How to Find the Mole Ratio and Molar Mass

[@hannahpeters9056]

I learned more in nine minutes than I have from my whole semester of chemistry! Thank you

[@mrcausey]

You're welcome. Thank you for watching and commenting.

[@alextodorovic3793]

Thank you my chemistry final is tomorrow and you just saved my grade

[@evangelimanprivate9007]

nice very clear, why can my teacher be this simple.

[@phillyphil700]

taking chemistry in school and have been out of school for at least 20 yrs. the book is blinding difficult to understand as well as the teacher thank you for making it simple. it is much easier to remember how to use for ex. avogadra's theory and finding molar mass. thanks again

[@notoriouspyt07]

you are a chem angel! my teacher skims through because he believes the class are chem majors I need the class to transfer and I've been lost Im barely hanging on with a C! why didn't I find you earlier! Thank you! Its a 3 hour class and I was lost. You explain it really well your voice is calming and encouraging. I actually like that you say "go to the other video" some of the other videos take too long. This was great! thanks again! i definitely subscribed I feel my IQ jumped a few pts hehe

[@gracekcoleman]

Have used your lessons to study for my past two chemistry exams and it's made a world of difference. The textbook can be so dense it's nice to have it broken down and made into simple concepts. Thanks!

[@vecrews]

You are a true blessing. I have not quit because of your video help.

[@bashirabubakar6279]

I find it very interesting, in fact it solved my very long problem in few minutes. Thanks Prof.

[@mrcausey]

You're welcome.

[@megannavarrokennedy6381]

Way better explained than the other videos I've watched, thank you!! Also, has anyone ever told you that you sound just like Marty McFly? lol!

[@mrcausey]

+Megan Navarro Oh yes, many times.

[@PlantFoodChain]

You sir are a genius! In my class we've been studying moles since January and i've been lost ever since then, but thanks to your videos, I was able to peice everything together and I can solve every problem. Thank you so much!

[@maxferracane4791]

Thank you! I have a test tomorrow and I feel so much more confident after watching your video!

[@andisiweziqu416]

Mr.Causey thank you for this video,,,,,I wasn't able to solve problems like these....but now I am,....THANK YOU for your help you've just saved my life

[@mrcausey]

Andisiwe Ziqu You're welcome. Thank you for watching and for the nice comment.

[@mrcausey]

You're welcome. Thank you for the positive feedback.

[@marssnw]

Love your videos. It is so much easier to learn from your videos than my teacher.

[@mrcausey]

You're welcome. Thank you for the feedback!

[@ericpinheiro1275]

you are such an amazing teacher

[@mrcausey]

Thank you so much for the kind words.

[@LizNarayan]

Thank you sooo muchhhh u definetly made this soo much easier!

[@yazeedqudah1548]

I love you man you just saved my life

[@mrcausey]

Thank you for the feedback.

[@cdotz1000]

Dude, you just saved my @$$ for a huge chem test.

[@Enysta98Death]

When my teacher isn't clear, this is where I turn to. Hopefully I'll be able to work the math tomorrow for a quiz (that we were hardly taught), though I fear the math will be longer since it's a four step process going from the mass of one reactant to the mass of another. Thank you for explaining things well, however. c:

[@alyciatiberio3706]

Thank you so much for making these videos. I probably wouldn't be feeling so confident about my chem final tomorrow if I didn't have them.

[@sweepgirl85]

Thank you Mr. Cauaey! These videos are saving me right now. You explain things so clearly 😅

[@mrcausey]

You're welcome! Thanks for taking the time to comment.

[@MrYazid30]

thank you so much for your ways to teach... your video are stimulating compare to others... i'm really appriciate your efforts..

[@jonathan99097]

Thank you. I needed a video like this to show me everything I'm dealing with.

[@ThuanVanNguyen]

Very clearly ! this video useful for me.

[@mrcausey]

+Thuận Nguyễn Văn Thank you.

[@justthegirl9799]

Thank you very much sir. Your video has been helpful in chemistry lessons. Vinaka

[@mrcausey]

+Justthe Girl You're welcome. Thank you for commenting.

[@kulsumkhansla4101]

thnx.......... u make chem sound so cool

[@Bayjore]

ur awesome thank you so much for explaining this so clear and concise cheers mate

[@Locke_Lamora_]

EPIC TUTORIALS. I tried to make tutorials for my personal project but the took so much effort and they weren't that good. So thank you, ?I appropriate all the effort you put in these video's. YOU ARE AMAZING!!! :D

[@Locke_Lamora_]

Ahmed Alsulaimani +Mr. Causey

[@mrcausey]

Ahmed Alsulaimani Thank you so much for the kind words and the feedback. It is greatly appreciated.

