How to find the equation of a normal line (and a tangent)

Learn how to use the derivative to find the equation of a normal line.

[@paulinagarcia4815]

BLESS YOUR SOUL!!!! i take IB math studies and my teacher doesn't do any teaching. the class is pure tests with him assuming that we've learnt everything when I've never seen this in my life. I've spent an hour trying to learn this and i finally clicked on your video and you made it SOOOO easy and understandable!! Thanks!! you saved my grade.

[@easymath_]

Thank you so much for your kind feedback! I'm really stoked this helped you. I'm sorry I haven't uploaded more videos. I need to start back up. Where are you doing the IB (Country)?

[@VijayVijay-ey1ov]

Wast

[@IceCubeD-or2gt]

IB?? im looking at this from IGCSE 🤡

[@L490sr]

mannnn thank you a lot! you explained it clearly and slowly and that is really what I was looking for. much appreciated.

[@fatimabelkacem9821]

Thank you sooooo much. I couldn't understand where the -1/2 part came from. Now it makes so much sense.

[@chaseramos4865]

5:12 for normal line

[@ramidabdoub9472]

Very helpful, thank you so much for this video, I completely forgot how to find a normal equation and needed a refresher, this was just perfectly explained, well-paced, and just my style. You explained everything in every step so I didn't get lost at any point. I take Math SL in IB and I think you should do a lot more videos based on that curricula, it would be so helpful! Thank you again!

[@wz5207]

Thank you so much. Very clear! Step by step, I appreciate!

[@saltysnake3774]

You just made it clear! You're amaizing!

[@mathiasallon8368]

Great helpful tutorials

[@cjalbis2k799]

Thank you to this video. Help me a lot in my math problem 😁💓

[@jonasmwita1837]

Thank you so much for this lecture

Ur too good, thank you Sir.

[@simonpham4750]

absolute legend + bloke

[@lakshmikumarijha8016]

Amazing sir🙏 thanks a lot😀

[@delgadojennifer8]

Love you. This helped meeee a lottt

[@easymath_]

Glad it helped! Let me know if there are any other topics you need further clarity on!

[@coolparrot9432]

Thank you, 2019!

[@tobiaschapinda6771]

A straight line y=-x+4 cuts the parabola with equation y=16-x^2 at the points A and B. a.Find the coordinates of A and B b.Calculate the distance between the points A and B c.Find the equation of the tangents at A and B, and hence determine where the tangents meet. d.At the point where A and B meet, the line Q is perpendicular to the line B. find the equation of the line at Q

[@muhammadmubashir1860]

thank u sir

[@teomarroma4342]

sir. Why you substitute ta x to get the slope 2? It isn't understandable that the slope is the coefficient before x?

[@PlaysDivine]

Isn't it because the slope of the parabola changes depending on x?

[@KM-nx5sh]

fantastically good

[@erickgaray463]

So in order to leave it in general form I must start from the point slope form and move my terms around to leave x positive? Or can I multiply my point slope to get my slope intercept form and then move x to the other side to make it positive? Will it be the same answer or are they different?

[@erickgaray463]

I got my slope intercept form as -1/2x+3/2 then moved it over to get 1/2x+y-3/2 as my final answer in general form...is this correct?

[@erickgaray463]

Nvm just got it oops

[@JB66736]

Thank you so much :)

[@easymath_]

No worries, thanks so much for watching! More vids coming soon!

[@sachinpatial8223]

Y=x^2 isn't it right hand parabola? 😮

[@hypedinertia3115]

really helped 😭

[@muhammadmubashir1860]

plz make a video on vertical line test and also on how to shift it

[@easymath_]

By vertical line test, are you referring to determining whether a relation (or graph) is a function? By "how to shift it", do you want me to show you a general guide for shifting any graph? Do you have any specific types of graphs that you're unsure about?

[@muhammadmubashir1860]

Yes I have but can u make some video's about it?

[@easymath_]

Mubashir Iftikhar of course! I'll try put a video out in the next week and I'll let you know!

[@muhammadmubashir1860]

Thank u so much sir if u did.well then I work for the promotion of your channel

[@easymath_]

Hello my friend, I apologise for the delay for the video! Unexpected events have kept me back! I will nevertheless release that video as soon as I can! Please forgive!

[@tewodrostesfahun9052]

Thanks

[@Juandru17]

What if there are no given points in a word problem? Does that mean its point is at (0,0) ?

[@brittonlemere5486]

Suba Rashi this may be a late reply but; if there's no given point, you're just solving for the equation of the tangent line (aka first derivative of original function), and if asked: the normal line (aka first derivative of original function with inverted slope) By inverted slope I mean if the slope is 2x, your inverse slope is -1/2 x, the constant in front of your variable gets put under 1 and it's sign (positive or negative) is swapped.

[@maisan6234]

is this guy the revision villiage guy

[@ajaymeena1141]

Then man i never understood that in my school

[@jawaharjb3740]

finally understood this shit!!!!

[@xyzpound9905]

Why did you flip the gradient of tangent to get the gradient of normal line??

[@OninabResources]

Since the tangent and the normal are perpendicular to each other, the product of their gradient is negative one. If you know the gradient of tangent, the gradient of the normal is the negative reciprocal of the gradient of the tangent. Get more on equations of tangents and normals to a curve at a given point: The link is kzbin.info/www/bejne/bmLPl6WGpb2nptE

[@itaachiii]

is that vikkstar??

[@charlesbautista3561]

Thanks tobiwan

[@aaronayad8948]

is this the atomi guy?

[@jeddle]

Nope, it's Jonny from 'Ignite HSC' ;) I've been doing English vids lately but am about to shift back to Maths and other subjects!