Lec-15 Joule-Kelvin Expansion:Properties of Pure Substances

[@harindamodara1232]

1:26 Joule Kelvin _Expansion_ or -Effect- , 9:29 Curve , 19:03 Joule Thompson Coefficient *(***21:29** a little mistake there should be a -ve sign)* 21:55 ideal gas *23:35 Pure Substances 28:38, 30:06 😂 -School level- to *Primary School level* . 31:55 Great Teacher 🙏, PV diagram 33:05-35:32 , 41:01 Triple Point, 42:02, 48:55 TS , 54:11 😨😨😨 Salute to your memory 🙏, Q1-18: 55:15---56:00---56:33---57:21---57:52---58:43 Answers of Lecturer 14: 59:10

[@gollavillihari2516]

generally i dont appreciate any teacher,but after watching i just cant stop to appreciate him.thank u

[@Abhishek-hy8xe]

One of the best lecture on KZbin for undergraduate thermodynamics. Recommended: 1. Book by Zemansky. 2. This lecture series. 3. A book with solved and unsolved problem.( May be garg bansal ghosh book, or yk lim). Practice explaining things in your own words and try to link or fitbdifferent concepts with each as part of whole .

[@meonjiworld]

okay

[@nikhilkayathwal7270]

Awesome lecture... I should have gone through them in my college days:)

[@mayurahire4098]

thank you sir,the music played after every lecture relaxes mind.

[@basseybassey6834]

sure....my favourite classic from old computer games

[@ankursrivastava9074]

👌

[@sathvikswaminathan7933]

Finally understood why the specific volume gap between vapor and liquid decreases with increasing pressure and temperature. Thank you sir for this excellent lecture.

[@werty593]

Presented in a very interesting manner. My teachers must learn from you sir......

[@guesswho-og2wv]

Simply world class.. R. I. P Sir. You are eternal.. These lectures would be a goldmine to students for decades to come.. Never feel like you're no more while watching these lectures.

[@shubhamsachdeva2330]

Best thermodynamics lectures...awesome..so much respect for you sir... thank you very much

[@satyadevpal6985]

Deep respect for you respected sirji

[@shardulkulkarni3999]

Properties of pure substances starts at 28:28

[@ahmadeldesokey9844]

Thanks

[@adarshmamidi5854]

Thankyou so much bro ❤

[@sheldoncooper4130]

thanks man

[@ankursrivastava9074]

Bhai aisa kaida krte h ki click krte hi timer pr shi time pr aa gye

[@ankursrivastava9074]

?

[@radhey886]

nice explaination and very helpful for me for my du second year thermodynamic syllabus and this proffessor is outstanding teacher......

[@Bringiton513]

Well done and thank you very much for sharing your expertise in a way which is so easy to understand.

[@anmolgupta-bj5ce]

Best conceptual video related to this topic thank you sir 🙏🙏🙏🙏😍

[@rudrajitmajumder7249]

Mistake In the expression of joule kelvin coefficient..... there should be a negative sign....

[@sahusandeep9547]

Yes

[@karthigeyan2486]

One of the best lecturer..I seen

[@balajibalu1603]

At 43:50, Sir told it is 100 deg C or 373K it's wrong to ignore 0.15( Sir should have told 373.15K). If it's ok to ignore 0.15 we can neglect 0.01 deg C(tripple point of water) which is less compared

[@mlg-allallong5491]

awesome .. but play video using 1.25 speed for reduce ur time and have greater under standing

[@mayureshmandhare3382]

thanks

[@sunalgautam6255]

i play at 2.5

[@shashu990]

Literally next level. Maza hee aa gya

[@sushaneraviteja7389]

thank you prof .s k som

[@aiswaryasanthosh7878]

At 53:35 Why does entropy increase at higher temperature? .Sir mentions it absorbs more heat ,but as temperature increases latent heat decreases no?

[@saurabhtripathi8986]

Awesome lecture of thermal engineering

[@attitudego]

An alternate explanation. The temperature increase beyond the inversion line is not just because of friction. H=U+PV. In ideal gas, this PV remains constant, which implies U is constant and hence, joule thomson effect is not possible. But in real gases, the PV changes. i.e, in cooling region, the specific volume (v) expansion is greater than that of the ideal gas v, which implies PV increases. To keep the H constant, the internal energy U decreases and thereby temperature reduces. In heating the specific volume doesnt expand as much (physical speaking, the attractive forces between the molecules does not decrease as much/repulsive forces does not increase as much - depends on compressibility factor Z) and thus U increases.

