If 2^x+y = 2^x-y=8^1/2, find x & y

[@Italianor01]

8=2×2×2(x+y) 2=(x-y) 8=2 x=2 dan y=1

[@letsthinkmaths4216]

Thanks for reaching out .x=2 &y=1 substituted in the question will give 8=2 which is wrong

[@Italianor01]

@letsthinkmaths4216 oklik sorry master teachvs84 ❤️❤️❤️‍🩹