How To: Find Limiting Reagent (Easy steps w/practice problem)

  Рет қаралды 414,836

ScienceMade Easier

ScienceMade Easier

9 жыл бұрын

A video made by a student, for a student. Showing how to find the limiting reagent of a reaction.
Kansas University. Rock Chalk Jayhawk, KU!!!!!!!!!
IGNORE:
Stoichiometry. Biology. Chemistry. How to work practice problem. How to convert. moles to grams
. grams to moles. how to. doing chemistry practice problems. science. how. to. do. science. intro college chemistry level. problems. molecular weight. neutrality. acid. base. calculations. molar. mole. molar unit. grams. weight. chemical. formula. empirical. molecular. science equations. easy problems worked. made easier. made easy. density. mass. volume. how to find them. finding density. finding volume. finding mass. how to find molarity. how to find molecular weight of anything! all chemistry equations keywords

Пікірлер: 305
@shemarwatts3928
@shemarwatts3928 4 жыл бұрын
How did you get the 1.75 moles you never explained that part
@sciencemadeeasier7100
@sciencemadeeasier7100 4 жыл бұрын
you're basically, instead of saying, for every 4 moles of NH3 you need 7 Moles of O2. your dividing 4 by 4 to make it 1 and whatever you do to one side of the equation you have to do the other, so you divide 7 by 4 aswell to get 1.75. therefore for every 1 mole of NH3 you will need 1.75 Moles of O2
@ej4458
@ej4458 4 жыл бұрын
@@sciencemadeeasier7100 but why by 4? why not by 7?
@bakhshizulfiqarmanzur8988
@bakhshizulfiqarmanzur8988 4 жыл бұрын
@@ej4458 I think it's because if you divide by 7, you would get a recurring decimal if you divided by 7, thus making your life harder for no reason
@charlierichardson8778
@charlierichardson8778 4 жыл бұрын
@@ej4458 ​ @Bakhshi Zulfiqar Manzur you are dividing 7 by 4 so that you can find out how many moles of O2 reacts with 1 mole of NH3
@zainpunjwani470
@zainpunjwani470 4 жыл бұрын
@blip trip in math generally, you want to get to 1 as your least common factor, so to get 7:4 is the same as 1.75:1 since 7/4=1.75, and 4/4=1. Hope this helps! :D
@alexxxx7826
@alexxxx7826 7 жыл бұрын
I'm a senior in engineering and i needed to review how to do this stuff. You made this video short, straightforward, and easy to understand. thank you
@sciencemadeeasier7100
@sciencemadeeasier7100 7 жыл бұрын
Thank you very much Alex, glad I could be of assistance.Good luck, finish strong. I have a good friend in his junior year now..shit looks nasty
@ItsAkra
@ItsAkra 8 жыл бұрын
I have watched at LEAST a dozen L.R. vids, trying to understand this (including all the best known Chem people on here) and this is THE ONLY ONE I GET. Thank god I get it now!
@sciencemadeeasier7100
@sciencemadeeasier7100 8 жыл бұрын
+Alexandra “North Star” Wilson Thank you so much! Thats exactly what I thought before I made my chemistry tutorials.. I couldn't find a good video online to teach me so I made my own videos to basically teach myself but others find them very useful :) Glad I could be of assistance and thank you for the compliment!
@shanthinarayan7019
@shanthinarayan7019 5 жыл бұрын
Yeah
@thembiemadlophe2618
@thembiemadlophe2618 3 жыл бұрын
Simple, straight to the point videos like this are hard to find these days on here, thank you.
@sarahshaban906
@sarahshaban906 5 жыл бұрын
this makes so much sense now! my new teacher just assumed everyone knew how to find limiting reagent but some of us students need to be reminded. thank you for this video!
@juanvalencia9378
@juanvalencia9378 6 жыл бұрын
Great video! I looked at 3-4 other sources and your explanation was by far the best. Keep up the good work!
@liamphillips9027
@liamphillips9027 4 жыл бұрын
thank you so much man i've been stuck on this for a few hours now and i finally get it, i've watched so many other videos but this video finally made it click! Thank you!!!!!
@ZacHHackable
@ZacHHackable 7 жыл бұрын
u saved my ass bro thanks
@sciencemadeeasier7100
@sciencemadeeasier7100 7 жыл бұрын
i gotchu bro
@adamcohen2881
@adamcohen2881 6 жыл бұрын
huntsman knife....xd
@SykoPatho
@SykoPatho 6 жыл бұрын
this teflon from h1z1?
