How to Optimize the Viewing Angle Using Calculus | Math Application

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Learn Math By Doing

Learn Math By Doing

Күн бұрын

Пікірлер: 14
@Alceste_
@Alceste_ 18 күн бұрын
Interesting how close yet different the intuitive answer of 50ft is from the analytic result.
@learnmathbydoing
@learnmathbydoing 18 күн бұрын
That's a great observation!
@diatribeeverything
@diatribeeverything 17 күн бұрын
Just discovered your channel. Great stuff! Keep it up. Subbbed.
@learnmathbydoing
@learnmathbydoing 17 күн бұрын
Awesome, thank you!
@unebonnevie
@unebonnevie 20 күн бұрын
Nice. Two application points mentioned in the vid. 1) To maximize something, take the 1st derivative. 2) The critical point of the derivative (equation) is zero to find the maximum value of the interested variable, the angle theta in this case.
@5729ariel
@5729ariel 19 күн бұрын
Great video!
@learnmathbydoing
@learnmathbydoing 18 күн бұрын
Thanks!
@vinodvenkatesan
@vinodvenkatesan 20 күн бұрын
What tool do you use for your animations? Thanks
@learnmathbydoing
@learnmathbydoing 20 күн бұрын
Just PowerPoint. The secret to create movement is the morph transition. Create (duplicate) two slides, and create some changes in the second slide. When you run those two slides with morph transitions, any changes from the first slide to the second slide will appear a motion, so with that as the idea, you can create the animation you want fairly easily. Here is how I usually do the animation. How to Animate Math Equations #math kzbin.info/www/bejne/iZCoqmN3gMmtnK8
@vinodvenkatesan
@vinodvenkatesan 19 күн бұрын
@learnmathbydoing Thank you for the detailed explanation.
@mnek742
@mnek742 20 күн бұрын
Nice problem! One can also use theta = tan^-1(x/45)-tan^-1(x/55)
@DanChereches-e8q
@DanChereches-e8q 19 күн бұрын
Nice idea for a problem However that calculation looks unnecessary to me. If T=55/x and B=45/x the tangents of top and bottom angles then by angle difference formula for tangent tan(theta)=Tan(top_angle-bot_angle)=(T-B)/(1+TB)=10x/(x^2+9*11*25) that is 55 or 45 but i just factored it out this thing is much nicer to differentiate and knowing the functions is uniformly increasing the min/max will not be changed. tan'(theta)=(10*(x^2+9*11*25)-10x*2x)/(x^2+9*11*25)^2=(10*45*55-10x^2)/(x^2+9*11*25)^2 so we got the extrema points of x=+-15sqrt(11) I don't think the difference is major but i just didn't feel like working with the arctangent lol
@michetix7885
@michetix7885 19 күн бұрын
Well that small guy could solve it by walking
@cradleofrelaxation6473
@cradleofrelaxation6473 18 күн бұрын
And I calculate this critical angle in my head when watching live performance. Ama phoking genius!!
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