[@jessikuur]

DUDE, THANK YOU SO MUCH.

[@LaydeeJyb]

Ive been trying to do this all afternoon, i have a midterm on this tmw and i could not get it down . Thank you so Much !

[@liamfairbrass4719]

Great video. It helped alot. Thanks!

[@aasiyahusain5690]

Thank you so much!! It was so helpful ^.^

[@SuperGamecheck]

Thank you for this video. It's awesome !

[@themsmeme93]

i have a chem question,hoping u could answer it? 1) mercury and bromide will react with each other to produce mercury(II)bromide hg(l)+br2(l)------hgbr2(s). what mass of hgbr2 is produced from the reaction of 10.0g hg and 10.0g br2? what mass of the reagent is left unreacted? What mass of hgbr2 is produced from the reaction of 5.00ml of mercury (density+13.5g/mL)and 5.00ml of bromine (density=3.12g/mL)

[@mrcausey]

Since the problem gives you moles to moles and a balanced equation you don't need grams. Use the mole ratio 1 mol C3H4 to 3 mol CO2 to convert. So, z mol C3H4 x 3 mol CO2/1 mol C3H4 = 3z mol CO2

[@mrcausey]

You are welcome. Thank you for the comment.

[@mrcausey]

You are welcome!

[@mrcausey]

@themsmeme93 I will use this problem for the Problem of the Week keep an eye out for it.

[@PvcAnonymous13]

I love this man

[@JJ-fq1ek]

You are the absolute boy thanks

[@ammarahmed5474]

everyone in my class has to go to institutes and use so much time and money when im sitting at home learning so much! thanks

[@mrcausey]

+AMMAR AHMED Thank you for watching and commenting.

[@roman20353]

+AMMAR AHMED I have a friend called Ammar Ahmed

[@dinganizulu3268]

Why do average atomic Masses of elements on the periodic table written With no units?

[@mrcausey]

Great question. Atomic masses were originally determined through a mathematical relationship based on the known ratio between carbon and hydrogen. In the mid-1800s scientists couldn't directly mass atoms but realized the need for an atomic mass unit. So, using Avogadro's gas law they were able to find a ratio between carbon and hydrogen (1:12). This lead to the definition of an amu as the mass of 1/12 of a carbon atom. Because a ratio was used the units can either be atomic mas units or grams (molar mass). H = 1.01 atomic mass units or H = 1.01 grams

[@anarahimi4948]

great video. thank you

[@damasake]

how do i know which ones to put on top and below

[@mrcausey]

You use unit analysis. kzbin.info/www/bejne/jpOxqp-tmqxnba8

[@justaprankbro]

Is there a simple formula that shows how to convert moles to grams and grams to moles...etc? btw great vid and subscribed!

[@sweatersnug]

you sound like Jeff Fisher from American dad XD you're a very teacher thank you :)

[@Mister6Dem]

thanks for the help

[@icemadrid1017]

Thank You so much for this great video!! :D

[@bdongeorge1]

Thank You! Without this i would fail chemistry!

[@kestonsmith1354]

thank you!! you're a genius!

[@theShelbylaw]

you should link your other videos in this

[@mrcausey]

Not really! There are no short cuts to learning chemistry correctly. The process is use molar mass to change grams to moles or moles to grams; use mole ratio to change moles of A to moles of B or moles B to moles A; use Avogadro's number to change moles to particles or particles to moles.

[@themsmeme93]

@mrcausey how do u calculate the 3.50x(6.022 23) i dont know,i am bad at math thanks to you i may not be failing chem.. THANKS ALOT.

[@MixiBerri]

I have a chemistry test tomorrow, thanks

[@mrcausey]

Good Luck!

[@mrcausey]

@themsmeme93 you need to use your calculator. 3.5 * 6.022 E 23

[@thebookwormdiaries]

Thanks so much! :))))

[@chanellee9762]

does an equation need to be balanced before you can figure out the ratio?

[@mrcausey]

Can't put everything in one video and the material here depends on other material. There over 70 videos available for use.

[@myhomeasia4276]

Thank u👍

[@lonniekelly8212]

How come it looks so easy when you do it? LOL wish you were my teacher!

[@1339hesam]

thanks

[@pakistanf1]

hey. what about mass to mass ratio and mass to particle ratio

[@Thisabadusername]

thank u

[@hajaralmansouri2703]

when i culculat the moler mass for H2O (2*1.0097)+15.999=18.0148 ~= 18.01 not 18.02 is that right?

[@mrcausey]

Check out some of the videos in the description.

