I had no clue how these graphs work, now i know what they are and what they do, now my teacher wont scream at me. Thank you
@praisejack96154 жыл бұрын
I am watching this at home in 2020 and it has made my understanding of IV graphs better .thank you so much
@bluesystemjackson4 жыл бұрын
It's Corona tiiiime
@allysiaasare1948 Жыл бұрын
Hey from the futureee
@simonvutov7575 Жыл бұрын
@@allysiaasare1948 im from even further in the future
@trekglet84003 жыл бұрын
introducing the threshold term to the diode graph makes it more memorable. thank you very much
@lol-vw7vu5 жыл бұрын
absolute hero, rescuing my gcse's. much love
@lailazafreen56744 жыл бұрын
Mine too
@archaaayyyy42824 жыл бұрын
Mine too
@c4wk5463 жыл бұрын
Mine too
@KAWTHARFARDOSI-s9j Жыл бұрын
you are the best teacher . you helped me to understand this lesson before one day from my exam . I need your explanation in my academic career
@python5175 Жыл бұрын
Im in IB, and this helps a lot for the graphs. Thanks
@ju4nita5 жыл бұрын
Thank you so much this just brought even more clarity to physics that other sources don’t so grateful
@evanmacdonald96327 жыл бұрын
I'm doing national 5 physics (Scottish equivalent) and this is a hell of a lot more easy to understand than any Scottish sources.
@gettoknowscience34037 жыл бұрын
Thanks Evan, glad to help!
@paolafiumarella86523 күн бұрын
Hi! Thank you for your video! I've a question. What are the I-V graphs for LDR and thermistors? Are they ohmic?
@juanquezada22967 жыл бұрын
I have to do a graph of voltage vs current and am wondering what is a good mathematical function that can fit my data for a light bulb.
@milkandduckrailway3235 жыл бұрын
Cubic function?
@mahnoornadeem51512 жыл бұрын
In thermistor, how is will the temperature decrease resistance when in ur previous video u said more temperature means more resistance
@rincavyt39102 жыл бұрын
Thank this helped me alot I was so confused. Also Just to understand does that mean the diode needs to melt a bit in order to conduct electricity so that it’s ions can be free?
@smellysnail1348 Жыл бұрын
why is it that when the temp of the filament bulb increases, the resistance increases. but when the temp increases for the thermistor, the resistance decreases?
@SA-AVIATION Жыл бұрын
Who’s watching the night before the test? Any way thanks really helpful
@funtime25112 жыл бұрын
Nice channel ! Really helps to understand
@faizmalik92106 жыл бұрын
It's important to indicate the reference directions for current i and voltage v to interpret the i-v characteristic curves correctly, especially the asymmetrical diode characteristic.
@KAWTHARFARDOSI-s9j Жыл бұрын
tthank you tooooooooooooooo much
@TheSaneInternational-SNI4 жыл бұрын
I was looking for a graph of thyristor... Anyways, it was a very nice video, it made my concepts clearer... Would be of great help if you provide a graph of thyristor tooo...
@LETTYONLY13 жыл бұрын
This guy is sooo good X
@smallishcookies7 жыл бұрын
Is the LDR usage for street lamp applicable? The street lamp would turn on when dark, but the graph shows that when there is more light, there is more current, and the lights will turn on. Am i missing something?
@gettoknowscience34037 жыл бұрын
Yes; in real life the circuit would be more complicated than just simply having an LDR - it would require additional circuit components arranged a certain way so as to get the desired output. But that is way beyond GCSE level so I didn't include a full explanation. The main point was that an LDR could be used as part of a circuit to control a street lamp.
@smallishcookies7 жыл бұрын
GetToKnowScience Oh okay thanks. i figured it would probably be something like that
@smallishcookies7 жыл бұрын
GetToKnowScience Really helpful video by the way, saved me 1 - 2 marks on a test yesterday :))
@gettoknowscience34037 жыл бұрын
No worries - I'm glad it helped!
@manasbapat67366 жыл бұрын
I thought all that would be required would be a filament lamp connected in parallel with an LDR. As night falls the resistance of the LDR increases so there is more P.D across it so the Lamp glows brighter
@nikhilrooprai26225 жыл бұрын
SOOOOOO HELPFUL MAN THANKS ALOT.👍
@otheraccount67794 жыл бұрын
*A lot
@angelina_allanson87593 жыл бұрын
Thanks so much for this, I've been off for covid and my tea hers didn't send me any work eventhough they said they would lol
@awabghazi65097 жыл бұрын
So in the light bulb situation it means that doubling the current will always be higher than doubling the voltage?
@dalirkosimov25767 жыл бұрын
Yes because the temperature increases. An increase in temperature will increase the resistance (like in toasters, which are just very large resistors). So, the more current you have the higher the resistance would be. Hope this helps. (EDIT: a filament lamp emits thermal energy becuase the electrons transfer electrical energy into "wasted" thermal energy and "useful" photonic energy. Its like lighting a stick on fire and using it as a torch. LED (light emitting diodes) are much more efficient, as they don't emit much thermal enrgy, meaning that you can increase the brightness (by increasing the voltage) without making the component hot.)
@johan.7622 ай бұрын
Teacher threw a chair at my head because I got this wrong
@wilma98786 жыл бұрын
But, isnt the Resistance R the slope? If it increases for the lamp then why does the slope of the graph decrease as it gets higher voltage? How do I calculate the resistance from the graph I/V for a lamp? When the function look like in your example.
@strat0caster1245 жыл бұрын
If you hand wave it and say R = dV/dI, then in I-V curves the slop is dI/dV = 1/R, the slope decreases means higher resistance.