@Emily-ze5er
@Emily-ze5er 3 жыл бұрын
This is the most helpful video I’ve found so far, thank you so much
@Hazza9990
@Hazza9990 5 жыл бұрын
Actually made sense and is a quick method unlike other videos . I’m very impressed !
@nataashaleong647
@nataashaleong647 7 жыл бұрын
I've BEEEEN struggling with this! Great video, thanks a million :)
@ragd0ll667
@ragd0ll667 2 жыл бұрын
thanks man, i did so many of these wrong as I mixed up how many moles needed with how many you actually have - this was a very clear explanation
@LeyahStorm
@LeyahStorm 7 жыл бұрын
Thanks for this. I've been super confused about Stoichiometry and I've watched other videos, even with a food analogy, but this one made the most sense. Cheers!
@mariaremik.j.8919
@mariaremik.j.8919 2 жыл бұрын
1. Quick vdo 2. Simply understand. 3. Tysm 😄ok bie.
@tiktokopedia2846
@tiktokopedia2846 4 жыл бұрын
THIS VIDEO WAS EXTREMELY HELPFUL. You literally saved me bro!!!
@scooby253
@scooby253 7 жыл бұрын
This video saved me and I'm doing AS chemistry! My teacher is rubbish but you explained it very well!! Thanks so much!
@lilfairyprincess1o1
@lilfairyprincess1o1 7 жыл бұрын
Amina Ahsan bruh I'm doing this at igcse lmao
@denise1116
@denise1116 7 жыл бұрын
Amina Ahsan same my chem teacher sucks 😂
@zhehin917
@zhehin917 5 жыл бұрын
Wow thank u so much for summarising two classes into 3 min
@hollyatomic
@hollyatomic 6 жыл бұрын
this makes the process so much easier, thank you !
@RedwaveStudios1
@RedwaveStudios1 7 жыл бұрын
Skipped a year, needed this man. Thanks!
@Strawberry.swisher.666
@Strawberry.swisher.666 2 жыл бұрын
Ive been stressing all week because my teacher sucks at teaching and I have to resort to KZbin as a replacement for my teacher. I finally found a video that made finding limiting reactants simple that also showed how you find the actual mole ratios. Thank you!
@srijnasahni7358
@srijnasahni7358 3 жыл бұрын
Amazing!! With the easiest explanation possible.Thanks a lot.
@sakshammankotia773
@sakshammankotia773 7 жыл бұрын
your marker works perfectly well lol
@lexibug6001
@lexibug6001 6 жыл бұрын
This was insanely helpful, thank you!!!
@meowmeow646
@meowmeow646 4 жыл бұрын
I really needed this, thanks a lot helped me very much!
@jakethatsnake55
@jakethatsnake55 7 жыл бұрын
You absolute legend, you made it so simple an easy! I know my brain is going to melt in my exam tomorrow and i probably still wont get this question right but i feel more comfortable now 😂😂😂
@manyagupta2858
@manyagupta2858 3 жыл бұрын
Thankyou so much! This video really helped
@user-od8vx2ei9g
@user-od8vx2ei9g 3 жыл бұрын
this is was so helpful thanks so much brother
@Omxralb
@Omxralb 4 жыл бұрын
You're telling me that my university professor took an entire class to explain this, while I learned it in 3 minutes?
@lanalana1986
@lanalana1986 3 жыл бұрын
yes
@te1327
@te1327 3 жыл бұрын
Your doing this in uni??
@abhya12
@abhya12 2 жыл бұрын
@@te1327 lol i was wondering the same cuz i m doing this in junior year of high school
@te1327
@te1327 2 жыл бұрын
@@abhya12 yeah in the UK we did this in year 10 which I believe is freshman year in the us (14-15)
@abhya12
@abhya12 2 жыл бұрын
@@te1327 sophomore it is, and yea same, we did it in year 10 too!
@denise1116
@denise1116 7 жыл бұрын
Thank you!! This is so easy to understand :)
@tawnyanderson3092
@tawnyanderson3092 5 жыл бұрын
super easy explanation!! great video!!!!
