Aldol Condensation || An Universal Video for Jee Advanced | NEET | Mains | AIIMS || IITian Explained

Hello, Guys. In this Lecture we are going to explain all the important points about Aldol Reaction and Aldol Condensation. As You all know that Aldol condensation is one of the very important topic for Jee Mains/Advance/NEET and AIIMS examination. Here, We will discuss this topic from very basic level to Jee Advanced level.
The Aldol addition reaction involves the addition of α-carbon of an enolizable aldehyde or ketone to the carbonyl group of another aldehyde or ketone and thus by giving a β-hydroxy carbonyl compound also known as an aldol (indicating both aldehyde and alcohol groups). The reaction is catalyzed more commonly by a base or some times by an acid.
If the β-hydroxy carbonyl compound containing an α-hydrogen undergoes subsequent dehydration to yield an α,β-unsaturated carbonyl compound, the entire process is also called as Aldol condensation. The dehydration step is possible under the aldol reaction conditions or mostly carried out by heating in presence of an acid or sometimes during acidic workup.
Mechanism In basic medium:
* The first step in base catalyzed aldol reaction is the abstraction of an α-hydrogen from the enolizable carbonyl compound to give a resonance stabilized enolate anion. Usually this step is slow and rate determining.
Note: Usually hydroxide ion is used as a base, since it is less basic than the enolate ion. This ensures the formation of only small amount of enolate ion and is a necessary condition for further reaction of this ion with unionized carbonyl compound. Otherwise, if strong bases like amide are used, all the reactant molecules are converted to enolate ions and no further addition is possible.
*The next step is the nucleophilic addition of enolate anion to the carbonyl group of second aldehyde or ketone molecule. The final product formed after protic workup is a β-hydroxy carbonyl compound (an aldol).
Note: In aldol reaction, the enolizable aldehyde or ketone acts as nucleophile, whereas the carbonyl group of other molecule acts as electrophilic centre.
Mechanism In Basic medium:
* Initially an enol is generated from the enolizable carbonyl compound during the acid catalyzed aldol reaction.
* Thus formed enol reacts with the protonated carbonyl group of another molecule.
Dehydration:
The spontaneous dehydration of β-hydroxy carbonyl compound containing an α-hydrogen may be possible under the aldol reaction conditions or by heating in acid medium. The formation of stable α,β-unsaturated carbonylcompound is the driving force for this step. Hence the initial aldol addition product is often not isolated.
Dehydration in basic medium:
It proceeds via E1cB (Elimination Unimolecular conjugate Base) mechanism. Initially, the hydroxide ion removes acidic α-hydrogen to yield an enolate ion, which is a conjugate base of aldol. In the second step, the hydroxide ion is lost from the enolate ion to furnish the α,β-unsaturated carbonyl compound.
And Many other aspects of this reaction has been discussed in details.
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We hope this would be very benificial for you guys.
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MKA Sir

[@IITianexplains]

Answer of 1st question is 3 mole of CH4. (As explained inside the lecture ) Compound has 3 acidic hydrogen. And in question no.3 (2nd step) -OH is with the carbon connected to N. Result is still same Chooti Chooti batton per logic bhi lga liya kro.😊 Next video is coming tomorrow.

[@MaheshBabu-gr9bg]

गुरुदेव, जिनको ये बात समझ आ गयी होगी मै समझता हूँ, उनकी preparation मस्त चल रही है । आपकी विडियो KZbin पर कहर मचा डालती है । यकीन न हो तो unlike देख लो । सबकी जल जाती है । 😂😂

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Sir In 2nd question 2nd step kaise hua Mere hisab say miss ho gaya hai aap say

[@bhavesbiology5388]

Yes sir. When I understood, your correction was there. Thank you very much SIR.

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Super explanations!! 👍

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Liked before watching💯💯

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The most reliable and relevant channel on KZbin for JEE Advanced Chemistry. 🙏🏼

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MKA SIR PROVES TO BE THE BEST PROVES TO GIVE ONLY THE BEST,even the first question is mind blowing,proud to be your student sir,thank you's are not enough to express how great it is to be your student,yet a very very heartful THANK YOU Sir..

[@saarankumar2118]

Sir you have skipped elementary questions. It saves time as most of us know easy questions. Thank you sir for such quality videos

[@nazrulislam-cu7li]

We will work hard for upcoming battle..... The battle is in the corner the entrance exams.... Thanks for giving aldol condensation video..... The most important topic for goc in iit Or aiims.... Thanks kashif alam sir

[@kmshivsinghvani]

Sir you are great leader of our country in education field

[@9829manoj]

A good teacher can inspire hope, ignite the imagination, and instill a love of learning. ... THANK YOU MKA SIR...........

