IEEE Standard for Floating-Point Arithmetic (IEEE 754)

[@m1hdi333]

Ahhh I hate exams

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We all do 🥲

[@breadmilkYT]

Got one tomorrow lol

[@GrantH2606]

What is it you're studying?

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Bruhh

[@Paul-q5l5h]

Same here😢😢

[@jhss12ageteashreddy41]

I have Sem tomorrow and this is really helpful

[@anishbiswas1492]

Exams in 1 hr, I'm starting the syllabus! Lesgooo

[@ZZZZ-uf4ew]

How was it? 😂

[@pjguitar15]

I'm just starting to learn this for an exam and My god. This is so hard to understand.

[@hacotell]

searching for IEEE 754 because it came up in the Rust Book. This video is excellent. this is the first time I'm learning about this any of this information, but you present it all so well, I want to learn more! Thank you!

[@chaithanyay3641]

But u know one thing they provided 0 knowledge😅

[@Dummy_Boy-q7w]

5:38 i think you wanna say (-15 to +14) because -16 means all zero's and +15 means all one's.

[@seabo9566]

Clicked on this video for IEEE arithmetic and got an entire explanation of the whole system… don’t you think the title should be slightly different. I know how to represent fps now show me the arithmetic like you said

[@RefreshingShamrock]

What would you even use Octuple precision for?

[@soumendey2872]

In floating point representation bias is 8 for 4 bit exponent i.e. (2^(n-1)). But in IEEE standard why bias is 127 for 8 bit exponent, why not 128?

[@zaidahmed596]

no it's 7

[@swethakoushik870]

2^k-1 = 128-1= 127

[@swethakoushik870]

Range for 2's complement is -2^n to 2^(n-1)-1. So for 32 bit single precision, it is 8 bit exponent. So range falls between -256 to 127. -2^8 = -256 to 2^(8-1) - 1 = 127

[@frozenshadow6454]

-128 to 127 I guess @@swethakoushik870

[@jeremylemans3005]

Because 00000000 and 11111111 in binary are reserved for other purposes. So the range in binary ends up being between 00000001 to 11111110, convert that range to decimal representation ==> 1 to 254. Now shift the range with -127 and it results in the following range: -126 to 127, which are the minimum exponent and maximum exponent, respectively, for single precision floating numbers.

[@Technonsia]

it is being used in the self-learning code.

[@gatecomputerscience1484]

Why you are not uploading pdf???

[@tszkoon4269]

why

[@johnkennethjizdeortega7449]

Hi, How about if the exponent in binary16 is greater than 15? How can I calculate the value of exponent?

[@Ianfrancisbush]

this was really great

[@tszkoon4269]

ok

[@tarush4445]

how is pattern of all zero 5:22 equal to -16 ??? wouldn't it be 10000

[@HarshDPatil123]

MSB for signed bit - ,remaining for magnitude .

[@groguyoda7275]

May I know how to find significand bits?

[@jasminnavi]

Another good video :)

[@tszkoon4269]

no

[@ichchakushwaha3209]

Ammm how do we know how many bits are there in mantessa and others..is there any trick to remember the bits

[@tech_muffin7854]

its determined by the type of precision you are working with

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Ahdr msgm ya handi 3dbtni

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ACM better

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olalalal blablabla hein

[@Sabausa746]

This videos are good and all but please stop talking like you are explaining mathematics to kindergarteners

[@prashantdiwakar325]

Baap ko mat dikha 😂😂😂

[@prashantdiwakar325]

Useless fellow 😂😂😂

[@Omar-vs9cz]

if you're feeling too smart you can always skip the video, eh

[@gokulnaathb2627]

Explanations like this will be understood by everyone. Kindergarten style is inclusive..

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