@leena_peena
@leena_peena 4 жыл бұрын
THANK YOU SO SO MUCH!!!! I FINALLY UNDERSTAND IT
@xtabbytayyibahx9600
@xtabbytayyibahx9600 3 жыл бұрын
THANK YOU!!! I FINALLY UNDERSTAND THIS!!!
@Vijay1591
@Vijay1591 8 жыл бұрын
Thanks man... Really helped Me.
@jaymaganti6604
@jaymaganti6604 6 жыл бұрын
This is Perfect!
@BruceLee-bd4pr
@BruceLee-bd4pr 9 жыл бұрын
Thanks for video. This really helps!!! Please make more.
@areceipt0245
@areceipt0245 4 жыл бұрын
thanks so much bro this really got me prepared for my quiz today.
@bryyyson
@bryyyson 3 жыл бұрын
exams tomorrow wish me luck lol, and yes this video helped thanks
@kritikamalik2546
@kritikamalik2546 3 жыл бұрын
Thanks for the great explanation 🌸😊
@jessyleong4740
@jessyleong4740 7 жыл бұрын
Helped me a lot thank you 👍
@zainabulbannah9935
@zainabulbannah9935 3 жыл бұрын
Nice dude👍
@RahulSharma-rk4nd
@RahulSharma-rk4nd 3 жыл бұрын
He got that 1.75 by dividing the no of moles by the stoichometry of the reaction. Like 8/7
@jerinjoseph9039
@jerinjoseph9039 8 жыл бұрын
All other videos made me confused!......but this is too helpful.............
@kendigjl
@kendigjl 7 жыл бұрын
Excellent. Thank you very, very much.
@dvitipatel3330
@dvitipatel3330 3 жыл бұрын
thank you, this video really helped me :)
@rafsanrahman7810
@rafsanrahman7810 7 жыл бұрын
thanks bro you explained it well.
@reykjaviktotoronto186
@reykjaviktotoronto186 7 жыл бұрын
awesome. simple method. thx man
@mirandawbu
@mirandawbu 7 жыл бұрын
thank you. this is very helpful
@nermeenpal6034
@nermeenpal6034 6 жыл бұрын
Thanks this video is helpful
@karenhany9005
@karenhany9005 2 жыл бұрын
i have a chemistry test in less than 5 hours and this saved my life tytyty
@farahsemary4197
@farahsemary4197 5 жыл бұрын
OMG thanks finally I got it :)
@thomasjoseph1545
@thomasjoseph1545 7 жыл бұрын
@Lizzy Reese they make really confusing things in the text but conversion of moles is really easy , all you have to remember is No. Of moles = given mass / molecular mass or atomic mass of compound
@mehakthakur7
@mehakthakur7 5 жыл бұрын
U r osm....thank u so much... Ur video Help me alot 💫💫☺☺☺
@grantwilkinson2444
@grantwilkinson2444 7 жыл бұрын
Sweet. Thank you!!
@denabaker3794
@denabaker3794 7 жыл бұрын
amazing thank you so much!!!!!
@diamondwilliams5240
@diamondwilliams5240 8 жыл бұрын
at 1:45 - end I don't understand could you explain that more
@gear1421
@gear1421 3 жыл бұрын
Perfectly Explained Sir
@aceilshamieh557
@aceilshamieh557 6 жыл бұрын
QUEEN u really helped me
@rishiyadav9007
@rishiyadav9007 3 жыл бұрын
Absolutely fantastic. Had to watch it twice, though, but the result is what matters! Cheers, ScienceMade Easier! edit: who disliked this video?!
@joelees3297
@joelees3297 4 жыл бұрын
Ugh. 15 in AP Chemistry - You saved me from failing a midterm. Tysm
@philipgukassov4300
@philipgukassov4300 5 жыл бұрын
thanks, you helped a lot
@inakizm
@inakizm 5 жыл бұрын
Tomorrow I have an exam! Thanks bro u saved me
@risingwindspress
@risingwindspress 5 жыл бұрын
Exam tomorrow wish me luck!!!