[@chanakyagattu1421]

Sir the theory you write in description box is unmatachable it clears concepts neatly and clearly. Thanks for your kind effprts

[@aryankr427]

SIR P BLOCK IN ONE SHOT PLEASE

[@futuredr.1657]

Hmmmm P block se 3-4 ques.aate h neet m Nd esme bhtt confusion hota h alg alg elements ki properties ko lekr

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Needed badly

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Yes please

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Pure content, no ads, no time pass with easy questions.

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Sir try to give more videos within 30 day

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Thanks sir for your support#JEEAdv#MKA sir

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Aajkal to KZbin main teacher kam entertainer jyada hai sir You are best

[@sahebgarain865]

Such much aldol ka concept boom Boom ho gaya

[@anuranroy4617]

I didn't get the part 17:01 ... how is the pyrolidine ring getting transferred from one carbon to another? How is it going to the carbon beside the carbon with C-OH?

[@subhankarpramanik2224]

Sir aisehi important reactions ko sare cover krdo ... Advance se phele .... Thnku sir..😊😊

[@srijanyadav4209]

Awesome sir!!!!! Keep bringing such BOOM BOOM questions!!!! Advanced me seedha aayse jee ques aayeenge, aur hum machyenge😊😊😍😍

[@NitishKumar-ro3yh]

I'm seeing this for JEE 2020. You have always taught us (surely me!) in a very easy way and increased the level of knowledge in chemistry. I cannot Thank you in words!!

[@MARINGANTISUDARSHAN]

No words and no talks... you are excellent sir🙏🙏🙏

[@Rage_SouL]

Aldol ka naya roop dekhne ko mila sir .....Thank you very much ...last wala Q. Sachme concept chamkane wala tha. Lots of Love from West Bengal...

[@siddharthgautam7293]

Thank you sir. You cannot imagine how much useful are these videos for a lot of students. Amazing explanation. Keep on moving sir.All the best.

[@chenaramkumawat1390]

Hello sir Me aapka hi offline student hu or abhi IIT Ropar(2nd year) me hu and Organic chemistry ke end sem ki teyari ki liye mene aapka ye video dekha h or sare concept clear ho gye. Thank you sir Chena Ram Kumawat

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Thankyou soooooo much sir ji 😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊👍😊👍

[@debrupachakraborty9352]

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[@organicchemist8356]

I m student of M.sc chemistry.... Organic...4 th semester....

[@rishabhkaushik9360]

great

[@babasprincess3846]

Me also🥰

[@itsanshpandey]

Very helpful

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BOOM BOOM 🎉MKA SIR!!😀

[@itsanshpandey]

The best lecture ( organic) on IITian explains...

[@nameisrango]

Description is the must watch thing for this video !

[@tanmaysarkar8384]

I know this Video is going to boom like crazy on tube. Definitely this would be great content as always. But did anyone notice that Sir has different wrist watch in Question no. 1 and in other question. 😁

[@dr.ishitajain7339]

Shi baat. Nice catch. I noticed this too.

[@mkasir-thegodofresearch8102]

😄Yeah bro...you did notice correct!!

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No view but 9likes what a power

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SIR PLEASE MAKE A VIDEO ON Sn1 vs Sn2 vs E1 vs E2 No one have been able to give a detailed explanation.... So you are my only hope......

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those 45- 50 min completely worth it !!!! solving complex questions easy way ... thank you very much!!!! also no ads .. just wow :)))))

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Next topic for organic 1.sterio(advanced level). 2.imp facts which are mostly unknown or neglected like BBr3, low temp hydrolysis,etc. Plzzzz sir.....

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Thanks sir🙂

[@SanjeevKumar-ei6qu]

👌👌👌

[@pijushpaul634]

Thanx Sir ........next is cannizaro please........

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Thank you sir 😇

[@Fun_at_its_peak_786]

Benzaldehyde is more reactive so it will oxidise and when react with RMgX 1 mole is consumed..... This is right answer

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SIR you are unique...your logic of understanding of organic chemistry is phenomenal

[@IITianexplains]

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Sir your lecturer very good I have never seen so Mach mechanistic and fully packed lecture

[@tanmoydutta5846]

One of the best videos on Aldol Condensation.....thoko like, sab lok...

[@swationeness5679]

Thanks sir

[@TarunSingh-vj5ty]

Sir…At “12:00” ......why the answer is 3/2 moles ? .....should not the answer be 6 moles(3x2)....pls reply

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Its commendable as always , a very thorough crux review , worth a lot . Thank you very much Sir .

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Best organic chemistry teacher for advanced.

[@rikenprajapati0306]

very conceptual questions for jee advanced

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[@shyamalbanerjee4988]

Sir thank you for such a wonderful video..but i had a doubt..in the first question you had described a logical enough reason as for why the larger compound is oxidized in cannizaro...but it is equally likely possible that attack by oh- and hence formation of coo- is hindered due to 3 huge bulky groups attached to that carbon...instead benzaldehyde should have been more reactive ...both logic seems equally correct...please comment and clarify...

