How to Light up 3v LED with 220v Power using Diode 1N4007 and 100k Resistor

How to Light up 3v LED with 220v Power using Diode 1N4007 and 100k Resistor
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How to Light up 3v LED with 220v Power using Diode 1N4007 and 100k Resistor
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[@isuriwijesekare8316]

This is dengerous

[@leo55_10]

sim... tome cuidado my friend

[@pcyl254]

All of electricity part is dangerous if not to be carefull

[@ramsuro]

220v. Можно просто взять один диод 1n4007 с одной стороны, резистор 0.5w 42k или 47k (до 100k) с другой и светодиод (led white или blue) посредине с соблюдением полярности, работает нормально. Для 110-127v попробуйте 39k (42k) если светит слабо уменьшайте до 27k - 22k, лучше 1w. Резистор греется немного и его вообще можно заменить на конденсатор 400-600v 100n-440n (начинайте пробовать с меньшего номинала) и паралельнот C включите R от 100k до 2 MOhm для разряда C после вынимания из розетки. Паралельно светодиоду иногда включают стабилитрон 0.5 - 1w 3.7-12v (выводы не обрезайте, это улучшит его температурный режим) и электролитический конденсатор 16v 0.1 - 47 uF, чтобы убрать мерцание, но это вовсе не обезательно.

[@mercedesm.7851]

Ваш комментарий и ваша информация действительно кажутся очень интересными, но мне пришлось использовать Google Translate, и я думаю, что заблудился, чтобы подписаться на вас. Не могли бы вы дать объяснение на английском языке? Спасибо и с уважением

[@ramsuro]

@@mercedesm.7851 What part of my comment exactly interested you?

[@chamindanissanka1378]

It's true. believe it. i did it.other KZbin channel is lying.thanks sir 👍👍👍👍👍👍

[@ninomandal181]

It can run all night or the LED burns?

[@mercedesm.7851]

Thanks for your video. I can see that, instead of just using a diode on one pole and a resistor on the other, you are adding a second diode before the resistor, and I would like to know why. Are you doing this to improve the alternating to continuous conversion with better filtering? Greetings

[@ramsuro]

One diode 1n4007 (700v-1000v) or 1n4004 (400v) is enough there, two need to be installed 1n4003 (200v)

[@ramanand3424]

do we really need 2 diodes? i made using single diodes and is working fine

[@EvoPortal]

There is no need for two diodes, the guy that posted the video does not understanding what diodes even are.

[@francislopes7741]

Very nice Vedio

[@baidaraka]

Angrezi pa pukhto kay. da Ochat sata, KEEP IT UP.

[@sanjaypal4678]

Very nice video sir.

[@jjj0nathan]

what is watt of resistor, my resistor is heating like oven,

[@prakashsuryawanshi6211]

Welcome India

[@SupremeRepairs]

Great job sir 😍🙏

[@EziCircuits]

Thanks a lot friend.

[@briancuares7264]

goodjob sir

[@tribudi8377]

Nice video..

[@ronicosta1979]

Very good

[@EziCircuits]

Thanks friend.

[@thekkekarachannel380]

Good.

[@practicallab]

good

[@arunavabanerjee1315]

Please tell Resistance watt.

[@helli3088]

Better use 2 resistors or use a condensator as well otherwise the resistor taket over 0,5w and gets really hot.

[@munnagreen747]

Kot pis 3 volt lait lagano jabe

[@zoeychen6284]

this tutorial can light up 10 or more than 3volts led lights? using 2 diode and 1 pc of 100k resistor

[@RixtronixLAB]

Nice video, thanks for sharing :)

[@samanthaxiakate9803]

what if i want 20LED in series what will i use? can i sue the same value of diode?

[@viciriucandreea5835]

Ok felicitari

[@santoshpradhan9513]

Sir if I use 1watt resistor then it will glow or not.

[@greenleavesfree971]

Sir resistance value 100 k. 1/2 watt

[@Neha2003-m5b]

Yes

[@MrMoromette]

LED picture from the left that you show as a model starting from min.0,51 up to 2,51 is wrongly connected. On the right side the animation shows that you connect the LED correctly. Try to chenge the pic or announce it!

[@m.i.mohamedirzhad1101]

This mathode working mcb indicater light ?

[@MMaheshThakur]

Just put one 120k ohm resistor . No need of a diode. Led is itself a diode

[@EziCircuits]

Hahaha Very good friend.

