I solve for xc and yc

[@venkiplaysguitar]

Thanks a lot sir...

[@evrstnslv]

Wait i dont understand why half of right angle triangle is that square? Why divided by 3?

[@SalmanAli-qy5fk]

Thank you a lot of sir❤️❤️❤️

[@tarungorli1436]

1st viewer and commenter

[@sh.joyshankersharma9611]

Sorry Sir but x2 value is 174.5

[@mdasifraini4068]

But in trapezium que. We can also do by finding area of trapezium and subtract area of semi circle

[@pritishranjanraul2858]

Ek dum jhakas

[@ManasPatnaikofficial]

You can access all the videos from mechanics from this playlist. Engineering Mechanics | Applied Mechanics: kzbin.info/aero/PLIhUrsYr8yHxfOmcGIeUThHEr9lQ3IXRS

[@tebzini2607]

give this man a bells

[@ganeshghode5595]

Thank u sir☺️☺️☺️

[@_yaswanth_varma_9588]

can u see check at x2 value once again . i have a doubt in that. please check value in any teaching there is no mistake

[@JovelSam]

if the question's values are given in mm, do we have to change it into cm ?

[@yahayamohammed9974]

2. Find the centroid of a semicircular section having outer and inner diameters of 200 mm and 160 mm respectively please help me out sir

[@alonsoaaronm.5986]

I got different final answers for x and y. x=120.42 cm. y=103.30 cm. Idk but we got the same solution and values. Thank you for your response sir!

[@anupatiyaswanth160]

sir can u plzzz solve a problem of centroid of a sector which is symmetric about y axis???

[@junivenacapulco304]

What software are you using Sir?

[@asishchowdary6890]

Sir I have the question but I can't sloveing it I am trying to slove but it not possible can u tell about how to retifie it plz

[@virendarnathchadha5371]

Sir i have a doubtt how can I post the photo ?? Please tell sir

[@Mahesh-9253]

Excellent teaching sir

[@ManasPatnaikofficial]

Engineering Mechanics | Applied Mechanics: kzbin.info/aero/PLIhUrsYr8yHxfOmcGIeUThHEr9lQ3IXRS

[@milansanthosh166]

Can you say it once more while finding the x axis and y axis of right triangle

[@markvincentvelascodingle1311]

the value of x2=174.54.

[@justineparadero6814]

How did you get 97.28 When i compute the Xc=i got 97.462

[@nandakishorjm1459]

Best class

[@gamebredtv804]

where are the centre of gravity problems

[@YashwanthSinghP]

Sir I am unable to solve one problem.please help me in solving that problem sir.

[@bibeksinghthakuri8273]

174.535 is x2 for semi circle

[@rahulhere13]

Thanks a lot🙂

[@shravangoud6668]

Thank u sir

[@mdasifraini4068]

Sir please upload complete engineering mechanics

[@ManasPatnaikofficial]

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[@samirkhadka4133]

How to find whether your ans is correct or not

[@itaachiii]

isnt this (big shape) a square tho

[@rushikeshjadhav7748]

Thankyou sirjii

[@mohamednasr6694]

very good and can you make more videos

[@ManasPatnaikofficial]

This is the entire playlist of mechanics Engineering Mechanics | Applied Mechanics: kzbin.info/aero/PLIhUrsYr8yHxfOmcGIeUThHEr9lQ3IXRS

[@chokigyeltshen2717]

Thank you so much sir...its helping us great...may I have your mail so I can drop my personal question sir

[@harshice_0793]

Tnq alot sir.....

