How to find the absolute max and min for 2cos(t)+sin(2t), calculus 1 tutorial

[@crystalhasley7613]

thanks for such clear and precise instruction, obvious patience for explaining every step

[@JACdUpProductions]

absolutely amazing way of explaining every single thing. thank you so much. liked and subscribed

[@medicisounds1384]

for this you can just divide by 2 once you get to the f'(x) = -2sin+2cos2x. Set it equal to zero and divide and it gets rid of the 2 and you dont have to worry about distributing.

[@officiallyaninja]

whoa, what's the tic tac toe method? I've never seen that

[@littleretroship6403]

I want to try this. For the record, I have no experience finding absolute mins and maxes with trig functions.I feel like it’s gonna be hard but i want a challenge. f’(t)= -2sint + 2cos(2t) set f’(t) to 0 and solve for t 0=-2sint + 2cos(2t) I can factor out both -2 and 2 0=2(-sint + cos(2t)) 0=-2(sint - cos(2t)) And ig divide both sides 0=cos(2t) - sint 0=sint - cos(2t) I’m sorry but I have no clue how to solve when it’s sint and cos(2t) I will check wolfram alpha Nevermind this is really complicated Edit: ah so I did have to have the same input. I don’t know any of those identities. Thanks for teaching me, now I know! Wow the tic tac toe method looks useful!

[@JirivandenAssem]

Just go to highschool :)

[@littleretroship6403]

@@JirivandenAssem too young

[@JirivandenAssem]

@@littleretroship6403 wowwww, average ppl get taught funxtions with sinus in the 10th grade!!!

[@TheEc1ypse]

@@JirivandenAssem ya but getting max and mins is gr 12 calc

[@middlemanning]

Ridiculous I have to do this in calculus I mean cmon

[@Greem877]

So we basically have to just differentiate the equation then use those critical points to find out the values on the critical points then we will use the extreme point of intervals to determine which one is the maximum or the minimum