IIT-JEE Advance (2023) Limits Series Question-4

[@Mathsm273]

Really your questions are very relevent for JEE Advanced

[@VedicBhatnagar-IIT-BHU]

👍🏻great ques

[@AkashKumar-no9xc]

The most underrated maths channel . Thank you sir

[@ommakadia3815]

great question sir ..

[@random22453]

Pls give more difficult questions till jee adv sir

[@rajbir2662]

Sir I like your content precise content

[@gnanaolig6385]

2100

[@vibhuawasthi5251]

sir actually i have an easier solution for this. Since the denominator of the first term ( whole part ) is tan^9(x), we can multiply and divide numerator and denominator by tan x to get tan ^10(x) in denominator. Then clearly by writing the whole first function part wise , we get function like (1+ tan x)^10 + (2tanx + 1)^10 , etc. Then we can simplify the left hand limit by old school method ( by putting h --- > 0 and in plaxe of x we put 90 - x ). On further simplification , we can clearly get a function which is of form 0/0. Then by using L hopital rule , we can further simplify and at the end , we will get 10 + 20 + 30 .... which simplifies to 2100

[@kavi5990]

Both methods are pretty much the same just that sir used notations

[@Viggu474]

It's easy sir

[@jamuneshsheta7011]

Sir how that 20 get cancelled out in 4th step...plasee some one ans me

[@makerhacker0171]

Sir, i really appreciate the help which you provide. Can you pls share the source of these questions so that we can also practice them by ourselves.

[@aryangupte2377]

Bro one shouldn't ask the magician about the secret behind his tricks

[@kavi5990]

​@@aryangupte2377 lol😂

[@anushka._..]

Sir i really like your content it helped me to thing out of the box 🙏

[@g.krishna4565]

Sir could you please extend your trigonometric series first??

[@Sanatan_saarthi_1729]

Today's was easy 😊😄

[@VivekSingh-ts6hj]

1/tan⁹@ is multiplied with all terms or only 1st , and it is tan⁹@ correct or it would be tan¹⁰@ ?

[@potath10e]

Yea it is multiplied by all the terms and it is tan^10 only

[@RZMATHS]

I have changed the thumbnail I hope it's clear now 🙂

[@VivekSingh-ts6hj]

@@RZMATHS Thanku sir.

[@kudagkumpan1726]

210

[@aaraveeshan3412]

2100

[@puneetsingh1076]

2100

[@potath10e]

Right bro