@alphacooda8581
@alphacooda8581 5 жыл бұрын
same haha
@triciafradrick3731
@triciafradrick3731 4 жыл бұрын
Mine is today and i woke up 5 hours early to study 🤣
@checker_boarder
@checker_boarder 4 жыл бұрын
I got one tomorrow
@ammaarquraishi2398
@ammaarquraishi2398 4 жыл бұрын
mine is tomorrow
@deananeal02
@deananeal02 4 жыл бұрын
@@ammaarquraishi2398 sammee
@parthchouhan7786
@parthchouhan7786 5 жыл бұрын
Nice explanation brother 😉
@blankcuriosity...9750
@blankcuriosity...9750 5 жыл бұрын
what a lifesaver
@_jrl_5262
@_jrl_5262 8 жыл бұрын
Thanks! Makes a lot more sense now :)
@_jrl_5262
@_jrl_5262 8 жыл бұрын
+ѕнα∂σω✤ I've been watching other videos and they make it overcomplicated and more confusing than it has to be.
@cuzimbatman1399
@cuzimbatman1399 5 жыл бұрын
It helped thanks man
@hrishikeshboro3481
@hrishikeshboro3481 6 жыл бұрын
helped me... thank you
@aasmohammad2181
@aasmohammad2181 Жыл бұрын
Bro i really like the way you write 6..BTW very well explanation..
@ighadakj
@ighadakj 8 жыл бұрын
thank you very much!!!
@diegomedina5051
@diegomedina5051 6 жыл бұрын
midterm tomorrow, yet another life saved by this
@sciencemadeeasier7100
@sciencemadeeasier7100 6 жыл бұрын
Glad to be of assistance, Diego
@mallharkhatua7374
@mallharkhatua7374 4 жыл бұрын
Thank you so much
@ketchup7108
@ketchup7108 3 жыл бұрын
Thanks bro!
@nielscremer599
@nielscremer599 7 жыл бұрын
Saved me man, ily
@AkashKumar-wm6vv
@AkashKumar-wm6vv 8 жыл бұрын
how do u get 1.75??
@sciencemadeeasier7100
@sciencemadeeasier7100 8 жыл бұрын
+Akash Kumar 4 moles of NH3 require 7 moles 02. Therefore, Each mole of NH3 requires 7/4 of a mole of O2. Understand?
@onalennamoeti4231
@onalennamoeti4231 6 жыл бұрын
+ScienceMade Easier no
@amiracampbell5973
@amiracampbell5973 6 жыл бұрын
Onalenna Moeti So basically it's, So 4/4 = 1 So 7/4 = 1.75
@sydneym3251
@sydneym3251 6 жыл бұрын
Onalenna Moeti you have 4 mol NH3 and 7 mol O2. So when you take one mol NH3, you divided the original 4 mol NH3 by 4. (4/4 =1) So to keep the ratio the same, you also need to divide the original 7 mol O2 by 4 also (7/4 =1.75) . So that’s where the 7/4 mol O2 comes from.
@TheDrewster1123
@TheDrewster1123 6 жыл бұрын
you're basically, instead of saying, for every 4 moles of NH3 you need 7 Moles of O2. your dividing 4 by 4 to make it 1 and whatever you do to one side of the equation you have to do the other, so you divide 7 by 4 aswell to get 1.75. therefore for every 1 mole of NH3 you will need 1.75 Moles of O2
@Amelia-om7ew
@Amelia-om7ew 4 жыл бұрын
thank you!
@alisabah4744
@alisabah4744 4 жыл бұрын
Can you tell me please how the NH3 is the limiting reagent?
@owen9166
@owen9166 5 жыл бұрын
keep doing this ur the best lol
@madhumitha405
@madhumitha405 4 жыл бұрын
Thankyou guy💝💝
@TheFluffyMiners
@TheFluffyMiners 5 жыл бұрын
Got a test today. Wish me luck!
@sheebavenu4329
@sheebavenu4329 5 жыл бұрын
Thanku very much sir..
@varshapatidar7381
@varshapatidar7381 5 жыл бұрын
you r osm thankyu 😊😊
@gracemdermody
@gracemdermody 3 жыл бұрын
its the night before my test on this stuff and i dont understand one bit of it but this video made me understand it hahah, lets pray i pass
@bagavathynagarajan2705
@bagavathynagarajan2705 4 жыл бұрын
Can we use this method in all limiting re agent problem
@nischaygirish4109
@nischaygirish4109 5 жыл бұрын
Really neat hand writing
@SirCreepus
@SirCreepus 5 жыл бұрын
Cheerssss got my chemistry exam in one hour!
