Implicit Differentiation | Differentiation when you only have an equation, not an explicit function

  Рет қаралды 18,649

Dr. Trefor Bazett

Dr. Trefor Bazett

Күн бұрын

Пікірлер: 19
@taia-b8f
@taia-b8f 24 күн бұрын
For the other people that got stuck looking at dy/dx = -2x/2y(x). Basically, just keep solving the equation that he shows you and keep treating dy/dx as a variable. 2x + 2y(x)dy/dx = 0 2y(x)dy/dx = -2x dy/dx = -2x/2y(x) dy/dx = -x/y(x) dy/dx = -x/y
@NINJA-tf6bf
@NINJA-tf6bf Жыл бұрын
Thank you very much ❤ Your explanation is mind blowing 🤯
@andybrice2711
@andybrice2711 8 ай бұрын
Thinking of y as the function y(x) was very helpful here. I've never quite understood before why this can be treated as an application of the chain rule.
@mohammadfallahzade2110
@mohammadfallahzade2110 4 жыл бұрын
You are a great Teacher thank you so much
@mnada72
@mnada72 3 жыл бұрын
Great 👍, very informative, thanks.
@gustavopalma9451
@gustavopalma9451 4 ай бұрын
Nice explanation.
@gordongoodwin6279
@gordongoodwin6279 Жыл бұрын
I love your videos but it would be great if you could re-do this one when you have time. As others have noted, it wasn't very clear how you arrived at the 2y(x) dy/dx as the derivative of the composite function. I understand it now but it wasn't clear in the video
@SandeepKumar-qu9dh
@SandeepKumar-qu9dh 2 жыл бұрын
Happy teacher's day sir
@studentsofmathematics8995
@studentsofmathematics8995 4 жыл бұрын
dear which software are you used for presenting lecture? please guid me. thanks
@florentinosanchez3969
@florentinosanchez3969 Жыл бұрын
Very nice video
@captainphysix
@captainphysix 7 жыл бұрын
great video!
@FRC_CR
@FRC_CR 2 жыл бұрын
I have to say up until this point the course was great but you seemingly assumed that from 4:03 adding some dydx randomly made sense. I have no clue how you got to that conclusion and you didn't really explain it. Can you help me please?
@gordongoodwin6279
@gordongoodwin6279 Жыл бұрын
Agree this part was poorly explained compared to everything else. The dy/dx is the derivative of the inside function (y), which flows from the chain rule. In other words, y(x)^2 is a composite function. The outside is the squaring act, so derivative of outside with respect to inside is 2y(x). Then we multiply it by the derivative of the inside. Well, the inside is just (y), so the derivative is dy/dx. Putting it all together we get 2y(x) multiplied by dy/dx
@Celtics-x4w
@Celtics-x4w 11 ай бұрын
@@gordongoodwin6279h
@eyesack3606
@eyesack3606 9 ай бұрын
Old Sheldon.
@qualquan
@qualquan 7 ай бұрын
bad
@twisted4872
@twisted4872 2 жыл бұрын
That was a horrible explanation . . .you murdered it.
@nebilzeleke3703
@nebilzeleke3703 2 жыл бұрын
are u edmonds cc student ????
@NINJA-tf6bf
@NINJA-tf6bf Жыл бұрын
You truly are twisted
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