Ideal Gas Equation | JAMB calculation tricks | Important JAMB points

[@imranfatai6426]

Thank you very much Sir Ajaks. I learnt something. The answer is 0.0078 mol Option C

[@oluebube-yc4jg]

Ajaks tutorial to the world 🥰🥰

[@AishatAliu-j1p]

I will not lie I really understood everything 😅😊

[@ajakstutorials6656]

Perfect!!!❤️❤️

[@AishatAliu-j1p]

@ we want more on KZbin

[@JedidiahTomiloye]

C.0.0078mol. Thank you very much sir I really understood the class more knowledge and Wisdom sir AJAKS

[@ajakstutorials6656]

Glad to hear that

[@PhilomenaAromeh]

God bless you Sir Ajaks

[@ajakstutorials6656]

Amen🔥🤲

[@oluebube-yc4jg]

Thanks very much sir Ajaks This is the best online tutorial now and forever🎉🎉 The answer is 0.0078 mol

[@ajakstutorials6656]

Lovely to in enjoyed it!🔥 0.0078mol is legit!

[@HamidShuaibtaiye]

Very simplified and understandable Thank you sir ajaks 🔥

[@ajakstutorials6656]

You are welcome!🔥🔥

[@GraceNkechi-ef7xq]

Thank you, Ajaks. 😌 I learned a lot 😊❤

[@ajakstutorials6656]

You're welcome 😊

[@AjakayeBridget]

I love the way you summarize after teaching well understud and clear thank you sir

[@ajakstutorials6656]

You are most welcome

[@AdaezeAmarachi]

👍 kudos to ajaks tutorials

[@ajakstutorials6656]

Thank you!🔥

[@geraldudomeh1874]

Wow✍️✍️✍️✍️

[@onyinyenwangwu3789]

I love how you have a summary after the class

[@ajakstutorials6656]

Lovely to hear!🔥

[@GiftMajekodunmi]

So good 👍🏽 thanks

[@ajakstutorials6656]

You are very much welcome!

[@h_mmin.g]

Ans; C. 0.0078mol ... Thank you for your explanations, sir, It's a detailed one...

[@ajakstutorials6656]

Very good

[@chrisjoshua6571]

Thank you very much for this, well detailed 🫡

[@ajakstutorials6656]

Glad it was helpful!

[@Gabriel-b3z6e]

Thank you so much sir ajaks 🔥😌. The answer to the question is 0.0078mol.

[@ajakstutorials6656]

Well done

[@christianchristopher-ne7kr]

U r the best

[@ajakstutorials6656]

Thank you!🔥

[@BRTTELECOMS]

Ajaks for a reason!❤

[@AbdulateefMusthapha]

The class was very interesting, thanks to you I have learnt something new The answer to the question is 0.0078

[@ajakstutorials6656]

Yes, correct

[@HabbiTech]

Thanks ajaks love it 💙

[@ajakstutorials6656]

@@HabbiTech that's lovely to hear!

[@muritadohnimatallahi]

Thanks your class very interesting and you are such a great tutor

[@DynamoDigitalMarketing_1]

Thank so much i really enjoyed the class❤

[@ajakstutorials6656]

@@DynamoDigitalMarketing_1 nice to hear, subscribe for more!

[@AsmauAbojututu-yh2lw]

A well explained class Keep it up sir🎉

[@ajakstutorials6656]

@@AsmauAbojututu-yh2lw that's very lovely to hear!❤️

[@AsmauAbojututu-yh2lw]

@ajakstutorials6656 Anticipating for your paid class sir 😁

[@itunuoluwadahunsi]

🔥🔥🔥

[@Debbie-on4wb]

Thank you Ajaks Under what conditions do real gases behave under ideal gases??

[@ajakstutorials6656]

You are welcome!📍

[@DynamoDigitalMarketing_1]

Answer is 0.0072

[@ajakstutorials6656]

0.0078* is correct.

[@ElijahAdebayo308]

I got 0.0078mol Which is option C

[@ajakstutorials6656]

Legit!🔥🔥

[@NachosMills]

Practically, compressibility factory is the same thing number of moles? I noticed they have the same formula.

[@Asiyah-p8b]

Sir what if the pressure is in mmHg

[@ajakstutorials6656]

@@Asiyah-p8b you simply convert to atm because if you don't, then you can't use the gas constant, R = 0.082 because the units will not be consistent.

[@Asiyah-p8b]

The answer is 0.0078

[@AdedokunGoodluck]

The answer is option C. 0.0078mol

[@AbdulateefMusthapha]

The answer is 0.0078 mole

[@ajakstutorials6656]

100/100📍🔥

[@Slayer_05]

I got 0.0078 mole

[@ajakstutorials6656]

Legit!🔥🔥

[@OjelekeAdelani]

0.0078 sir

[@ajakstutorials6656]

Very correct✅✅

[@HabbiTech]

The answer is 0.0078mol.

[@ajakstutorials6656]

@@HabbiTech that's correct!💥

[@Rahmat-c7r]

I got a wrong answer but it's because I didn't convert the pressure but I got the right answer already 0.0078 mol

[@Omotolanidamilola-o1t]

0.0078mol

[@ajakstutorials6656]

Perfect!!❤️❤️❤️

[@GiftMajekodunmi]

What is the answer to the question. I have gotten my answer so I want to know if am correct or not

[@ajakstutorials6656]

What was your answer?

[@GiftMajekodunmi]

0.168

[@GiftMajekodunmi]

@@ajakstutorials6656 0.168

[@ajakstutorials6656]

​@@GiftMajekodunmi try again dear!🔥

[@rajiboluwatife-l8t]

The answer is 0.0078mol

[@ajakstutorials6656]

Lovely!❤️❤️

[@jokotola4190]

0.0078mol