How To Solve HackerRank Drawing Book Problem

[@JavaAidTutorials]

Hello Coding Lover, If you have any doubts or any better approach to solve this problem, let me know in comments.

[@tazzyreign2629]

Love the solution!

[@noibiolamilekan3501]

The best solution so far! You are too good

[@kishlayamourya3141]

You made the question looks so easy...nice explanation.

[@JavaAidTutorials]

thank you. 🙂

[@SaumyaSharma007]

thanks a lot, SIR..............that was very helpful.

[@JavaAidTutorials]

Most welcome!

[@shubhamtiwari5297]

Simple, Understandable Logic Great work New Subscriber Cheers

[@jordenparker6454]

Thank you so much for this, man! Your explanation really helped me out. :)

[@JavaAidTutorials]

Thanks, Jorden for your feedback. keep watching and keep commenting..:) It motivates me to do more for you all..

[@prijaymaharjan]

Thank you clear all doubt in Draw Book Solution Algorthm

[@JavaAidTutorials]

You are most welcome

[@mkriiger]

Simple and elegant solution, nice!

[@JavaAidTutorials]

Thank you! Cheers!

[@atiqshaikh6010]

what if count starts from 1 which will be on the left side of the page 1,2 --- 3,4 ----- 5,6 (like this) i think n/2 wont work in this case

[@GauravKumar-ux1os]

Brilliant sir!

[@smartcoder1112]

perfect tutorials for the beginner (Y). You Rocked bro...!!!

[@JavaAidTutorials]

Thanks buddy..

[@vinayabhat4826]

thank you !! It helped me a lot!!

[@pramodbasu7732]

Great Explanation !!

[@pramodbasu7732]

grate Explanation !!!

[@shubhamsagar9153]

thanks mate your videos are helping me a lot since I am net to competetive coding. but can i ask you what to do when you r stuck on a question for days and logic does not click its very frustrating.

[@JavaAidTutorials]

i hope my quora answer will cover this- www.quora.com/Is-not-being-able-to-solve-HackerRank-problems-for-a-beginner-normal/answer/Kanahaiya-Gupta-2

[@amanrai8010]

I have watched your video it was really easy to understand and was really efficient. Thanks for sharing

[@JavaAidTutorials]

Thanks Aman for your compliment..

[@RobertShane]

I thought there was a way of doing it where you could only calculate from the front and then subtract off something to get from the back but I couldn't figure it out. Thanks.

[@gokulnaathb2627]

Thank you for the explanation, Sir :)

[@codear2519]

good video thank you

[@soham_narang4487]

what if n=12 it gives a different output for p=8 and p=9, but instead, it should be the same

[@mrinmoyhalder7293]

I think we have to take floor value always

[@JavaAidTutorials]

In java 8/2 and 9/2 both are equal to 4. So answer will be same for both. If you are using some other language check if division works in the same way or else take floor value as mentioned in above comment.

[@ManojKumar-hu6uk]

very good explanation.

[@JavaAidTutorials]

Thanks, Manoj for your compliment..!!

[@mdabidiqbal1153]

Thank you so much

[@JavaAidTutorials]

Most welcome..

[@anilappana8833]

Good logic

[@JavaAidTutorials]

thank you..!1

[@djamelnm7740]

Thank you very much

[@JavaAidTutorials]

Welcome 😊

[@soumyat4861]

N/2 is understood as each flip has 2 pages but why we assigned target pagecount from front as p/2? Can you please explain

[@lostt3435]

even from the front if u wanna go to target page it will require p/2 turns, as p here is target page.Simply like we do in maths we have just put the value of p in n/2

[@khii_khii]

best one

[@rohanshrivastav1382]

thank you bro

[@JavaAidTutorials]

welcome bro.. thanks for watching..!!

[@biswadeepchakraborty5354]

Thank you so much. I want to learn Dynamic programming. Could you please help

[@JavaAidTutorials]

welcome @Biswadeep. Sure will make a tutorial on dynamic programming soon. stay tuned.

