How To Make a Voltage Regulator Circuit Using Zener Diodes & SuperCapacitors

This electronics video tutorial explains how to make a voltage regulator circuit using zener diodes and supercapacitors.
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[@razabazal4669]

In this video were gonna talk about everything your professors failed to talk about and were also gonna go over how without me your lives would be so much more difficult. Thanks so much again for all you do.

[@Haristiro]

I love this guy as he is my family

[@kabandajamir9844]

The world's best teacher

[@jamesdepaul3410]

Very logical explanation

[@josianemartinez6062]

Note that your discharge path does not have any resistor (aside from the Cap's ESR and the dynamic resistance of the zener). Therefore the discharge time would be much faster than the charge time. You should add a resistor in series with the caps to get more stability in the case of downward voltage spikes.

[@thembinkosimbonambi1921]

You are great Broh

[@nyunai298]

When i listen i feel like i'm becoming an engineer

[@kabandajamir9844]

Please l have a problem of amplify ing a clap switch it's sensitivity is to low please help the world's best teacher

[@successthruknowledge]

I'm sorry but I can't understand how he determined the voltage at the point in the wire above the zener diode. That would mean that the voltage drop across the resistor is 0.3V does it not? When I created this circuit in the iCircuit app for macOS then I don't see the same numbers. Also, I'm confused. I thought current could not flow across a zener diode in reverse if the voltage was lower than 3.3 at the point before the zener diode.

[@nayr6161]

Big fan

[@ARMYStrongHOOAH17]

I wonder if you could hook another 1k resistor in parallel with the resistor but through a switch so while the switch is engaged the net resistance is 500Ω, allowing the capacitors to charge quicker. As the caps get close to 3.3v you could disengage the switch, removing the extra resistor from the circuit to maintain voltage stability. What are y'all's thoughts?

[@Frisso92_]

Yes, you could also connect the capacitors directly to the battery or your energy source and the charging would be faster indeed. The only problem of using smaller resistance is that the diodes don't support much current

[@ikbalalraiksu1030]

What happen if diode zener kept on opposite direction in the circuit, thank for axplanation

[@BraulyoGaming]

I want this with 24 volt input and 20 voltage out put.

[@WebSpyderCode]

Don't forget the load impedance.

[@almac4520]

Absolutely. Unless this circuit just delivers a reference voltage to a input with high impedance, the load will drain these super caps down. If this is a heavy load the circuit will not regulate very well.

[@spacepirateivynova]

wouldn't 2 10f caps in series like that act like a smaller cap... say 5f? as if the dielectric layer was thicker between the conductive layers? From what I understood it was when they are in series that you get a higher capacitance, at the same voltage... wait, no, now i see why they are in series, to get a higher voltage rating out of single lower voltage super caps... i would have used a single 10F say 5 volt super cap (I don't know how they are set up voltage wise, i'm still learning about supercaps in general... PULSE caps, now that's my thing.)

[@stark_energy]

Placing same capacitors in series increase voltage rating BUT the capacity will be the same. Capacitors behave exactly the same as battery with respect to series / parallel configuration.

[@ceciliaaguilar1001]

how is he calculating the vout for a given vb?

[@NotMarkKnopfler]

I've studied a lot of these circuits and they all seem to be the same: They all have the resistor in line with the positive output terminal. This seems inefficient to me: you are always 'burning' current through the resistor, even if the Zener is not conducting. Why not have the resistor beneath the Zener diode, so that when the diode 'opens' the resistor limits the current that the Zener is having to pass and only drops the excess voltage across it? Have I misunderstood something? Thanks.

[@niloyabid2851]

There seems to be a misunderstanding. The thing with the resistor is that without any resistance the current would burn the wire, so the resistor regulates the current. As for placing it below, you can imagine it like a line of people walking after one another in a loop, even if the resistor is placed below, the "people" will movr through the loop simultaneously.

[@briansbrian771]

who are you???, how do u teach everything???

[@davidsai]

i need a 6 votl ouput a 7.4 volts imput and load current of 500 mamps how do i do thanks

[@johnsun2416]

Why bother with these but instead use LM317T or L780 series voltage regulator.