@katielott6226
@katielott6226 4 жыл бұрын
SAME
@sangat4315
@sangat4315 3 жыл бұрын
same lol
@nahidaasali2443
@nahidaasali2443 2 жыл бұрын
Woooooowwwwwwwww thank youuu
@monatestays7416
@monatestays7416 5 жыл бұрын
Awesome
@waad5497
@waad5497 5 жыл бұрын
You just saved my ass thx so much
@Kage1128
@Kage1128 4 жыл бұрын
Literally the only video i have found on youtube that explains it so simple and easy to understand. The rest is just a bunch of confusing bullshit
@elliemartin8957
@elliemartin8957 3 жыл бұрын
thank you thank you thank you
@NIKKI-xu7qb
@NIKKI-xu7qb 7 жыл бұрын
u are so so good. do u have video on theoretical yield calculation
@ZacHHackable
@ZacHHackable 7 жыл бұрын
its simple what the problem gave you divided by what the stoich equation gave you
@lucyw5684
@lucyw5684 6 жыл бұрын
Why do you do moles of NH3 x moles of O2 needed? I thought you did 8.06/2.58 to get the ratio then compare it to the ratio from the formula to see which one's in excess
@gageoutlaw3824
@gageoutlaw3824 2 жыл бұрын
Thank you
@OGtrushalpatel
@OGtrushalpatel 6 жыл бұрын
That was surprisingly easy...
@josh4467
@josh4467 7 жыл бұрын
How'd you know whether to multiply 1.75 by 2.57moles rather than 8.06 moles of oxygen
@haileyoberlander2743
@haileyoberlander2743 6 жыл бұрын
THANK YOU
@exha1edyt702
@exha1edyt702 3 жыл бұрын
What if it moles instead of grams like 43.9g
@mustafapeeran5964
@mustafapeeran5964 7 жыл бұрын
Very helpful thank you
@sciencemadeeasier7100
@sciencemadeeasier7100 7 жыл бұрын
Thank you (: Glad I could be of assistance
@marymaebatal1802
@marymaebatal1802 Жыл бұрын
How did you get the 43.4
@metalfacemo8055
@metalfacemo8055 2 жыл бұрын
bro i looovvveeee yooouuu
Limiting Reactant Practice Problem
10:47
Tyler DeWitt
Рет қаралды 1,2 МЛН
How To: Find Wavelength / Frequency (EASY EQUATION w/ problems)
4:05
ScienceMade Easier
Рет қаралды 582 М.
WHO LAUGHS LAST LAUGHS BEST 😎 #comedy
00:18
HaHaWhat
Рет қаралды 21 МЛН
I Can't Believe We Did This...
00:38
Stokes Twins
Рет қаралды 108 МЛН
ТАМАЕВ УНИЧТОЖИЛ CLS ВЕНГАЛБИ! Конфликт с Ахмедом?!
25:37
ПРОВЕРИЛ АРБУЗЫ #shorts
00:34
Паша Осадчий
Рет қаралды 1,6 МЛН
Stoichiometry - Limiting & Excess Reactant, Theoretical & Percent Yield - Chemistry
20:12
The Organic Chemistry Tutor
Рет қаралды 1,8 МЛН
How To: Find Molarity (EASY steps w/ practice problems)
3:50
ScienceMade Easier
Рет қаралды 102 М.
Converting Between Grams and Moles
10:47
Tyler DeWitt
Рет қаралды 2,4 МЛН
Find the Amount of Excess Reactant (+ Example)
5:37
chemistNATE
Рет қаралды 27 М.
Introduction to Limiting Reactant and Excess Reactant
16:58
Tyler DeWitt
Рет қаралды 2,8 МЛН
Stoichiometry: Mole Ratios | Grade 10, 11 and 12 Chemistry
12:12
Miss Martins Maths and Science
Рет қаралды 12 М.
How to find the limiting Reagent
20:48
Transcended Institute
Рет қаралды 2,3 М.
Percent Yield Made Easy: Stoichiometry Tutorial Part 4
7:45
ketzbook
Рет қаралды 227 М.
How to calculate limiting reagent in mole concept
27:20
The Dms Online School
Рет қаралды 9 М.
An Actually Good Explanation of Moles
13:37
Steve Mould
Рет қаралды 1,4 МЛН
WHO LAUGHS LAST LAUGHS BEST 😎 #comedy
00:18
HaHaWhat
Рет қаралды 21 МЛН