[@myhomeasia4276]

So simple . It's like neck slice

[@themsmeme93]

how do you calculate the 3.50x(6.022x10 23) i am clueless.

[@mrcausey]

No, you didn't round off correctly. the answer would be 18.0184 which would round to 18.02. The 8 would round the 1 to a 2.

[@mrmonkeyboy122]

How do you do moles to grams?

[@mrcausey]

Check out the videos of specific problems worked out. I call them Homework Helpers.

[@bb-tm8hs]

thx

[@mrcausey]

[@arishaartistic5400]

thank god a proper video. everything else is ppl writing on white boards -_-

[@mrcausey]

Check out links in the description.

[@RyanPeslak]

Even after watching these I have no clue. My teacher does not know how to teach and she admitted it herself. Theres about 4 students that actually know this stuff and she just keeps going ahead and no one gets anything anymore. I dont know what to do anymore, and the semester is about to end and I have a 49...

[@roman20353]

does 3.50 mol mean the same thing as 3 moles? Please help.. thanks!

[@mrcausey]

+ROMAN HANG LIMBU No. But, if you do get fractions multiply by a factor that will result in an integer.

[@muskanshrivastav5359]

sir plz help me for this que..a mixture contains 0.2g of oxygen gas and 0.4g of carbon dioxide gas.so the ratio of oxygen atom present in oxygen gas to that in carbon dioxide gas is......... sir plz send me the answer

[@mrcausey]

Determine the moles of oxygen and the moles of carbon dioxide then determine the atoms in each sample.

[@muskanshrivastav5359]

Mr. Causey thankyou sir

[@sydnibates3858]

Should I watch this video first, or balancing a mole first..

[@mackthemark9105]

Okay, here's a follow-up question: if you know you have one mole of NaCl, how many moles would you have of Na and how many of Cl?

[@mrcausey]

One mole Na and one mole of Cl. The formula unit is the simplest ratio of the ionic compound.

[@dialasaab972]

i dont get it , for mole in grams . first you put the mole divide by 1 then in B you put 1 divide by the mole. why?

[@mrcausey]

When changing moles to grams you use the molar mass so the moles cancel out and in grams to moles you have to flip it so grams cancel out. They are two different situations using the molar mass. You might want to check out the "How to Use Moles" video in the description. There other videos listed that might help also.

[@dialasaab972]

oh yeah i just got it and your video was very helpful thank you so much .

[@mrcausey]

diala Saab You're welcome. Thanks for watching.

[@fbiuzz]

How the hell do you know when to round off to?

[@safaafathallah5747]

Ahh I love you ♥♥

[@iDiceKingkaiserzap]

cool

[@spartan117lego]

"And that's like magic" :D

[@KatrinaKrystal]

Avogadros number= 6.02x10^23

[@christianf4017]

lol i have an exam tomorrow and im dead

[@mrcausey]

Well, actually that is rounded off.

[@PhDeeznutz]

3 words "saved my ass"

[@themassreviewer]

Mr.Causey Im Dieing In Chem I Understand Nothing Theres no Hope :(

[@jessicadelrosario5388]

You should go slower to allow us to type in the answer to the calculator and follow along

[@mrcausey]

+Jessica del rosario Don't forget there is a "pause" button. Thanks for watching and taking the time to comment.

[@LindaGUlm]

You're able to eliminate your moles permanently from home, without having leaving scars

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You could click here to check out the remedy: great7.net/get-smooth-skin

[@SwiftSkill1]

Linda G. Ulm 😂😂😂😂😂

[@audriefox6296]

Toooo the board

[@Junaid786Shadpur]

Lol I understood nothing. If anything, I'm more confused than before

[@emilylushbaugh7098]

same same same

[@warsfa]

right? he doesn't seem to explain, but just does it

[@mrcausey]

It's not an explanation. It's a how to. If you don't understand it you are missing information that you need to gather. Check out this video on the mole kzbin.info/www/bejne/r3rad6R_qZiBh9E

[@rynklly05]

FINALS

[@OscarTangableVII]

good videos but need to stop referring to other videos!

[@joshuapamintuan6086]

I"M HERE BECAUSE OF FINALS... HOW ABOUT YOU? xD

[@rickmangarrett77]

This shit gets off the screen too quickly to even write god damn.

[@mrcausey]

+Garrett Rickman Use the pause and play functions!

[@rickmangarrett77]

+Mr. Causey you right my nigga. My bad.

[@emilylushbaugh7098]

this is not in the least bit helpful

[@mrcausey]

I'm sorry. Maybe you were looking for something else?

[@Jolt3d]

Don't worry, it was very helpful to me.

[@mrcausey]

Thank you so much!

[@mrcausey]

Well, actually that is rounded off.