[@अण्वायुवरीवर्त]

If your PV increases your temperature should increase n as u say U will decrease so T will decrease This is contradictory But that is the point Now the question is, is the compensation perfect that is ΔT=0 If yes then we have only two options to get to know 👆or👇 it's the friction n expansion LOL I said the same thing twice

[@sahilsingla3547]

Awesome lecture and explanations sir.. thanks for uploading this..

[@davie6422]

flow rate is same means mass flow rate is same then rhow will come into play for compressible fluid then how can we say thAT VELOCITY IS SAME

[@adarsh7307]

best lectureee

[@guruprasadkancharla5555]

Thank you for the awesome explanation sir!!

[@vigneshjg5167]

Thanks for a beautiful lecture sir

[@rohitbhosle6521]

23:00 - 24:00 my doubt is solved..ty

[@amitprakash2071]

pace is so fast but lecture is so good

[@sagaragarwal7700]

can the two effects in joule kelvin expansion that dictate whether the final temp.will increase or decrease completely nullify each other ???

[@biswajitdebnath8984]

Definitely yes, see the curve you will get 2 point where the two temperature will be same means there is no increase or decrease in temperature

[@aiswaryasanthosh7878]

@@biswajitdebnath8984 At 53:35 Why does entropy increase at higher temperature? .Sir mentions it absorbs more heat ,but as temperature increases latent heat decreases no? Can you help?

[@biswajitdebnath8984]

@@aiswaryasanthosh7878 yes as temperature increases Lv decreases ,but it does not mean that entropy at the state of saturated liquid line decreases, Decreasing Lv simply means that the entropy difference between the saturated liquid line and vapour line decreases...and if you are confused why entropy increases with increassing temperature simply see the formula (delta S = C ln T2/T1) for liquid state if you fixed T1 and incease T2 ,S2 will increase.hope it helps

[@ahmadeldesokey9844]

Incredible

[@Goldspotter]

Amazing!

[@coollntract]

why net volume changes,in the condition two properties of the system remain constant throughout. (if two properties of system remains same then all the properties should remain same

[@8895962910]

piyush pandey not in all case though, as in wet vapor case even after making constraint both p, T properties can change as dryness function Change

[@diplomatutorial3256]

28:21 - properties of pure substances

[@SPEEDSTERSPEEDMAD]

Nice vdieo man

[@monishreddy1797]

In the graph shown at 13:07 he said dP should decrease because of throttling....But those points are obtained at different setups where the valve opening is changed..so dP doesn't necessarily become negative always( that is after measuring the pressure at the outlet at one instant and change the valve opening to a different out flow rate, and measure the pressure and take the difference between those two pressures) so dP being positive or negative has nothing to do with throttling...and also it doesn't necessarily becomes negative always...Right??

[@ganeshn3800]

Here dp is by considering friction as per video

[@conceptwallahesegatepsusss9249]

So nice vedio

[@mrregisx6261]

super sir!

[@BAWAkulkarni]

I didn't really get why the slope of the vapour dome is steeper on the left. Anybody get that part? At around 44:00

[@ashindraprasad2057]

***** There is acountering effect....since specific volume increases as temp. inc. and also specific volume decreases as pressure inc.

[@anonymoustraveller2254]

Bharadwaj Kulkarni because at high pressure density of liquid should be high & at high temperature density of liquid should be low but since liquid is not compressible so increase in density due to increase in pressure is almost insignificant although due to increase in temperature the density will get reduced this inturn will cause the specific volume to increase whereas in vapour due to increase in pressure increase in density of vapour is quite noticible & dominates over decrease in density due to temperature hence the density of the vapour decreases , the graph is of specific volume instead hence we have to consider reverse effect then that of density .

[@ANDREWABISHEKRBME]

great !!!

[@apuaddress]

Where's the sound?

[@NILMANIPRASHANT]

Awesome

[@kiransingampalli5076]

🙏🙏

[@SumitKumar-he9wq]

anybody tell me about inversion temp....how to get it

[@jupironnie1]

found series very useful in terms on knowledge and factual info. But teaching method is puzzling..came across an instance where a query was brushed aside as a childish question..very disturbing for a learning centre..maybe a slip of the tongue due to the camera..dont get upset with my critical comments ! bear in mind that progress in learning was from asking the so called dumb questions

[@mmoore9954]

19:08

[@indianj7388]

RIP Sir.

[@mmoore9954]

46:06

[@kiransingampalli5076]

Thermal godddd

[@mmoore9954]

7:04

[@MindYourFunds]

bhhalb.....good

[@saurabh9978]

awesome

[@mmoore9954]

36:53

[@ankursrivastava9074]

28:41