H.W. Since spanning set has 2 elements and 1 is not scalar multiple of other they map the basis of 2 dim which contradicts out result of 1 dimension null space
@rustumkhaire71936 күн бұрын
p(1)=0
@heeralalbind6 күн бұрын
H w d is not currect answer
@rustumkhaire71936 күн бұрын
null space k definiton
@tan203415 сағат бұрын
The null space of an m×n matrix is written as null A is the set of all solutions to the homogeneous equation Ax=0
@sandhyakumari87186 күн бұрын
Which of the following is a subspace of the real vector space R^3 (a) [(x ,y,z)€R^3; y€Q] (b) [(x,y,z)€R^3; (y+2)^2 + (2x+3y)^2=0] (c) [(x,y,z)€R^3; x+2y-3z+1=0] (d) [(x,y,z)€R^3; yz=0] Sir please iska solution bata dijiye option b nhi samaj aa rha h
@WELCOMETOBEAUTYWORLD6 күн бұрын
Option b
@zero-sl3bn6 күн бұрын
@@sandhyakumari8718 sum of squares are always either positive or zero so we can get y+2=0 and 2x+3y=0 (in R) both are linear that's why this is subspace
@sandhyakumari87186 күн бұрын
@@zero-sl3bn Thank you
@sandhyakumari87186 күн бұрын
How it will satisfy the zero vector condition ?
@zero-sl3bn6 күн бұрын
@@sandhyakumari8718 oops I didn't saw the equation clearly I guess none of them are subspace 😅 Edit: (I thought it was 2x my mind didn't registered)