[@ManasPatnaikofficial]

All the best Subjectwise Playlist: 1. Engineering Drawing/Graphics (English): kzbin.info/www/bejne/jXiZeWWmfriIsLM 2. Engineering Drawing/Graphics (Hindi): kzbin.info/www/bejne/iXObZJaLlqacea8 3. Engineering Mechanics / Applied Mechanics: kzbin.info/www/bejne/kGW6f2WQbtSenNU 4. Mechanics of Solids / Strength of Materials / Mechanics of Materials: kzbin.info/www/bejne/eaCXip-Xq6ijm7M 5. Theory of Machines: kzbin.info/www/bejne/eaCXip-Xq6ijm7M 6. Machine Drawing: kzbin.info/www/bejne/n3emn3mLh556msU 7. Engineering Drawing for Engineering Services Prelims: kzbin.info/aero/PLIhUrsYr8yHwFTNav_k3EEIvztQEQHilU 8. Physics for Class 11: kzbin.info/www/bejne/ZpfIm4h5bJ5_kLs 9. Manas Speaks Series: kzbin.info/aero/PLIhUrsYr8yHz9g5V7Lw_BA5UXbAbgVyf0 10. Channel 2 Link: kzbin.info/door/_aqx41HWeOebfL6FqBYU6Q

[@sunilr2804]

Thank you so much sir

[@ManasPatnaikofficial]

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[@sphamongorosh8364]

i am confused on how you get your x2?

[@ManasPatnaikofficial]

Well I can only say that you need to watch the video again I am sure you will be able to work it out yourself

[@AbdulJalil-uw3ro]

Sir i can't understand x2 I think x2 =140+((4*60)/(3*π))=165.46 cm Sir Plz solve my Problem

[@ayamsapkota4041]

200-(4r/3π) is equal to 174.5 not 175.5 :D {5:31}

[@siddharthmurali9861]

true , i am getting the values as y=90.25 and x=97.648

[@prajwalgawai2912]

Tysm😊

[@Thedisgracedone_2004]

sir this is a square not a rectangle

[@KajalKumari-wh4oc]

😊

[@prathameshshede7622]

Thanks sir

[@abhinavawasthi6553]

area of a2 seems to be incorrect it should be 5652

[@rightwinger2709]

Sir my ans of Xc is 97.65 is it ok plz rply..

[@yashgoyal1513]

Ya its correct... Same as me

[@satishkumar-iv5bw]

X2 =51.32 value but you got 175.5 how sir once tell 😬🙄🤧🤧

[@you-ep1qq]

It's not rectangle, it's square man

[@Muralikrishnagorthi]

Sir that is square not rectangle

[@subramaniramesh7725]

X axis is 200cm Y axis is 120+40+40=200cm Then it must be square not a rectangle

[@ManasPatnaikofficial]

Yes you are right.........I got tricked by the shape. Glad that you pointed out. 😀Do share this channel and its playlist with your friends. 1. Engineering Drawing Playlist (ENGLISH): kzbin.info/aero/PLIhUrsYr8yHwDUrVYmUNYkEeZgZTvoIfS 2. Engineering Drawing Playlist (HINDI): kzbin.info/aero/PLIhUrsYr8yHx0C3ebAW-FQxTP8ig8-QxU 3. Engineering Mechanics Playlist (OLD): kzbin.info/aero/PLIhUrsYr8yHxfOmcGIeUThHEr9lQ3IXRS 4. Engineering Mechanics Playlist (NEW 2023-2024): kzbin.info/aero/PLIhUrsYr8yHxeypEyVdWeGNxWHjNxU_JP 5. Mechanics of Solids Playlist: kzbin.info/aero/PLIhUrsYr8yHzft7ygw5THZo4aDcsxEadP 6. Theory of Machines / KOM / DOM Playlist: kzbin.info/aero/PLIhUrsYr8yHx0aFXSQvT7nm6ivJSMKnAU 7. AUTOCAD Playlist: kzbin.info/aero/PLIhUrsYr8yHyLArdiiSDLa0Fmz8YKIy7G 8. Machine Drawing Playlist: kzbin.info/aero/PLIhUrsYr8yHzwT06rv7u3tqdfmmKOCz1w Visit Main Channel Page(@manaspatnaikmech) for Playlists on specific topics. Second Channel for Hindi Audience: @btechplus Download the Manas Patnaik App for Premium content : bit.ly/3wMRxoc

[@0501245]

It is 2/3*b not just b/b

[@shivasharanj8690]

Thank you so much sir