Implement Pow | gfg potd | 29-01-25 | GFG Problem of the day

[@CodeGenius316]

Detail me samjhane ke chakkar me video lambi hojati hai btw like to krdo

[@Mystical_Moments]

brute force fails in negative case

[@amanqureshi3222]

change b->1/b and e->-e. double ans=1.0; for(int i=0;i

[@ganeshjaggineni4097]

NICE SUPER EXCELLENT MOTIVATED

[@CodeGenius316]

Thanks ❤️

[@itsmychoice7217]

This can be also done simply by using the power function double result=pow(b,e); return result;

[@CodeGenius316]

🙂

[@kartik2777]

@itsmychoice7217 🤦‍♂🙅‍♂

[@pashukumar1724]

Ha tb interview mein yehi krne aana 😅😅

[@pashukumar1724]

isse aaccha return pow(b,e); le 😅😅

[@itsmychoice7217]

@ maine sirf ek approach batai hai 1 question ko solve karne ke liye multiple approaches hoti hai bro.