[@omweng6163]

just put 120k ohm and small bulb no need diode

[@ramsuro]

will live longer with a diode

[@sureshravidas5875]

Resistance Ka watt Kitna h?

[@kitpro1160]

👍🏻👍🏻👍🏻

[@Devendradixit125]

डाई वोड केसे लगाना उल्टे के सीधे

[@nzhossain809]

Can i use 4 blue colour series led in this process.?

[@ramsuro]

R = 42k

[@hiralalbatwal3437]

Sir I want resistance value ...? Used 3 volt led in 220 volts with diode in4007

[@ramsuro]

100k-120k best

[@JAGADEESH_M]

What the voltage across led? could you measure it because i need it for another application..

[@s.s2567]

You must use the Ohms' Law

[@leo55_10]

usar 2 diodos 1N4007, a meu ver não vale a pena nesse circuito.

[@dr.robertbennett8951]

Your small 1/4 watt resistor will BURN UP...must use larger..preferably 1 watt

[@1960MAILO]

ok😁

[@prakashsuryawanshi6211]

Why used 2 Diodes

[@ramsuro]

1n4007 - 1, 1n4003 - 2pcs

[@debojitacharjee]

Formula for LED resistor is R = (Supply voltage - LED voltage) / LED ampere. So, R = (220-2)/0.02 = 11k but when I connect 11k with glass type transparent LED then it fuses after sometime. Why?

[@manmeetandroid]

Try 180k register or 220k register, its fuses due to low register value.

[@debojitacharjee]

@@manmeetandroid No even higher resistor fails. The main reason is power factor of LED as they are capacitive load. Using a diode resolves tge problem.

[@manmeetandroid]

@@debojitacharjee Actually LED is one kind of diode only material used for making those are phosphorus, but due to excess heat it fuses you can create more stable circuit using addition of 2 diode (which will make half rectifier) in unidirectional way,( R-D-LED-D).

[@debojitacharjee]

@@manmeetandroid not necessary, additikn of only one diode in series will protect the led. Led is a diode but cannot be used as a diode because it has high resistance and when used in parallel (as a load) with AC, works as a capasitive resistance because it's made from PN/NP type semiconductor. Any capacitive load on AC will cause a negative phase shift which will give a -ve power factor value. So the formula P=IV*PF will be applicable and if we use a resistor R with the led then the value of R will be R=(V^2)*PF/P but without knowing the PF we won't able to find the value of R for the led. If we use a diode then the AC will become pulsing DC but not AC, so the led won't behave like a capacitive load. Then the value of PF will become 1, and we can easily calculate the value of R and that will protect the led also.

[@poonchau5389]

1. Voltage sometime up to 240volt 2.you have to calculate watt if the resistor Sorry my English

[@Abuhamza7890]

how to run multiple LEDs 4-8 in numbers on DC 3 volt?

[@adityabarman874]

You have to connect one capacitor which is 50v, 100uf

[@A.p.s.random]

Is thishis LED light DC or AC?

[@snse5407]

DC

[@ashokgouda2850]

Diode Kyu lagaya he

[@PatambagniMaamCathyYTChanel]

Can I use 330k ohms resistor?

[@ramsuro]

dark light

[@elsever.operator]

👏👏

[@EziCircuits]

Thanks friend.

[@erwinconxepts]

you dont need a diode because led itself is a diode 😂

[@Usernamei6549]

Big brain......

[@SinhalaWeightLossGuru]

Then plug 🔌 it direct to ac you will see the fireworks 🎆🎇 🙈🤣🤣

[@ramsuro]

One diode need 1n4007 (700v-1000v) or 1n4004 (400v), two need to be installed 1n4003 (200v)

[@li-cg]

Ông nói chuẩn quá😂

[@solidname9085]

why u use 1N4007 diode?

[@ramsuro]

700-1000v

[@robertzajacek1350]

@@ramsuro Yes, and most important, the diode protects the LED in reverse polarity.

[@creativitystudio4380]

I used this same circuit and the led got burnt

[@s.s2567]

Did you use the Ohms'Law? Beware the current AC!

[@nizarbreiche123]

👍

[@bluestarcomponentes9927]

resitor for youu squebay

[@mikelunsford2587]

Where you find a lighter. No body smokes here .

[@LHJARS]

you need only one diode

[@snse5407]

4 diode in Bridge for better result.

[@apdulmatemsk2191]

English TV series hot

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