How to move Zeroes to end of an Array? | Animation

[@itsdineshvaryani]

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[@shubhamagarwal1434]

Best series for DS & Algo. I am also 10 yrs java exp guy. Was looking for DS & Algo free course over KZbin with java implementation and found this. Hats Off To You Man....Excellent Work. GOD BLESS YOU :)

[@itsdineshvaryani]

Thanks !!!

[@ritamdas_ju]

same comment in every video🙄🙄

[@ALJ_8840]

package BASICS; public class array5 { public static void main(String[] args) { // TODO Auto-generated method stub int [] array= {0,0,1,2,1,2,0,1,1,8,5,0,0,0,9,0,0,0,-9,100}; int [] array1=new int[array.length]; for(int i=0,j=0;i

[@harshvardhansingh5647]

😮 Very good .Well done .Respect for you.

[@itsdineshvaryani]

Thanks

[@achiever27]

Amazing explanation with really awesome animated content

[@itsdineshvaryani]

Thanks !!!

[@shibaramsathua6683]

could you explain the actual algorithm before showing the exact code to do the problem , it is not an effective way to understand form the answer to question , actually we have to explain how the answer comes out from the question , and differnet way to solve it.. By the way you are a great teahcer and learning from you is valuable to me.

[@someshsahu4638]

Very nice explanation sir thankyou 🙏🏼🙏🏼🙏🏼

[@itsdineshvaryani]

Welcome

[@venkatramreddysomala14900]

Best explanation, Thank you

[@itsdineshvaryani]

Glad you liked it !!!

[@pawankumar-li9ib]

Great vedeo sir 👍ur teaching style is totally amazing 🙏

[@itsdineshvaryani]

Thanks !!!

[@StoicX7]

Sir please Upload A Video about How To Build Our Own Logic To Solve DS&algo Problems

[@itsdineshvaryani]

Will add !!!

[@karentechnologies3990]

Here's another algorithm to achieve the same goal : public int[] shiftZerosToEnd(int[] numbers){ int[] result = new int[numbers.length]; int position = 0; for (int val : numbers){ if (val != 0){ result[position] = val; position++; } } return result; }

[@wizardop2100]

Thanks 🙏🏻

[@AvionInn]

it does not work for {0,0,2,3,4,0,0} this array

[@AvionInn]

sorry it worked , my bad

[@shubhamagarwal1434]

Comparing: 1. Both have same time complexity O(n) 2. Space taken by your algo is more as it requres an extra array.

[@LuizFelipe-ow2gf]

i think this algorithm is better because it doesn't access and return a reference to the numbers array, correct me if i'm wrong

[@nafishasantonmoy2272]

I have taken two pointers approach for this problem- static int[] moveZeroesToEnd(int[] array){ //two pointers approach int start = 0; int end = array.length-1; while(start < end){ if(array[end] == 0){ end--; continue; } if(array[start] == 0){ int temp = array[end]; array[end--] = array[start]; array[start] = temp; } start++; } return array; }

[@lordstark6927]

Simply awesome👏

[@itsdineshvaryani]

Thanks !!!

[@dineshkm7832]

This one is more complet time and memory .. for (int i = 0; i < nums.length; i++) { if (nums[i] != 0) { nums[nonZeroIndex++] = nums[i]; } } // see while below then add 0 at end to match array size // Fill the remaining elements with zeroes while (nonZeroIndex < nums.length) { nums[nonZeroIndex++] = 0; }

[@DILIPKUMAR-qc8zw]

Great explanation...Thanks a lot

[@itsdineshvaryani]

Welcome !!!

[@chinniachari]

Another simple way of doing it, private static void zerosAtLast(int arr[]){ int zeroIndex = arr.length-1; for (int i = 0; i < zeroIndex; i++) { //No need to iterate till arr.length if (arr[i] == 0){ arr[i] = arr[zeroIndex]; arr[zeroIndex--] = 0; while (arr[zeroIndex]==0 && i > zeroIndex){ zeroIndex--; } } } System.out.print("Zeros at last = "); for (int i = 0; i < arr.length; i++) { System.out.print(" - "+arr[i]); } }

[@prabhu5569]

Sir The logic you said for reversing the array won't work for this problem?

[@MohdDanish-kv8ry]

can you please tell me about the time complexity of the given algorithm?

[@itsdineshvaryani]

O(n)

[@abhishekranjan1094]

Very nice sir

[@itsdineshvaryani]

Welcome !!!

[@swapniljagatap3533]

Thanks 👍👍👍👍

[@itsdineshvaryani]

welcome !!!

[@SOUALMIABDENNOUR]

good amazing algo but you can use another way to swap without using temp arr[ j ] =arr [ i ]; arr[ i ] =0 ;

[@NFM-nb7dl]

💙

[@itsdineshvaryani]

thanks !!!

[@harshsinha6067]

this solution will not work for this input {1, 2, 0, 0, 0, 3, 6}; please check

[@ahmetyasarozer]

Nope my friend, it works. I've tested just now.

[@saidbifalankeep]

it's work

[@siva-m2t7o]

Code not visible

[@pavanrajp4633]

👍

[@harshsinha6067]

please try this solution instead public static int[] movetoEnd(int arr[]) { int j=0; for(int i=0;i

[@chaitanyasingh8620]

👍👍👍👍🏻

[@itsdineshvaryani]

Thanks !!!

[@themesiah8429]

I am able to think of this algo better but seems lengthy. I wonder if it impacts time-complexity much. Is it greedy? loop over j looking for a zero - if j finds zero, loop i from (j+1) till end of array -- Case 1: if i finds a non-zero number, swap and break out of i loop -- Case 2: if i reaches end of array, no non-zero number was found for swap and array can be returned. Thoughts? public int[] function(int[] arr) { for (int j = 0; j < arr.length; j++) { if (arr[j] == 0) { for (int i = j + 1; i < arr.length; i++) { if (arr[i] != 0) { int temp = arr[i]; arr[i] = arr[j]; arr[j] = temp; break; } if(i == (arr.length - 1)){ return arr; } } } } return arr; }

[@vamshiraj7097]

You are the just explaining the solution, but you are not explaining how you come up with that solution.We have to learn how to approach to solve a problem not just merly understand the solution. I really appreciate your work but this is my opinion.

[@beanneverseengaming3915]

import java.util.Arrays; public class MoveZerosAtEnd { public static void main(String[] args) { int arr[]={5,0,0,2,3,6}; newArr(arr); System.out.println(Arrays.toString(arr)); } static int[] newArr(int[] arr){ int end=arr.length-1; for (int i = 0; i

[@jkrollin9768]

it swaps zero at the end with zero in beginning

[@siva-m2t7o]

Jaffa nupetni vedio focus gavinalani but artham kakunte code chudalani but title vesi

[@siva-m2t7o]

Title vesi moddagudipiccha

[@prajwal.gadakh]

Why you haven't used, if and else if ? Why you used if, if ?????

[@saidbifalankeep]

because which write else if the logic will be like this(the consition if is true the else if won't be execute because if was true but made if,if that meanse check first-> if is true perform it and check also the second if -> if is true will be perform it that's different i hope you understand it

[@prajwal.gadakh]

@@saidbifalankeep yeah got it, thank you so much.