[@arjunseth5836]

@@JavaAidTutorials Is tutorials on DP there? I couldn't find any..

[@i_am_kshitij1118]

if n=10 and p=7 then from right to left we require 2 turns but from the formula we are getting (10-7)/2=3/2=1 what is wrong here should i put another condition that if n==even and p==odd then turns from end is equal to (n-p)/2 +1

[@JavaAidTutorials]

int totalPageTurnCountFromFront = 10 / 2 =5; int targetPageTurnCountFromFront = 7 / 2 =3; int targetPageTurnCountFromBack = totalPageTurnCountFromFront - targetPageTurnCountFromFront; targetPageTurnCountFromBack=5-3=2 return Math.min(3, 2); answer 2 hope , it will hellp.

[@mruduladdipalli5417]

Great!

[@JavaAidTutorials]

Thanks Mrudul..

[@anuragtiwari3032]

Great explanation bro but can u please help explain the editorial answer of this problem as their is some left right shifting involved which im unable to understand.i know how the shifts work but I'm unable to understand the logic behind it

[@JavaAidTutorials]

Thanks @Anurag. Lets take this sample input- n=7 p=4 graphical view of book will look something like this- [ ,1][2,3][4,5][6,7] every interval bracket[x,y] represent the book with x page on left and y page on right. They are calculating no. of turns from right to left (from last) If n is odd, then she turns(n-p)/2 pages. because if n is odd it means total page either be 1 or 3 or 5 ...any odd number and page 1 is always fix. so if you subtract one from odd number it will become even and every page contains 2 pages. so we can divide it by 2 now. so it will be p/2. if you go from left to right or (n-p)/2 if you will go right to left(they used right to left strategy). If n is even, then she turns (n-p+1)/2 pages.because if n is even and 1 page place is fixed then we are left with an odd number. ex- [ ,1][2,3][4,5][6,7][8, ] in this example after leaving 1 page we left with 7 page and if divide 7/2 it will integer division so it will result 3(instead of 3.5 because there are one more page left) turns which include only 6 pages as per page 2 page number.so while considering from right to left you need to add 1 into the above formula. (n-p+1)/2 I hope. you got the idea.

[@anuragtiwari3032]

@@JavaAidTutorials thanx a lot man for this explanation. yeah I got the idea. May god bless u :)

[@JavaAidTutorials]

@@anuragtiwari3032 most welcome..:)

[@mrinmoyhalder7293]

How did u clicked this logic by seeing this problem 1st time ??

[@JavaAidTutorials]

Frankly speaking, This was not the first problem for me, I have solved this kind of problems, thats why i knew this.😊 I hope now you know this trick and will be able to apply on your similar future problems.

[@anujgupta7749]

@@JavaAidTutorials Thank you sir.

[@IamDemotivated]

🙏🙏🙏🙏🙏🙏

[@devanshsrivastava4265]

import java.util.Scanner; class Solution{ public static void main(String[] args) { Scanner Scan = new Scanner(System.in); int total = Scan.nextInt(); int pagee =Scan.nextInt(); if(total%2==0) { total++; } int div=pagee/2; int div_back=(total-pagee)/2; if(pagee==1 || pagee==total) {System.out.print("0");} else if(div>div_back) { System.out.println(div_back); } else if(div

[@JavaAidTutorials]

thank you.

[@r_shinchan2459]

Today's problem and their solution pe drawing banani he

[@JavaAidTutorials]

Sorry, I did not get that? 😃

[@preetiipriya]

why didn't i think this way

[@ahmedouyahya]

Thank you sooooooooo much.

[@JavaAidTutorials]

Most welcome 😊

[@lasithadulshan7357]

Thank you !

[@juborajroypavel8342]

Thank you so much.

[@JavaAidTutorials]

You're welcome!