Individual Distribution Identification: Detailed Illustration with Practical Example

[@yuhangsun8977]

It is a great video. Anticipate more video about statistcs

[@learnandapply]

Thank you so much for your valuable comments and appreciation!

[@dakshaudawatta8219]

Simple and very clear thank a lot 🖤

[@learnandapply]

Thank you so much for your valuable comments and appreciation!🙏

[@seansarran6666]

Hi there. Great video. Just 1 question. Why are we choosing the 3-Parameter Weibull distribution when the Johnson Transformation shows the highest P-value > 0.05?

[@learnandapply]

Thank you for your valuable comments and appreciation 🙏☺ You can select any distribution with a p-value of more than 0.05

[@seansarran6666]

@@learnandapply Thank you for your response. Again, great video.

[@phillips2278]

Is there a package for R that provide this similar results?

[@learnandapply]

Thank you for your valuable comments, but so sorry as I am an expert in Minitab with no exposure to R. If you want the package for the Minitab, you can get it at the link: vijaysabale.co/minitab

[@ruthvn]

Hiii sir, thanks for the great video. I'm sorry i wanna ask, i have data that all the p-value are under 0.05 and then i saw your reply in another comment said that if that happened we can decide based on smallest LRT p-value. In my data there are 2 distribution that has 0.000 LRT Pp-value, the first one has larger AD and P-value, the second one has smaller AD and P-value. Which distribution should i choose?

[@learnandapply]

You are correct! Please use the distribution with lower LRT p-value. Thank you for your valuable comments and appreciation! 🙏😊

[@ruthvn]

@@learnandapply Thanks for your reply! I'm sorry i wanna ask again, what if in my data there are 2 distribution that have the smallest LRT P-value?

[@learnandapply]

That's fine. If you don't have any distribution with a p-value of more than 0.05, you need to use the LRT p-value. You need to select the smallest LRT p-value, less than 0.05 in this case. You can select any distribution with this value.

[@ruthvn]

@@learnandapply I understand, Thany youuu!

[@learnandapply]

You're welcome! ☺️ You can enroll in my Free Training Module on Lean Six Sigma & Minitab by using the link: vijaysabale.co/freetraining

[@gowthammurali1224]

In this example Johnson transformation has P value = 0.986 But why we go for 3 parameter weibull? Thanks in advance

[@learnandapply]

In data transformation, there will be a change in data to fit a normal distribution. If any other distribution is fitting to the data, then please avoid the transformation. The transformed data can create confusion in a team sometimes. Thank you for your valuable comments!

[@gowthammurali1224]

Thanks for your valuable comment..

[@learnandapply]

You're welcome 😊

[@vilasnarkede1898]

Thanks for video..sir I have data ,I gone through individual distribution identification test but found all "p" values in propabilty summary are less than 0.05 .As per the checkpoint for distribution type , we are deciding the distribution when the respective "p" value is more than 0.05.In my scenerio how to decide the distribution type when all values are below 0.05. plz your guidence required.

[@learnandapply]

Thank you for your valuable comments and question. In that case, you have to use LRT p values. It's there in the video. Please go through it and let me know if you have any further questions.

[@vilasnarkede1898]

@@learnandapply ok so ..we have to go for lowest LRT "p " value in that case??

[@learnandapply]

Yes, the LRT p values which is less than 0.05

[@mahmoudihocine2837]

What do we do if we have discrete data? How can I identify the distribution? Thanks in advance!

[@learnandapply]

Mahmoudi, please see the videos on Binomial and Poisson Distribution. You're welcome ☺🙏

[@jafarmandoury6073]

this video has been a great help to me, sir can I send you an email regarding a dataset I'm having trouble in processing?

[@learnandapply]

Thank you so much for your valuable comments and appreciation ☺🙏 Sure, please send me the data.