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[@anmol__shankar]

Incredible collection of questions sir, learnt a lot from each question. Thank you!

[@aryanisgood]

Khatarnak faadu questions hai sir maja aa gaya

[@mdsaim9779]

Thank you kasif Sir.......I have never seen any video on aldol like this....this is full of brilliant concepts....

[@IITianexplains]

Asalamalekum

[@mdsaim9779]

Walaikum assalam wa rahmatullhi wa barkato hu....May Allah give you a very happy and energetic life....

[@yoganandagupta4362]

In 1st question why answer is 3/2... ,rather 3 moles

[@IITianexplains]

Answer is 3 moles Hydrocarbon . 3CH4

[@IITianexplains]

3 moles hi hoga answer. 😊 Please check the pinned comment. 3/2 likh Diya h...it's actually 3 moles. (As explained)

[@yoganandagupta4362]

I don't know how you get this much patience... Doing for no profit, again replying.... I have no words to appreciate your efforts sir!!!

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Sadabahar ❤❤❤

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Sir SCRA exam has been cancelled by upsc since 2015

[@IITianexplains]

Yes for reference.

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Thnq..Sir..Jii.😍😍😍😍..

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[@udaydoshi6233]

Kya muje koi first question me 3/2 answer kaise aaya wo samja sakta hai ?? Acidic hydrogen 3 hai to 3/2 kaise aa gaya??

[@IITianexplains]

Beta 3 moles hi hoga. Likhne me galti hui h.😊

[@learningsoul7289]

Thank a lot sir 🙌😊😀😇

[@pratikkumar1060]

Sir pls make a video of jee adv level questions on aromatic chem topic..

[@urvashidekate6742]

Best questions.. Sir

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Your teaching methods are too good sir. I could not get my eyes off the screen this whole time.

[@pratikkumar1553]

Hello sir.. Sir can u plz solve some examples of multiple reactions question of organic.. as in jee 2018 lots of those types of questions were asked.. Sir pleaseeee....

[@pratikkumar1553]

Sir when would u upload

[@sakshamsaxena4159]

Extremely helpful for jee advanced thank you so much sir🤟

[@ayushmaandash3562]

8.6k views only? 😤😤😤. This should be on he trending list by now. Best video on aldol condensation. Even the first question was mind blowing ♥️♥️♥️. Love your mentos concepts sir. Lot of respect

[@organicchemist8356]

Hi sir

[@AnkitKumar-ix3bp]

You are great sir

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Kind sir , i know its selfish but we need only two topics which is missing BIOMOLECULES and STEREOISOMERISM atleast my preparation will be complete for Inorganic and organic :)

[@suvroganguly6211]

"8:40" there would an OH group attached to the carbon atom.

[@samdsouza805]

best explaination

[@ShivamSingh-rl8lr]

Sir.....BEST IN THE WORLD....😍😍😘 TYSM SIR FOR THIS VIDEO. 😍😍 PLS SIR EK REQ H CAN U MAKE A SMALL STRATEGY VIDEO ON BITSAT OF 10 MINUTES...PLS PLS PLS PLS PLS PLS PLS SIR....KYUKI I KNOW APSE ACHA OR KOI STRATEGY NI BTA SKTA IS EXAM KI PLS SIR

[@navaneethbuilds]

Sirji tusi great ho hats off sir for your outstanding lectures

[@girishdeshpande8879]

In q 3 (26:16) why ring expansion did not take place, instead hydride shift is done?

[@yatharthgupta6468]

Best video on aldol👍👍👍

[@samarthshukla1160]

sir ur videos really takes our level from micro to macro

[@nehachalotra7943]

Sir, i really appreciate your efforts.. I have one doubt regarding ques no.2 . Please explain the step after intramolecular proton transfer.

[@vikasdangi1787]

Why steric hindrance is not working in Q1. and if base is conc than it gives cannizaro and if it is dil than it will give aldol how in this reaction CA(OH)2 can give both . PLease reply,

[@pritammishra3360]

sir when i see the poster of a new video i feel extremely happy but when i watch it fully i become sad as i wish if i could watch it thousand times making it evergreen and this is one of them

[@malikbhai3192]

Tq so much sir

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[@organicchemist8356]

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Hii

[@IITianexplains]

Shukriyaa Esha 😊 भारत माता की जय ।

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u r in our great nice to.see u

[@organicchemist8356]

Thanx to all of u

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Super

[@yashpalmahdele5610]

sir question no 2nd me 3rd step aap fir se dekhiye sir sayd thoda sa mistake he usme OH bonding me. thank you sir

[@IITianexplains]

Yes. Check the pinned comment.

[@Sheela-ky6mp]

Cannizaro reactions bhi padhana sir😊

[@sachinmaurya7474]

So much thanks sir Great explanation

[@rohtashkumar6507]

Always eagerly waiting for your videos.....

[@SeekingTheTruth369]

Sir next h2/ni