Important Aptitude Question for GATE 2025 | Algebra

[@ExergicGATE]

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[@ExergicGATE]

Answer to Practice Question is -16. f(g(x)) -3x = x^2 - 4x - 12 Minimum value will be at x = 2 Substituting, we get 4 - 8 - 12 = -16

[@KaranBhil-zt9qm]

Thank you very much ma'am for this session please keep making videos for all other topics

[@rehmani111]

Maam apki awaz ias tina dhabi se milti hai, I got the answer (-2)

[@uuttaamm]

Ans -16 option B

[@saiashish3065]

Practice Qn : Answer is -16 , Option B

[@raj-wb7hz]

Madam are you from Kerala

[@batball6582]

Mam minimum value i find -2

[@ExergicGATE]

f(g(x)) -3x = x^2 - 4x - 12 Minimum value will be at x = 2 Substituting, we get 4 - 8 - 12 = -16

[@RichieRich-hh5vt]

thank you mam

[@sktutorial2023]

-16 op b

[@letslearn1509]

Ans (-16) B

[@gaya3_1317]

Option c - zero

[@ExergicGATE]

f(g(x)) -3x = x^2 - 4x - 12 Minimum value will be at x = 2 Substituting, we get 4 - 8 - 12 = -16

[@hemantshendkar8537]

Option C - Zero

[@ExergicGATE]

Check again!

[@AdityaRajgor-nz2nm]

ans is B(-16)

[@batball6582]

Bro mujhe bata sakte ho ki minimum value +2 kese Aya mera to -2 arha hai