IGCSE Computer Science C2 - Data Packet, Packet Switching, Error Detection Method & Encryption

[@avationfreak1015]

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[@Harsh_0043]

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[@jamesganleongyi]

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[@andiamruby66]

Finally finished first 2 videos and really enjoyed it! Moving to the next one :)

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My exams also start in 2 days lol. He has been really helpful to me aswell, really hope u do really well in ur exam and pls do let me know how ur exam went😅.

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how'd it go??

[@narayanchauhan7541]

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[@ItsMe-fu3yq]

Thanks for the excellent explanation again James Gan!! I understand this topic much more now!

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Nothing to say really, I am so ahead of what I am learning in class rn because of you. THANK YOU

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i literally have an exam this morning and it’s currently 00:29 in my country 😭😭 Thank you soo much for your videoss. lm literally binge watching thesee!!!❤️🙏🏽

[@hibaalam3884]

Soo how did ur exam went ?.

[@Ch.Hashim_15]

What grade did u get ?

[@riipaah]

my exams are in 4 days and im soo confused on this topic. thank u so much

[@theRealCobra69]

Great video, helped soooo much you have a great ability to condense the topic so that approaching the books is less harder, one thing pls can you pls explain parity block pls pls!

[@Irtixxa]

It's literally 1 am and tmr is my cs exam, you're literally like my last resort ❤

[@Ch.Hashim_15]

What grade did u get ?

[@Irtixxa]

@@Ch.Hashim_15 I GOT AN A* THE EXAM WASN'T THAT HARD (at least for me) alhumdulillah ❤️

[@Ch.Hashim_15]

@@Irtixxa good for u , congrats man

[@Irtixxa]

@@Ch.Hashim_15 thanks dude ❤️

[@aunglinsteve1446]

bruhh this video really helped me thanks James

[@HarshBokan-p4x]

thank you so much, u saved my exam

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Thanks

[@jamesganleongyi]

You are welcome :) thanks for the generosity !

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James gan A.K.A my life saviour

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Me and you both gang

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[@usmanrathore1228]

@@blinkaze1584 less than 8 hours

[@usmanrathore1228]

I'm 50 percent prepared

[@benjamwd8254]

last min cram sesh before tomorrow, like to wish me good luck

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same hereeeeeeeeee ggs

[@benjamwd8254]

bro you saved me

[@sapphire4915]

Thank you so much, could you let me know the difference between a router and a node?

[@readmydescription4507]

Node is the route followed by the data and router directs the data to that route ig

[@Alatus_Alias]

very well explained

[@omarbilal2302]

Hi, I have a question. How would we have 13 data packets if the data is 100KiB because 1000/64 is around 16 data packets required?

[@abbasraza6418]

bro he said 'roughly' it was a rough guess or an assumption, not the actual no. of packets

[@cornelius180]

I've been using this computer science playlist to study and its been very helpful and entertaining, but i would like to ask if it suits the edexcel igcse? Or is it cambridge only?

[@iamfree613]

Love ur vids

[@ahonzaming7713]

what about module 11? on the check digit part

[@RASHIDAKANWAL-k8v]

james gan you are my academic jackie chan !!!!!!

[@drag0nslayer225]

my exam is tomorrow and i saw ur video thanks a lot

[@Ch.Hashim_15]

What grade did u get ?

[@AndiKurniadi-e2w]

Hi, thank you for the video, I get a better understanding by watching your video. By the way, do you have videos about message switching? I am not really understand the message switching analogy. It will be a great help if you can make a video about that. Thank you.

[@sunnikattar3558]

Why did you multiply the even number by 3 in check digit ? 37:47

[@tochukwuanajemba3962]

That's the algorithm on how it's calculated. Read the second point in the slide on the bottom right.

[@usharabrana]

Where is the modulo11 method?

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W for this guy

[@icy3203]

nice thanks a lot man

[@Area_58]

Can you plz do full syllabus of 2210 computer science , my teacher doesnt teach well

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[@OriginsPlays]

absloute W giga chad

[@kiaradeefortune]

i have a question. isnt 173 divided by 7 = 24.7?

[@yatharthpawa9582]

so since 173 is not divisible by 7 they see the last number which is divisible by 7 which is 168 and 168/7 is 24 so thats your quotient and for your remainder you just do 173 - 168 = 5

[@annelii-t8s]

LEGEND

[@infotainmentbits]

37:14 isn't 8 an even number?

[@SlynxBozo]

Hey man you did a mistake at 37:13, how is seven an even number isn't it an odd number?

[@hasnaahmad4656]

He meant the position of the number. In this case, 7 is in the 2nd position of the number, and two is an even number.

[@EshwarForlearning]

he may save my exam because my teacher copies him

[@8dgigs979]

thanks lad

[@ArifHussain-vx2yg]

I can not thank you enough

[@hamzahussain5053]

Why Divide by 7?

[@AtoZSiblings]

its just an agreed algorithm he used , but u don't need to use it there are many different algorithms to use

[@vampiresreprisal6991]

Is it important to remember the algorithm for ISBN-13 and Modulo-11?

[@Palestinewillbefree960]

No......

[@Not_Ali_Munaim]

[@Not_Ali_Munaim]

🌶

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I am also reading same book

[@Loothxd]

0:00

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SSSR

[@scarface-j6p]

manarite