Intuitive analysis of inductor behavior and Buck converter by Prof. Sam Ben-Yaakov
Пікірлер: 231
@doraharony31283 жыл бұрын
I am a former student of yours, graduated in 2008. It's great to see your lectures on youtube, just as good as they were back in the day.
@sambenyaakov3 жыл бұрын
👍😊
@TheKatrinaYang27 күн бұрын
This is such an underrated video teaching how buck circuit works. Trust me, study this video is better off than watching 10 other videos on buck converters that only touch surface level understanding! 🌟
@sambenyaakov27 күн бұрын
Wow, thanks!
@MehdyHassan6 ай бұрын
I spent only 4 minutes and I can already feel that it is going to be a fantastic lecture
@sambenyaakov6 ай бұрын
🙂👍
@copernicofelinis Жыл бұрын
Your tip on how to resolve for the polarity of the inductor voltage is pure genius.
@sambenyaakov Жыл бұрын
🙏👍
@moukaslouka79207 жыл бұрын
It is rare to find someone clearly explaining what happens in a somewhat complex circuit. Thanks for sharing.
@sambenyaakov7 жыл бұрын
Thanks for comment.
@Purple__7 жыл бұрын
Excellent, thank you!! I went from barely understanding how they work to full basic understanding of inductors and buck converters, something the papers and other explanations I found online was not able to do. I love the graphical explanation with the graphs, I'm a bit of a visible learner so they helped a lot.
@sambenyaakov7 жыл бұрын
Thanks for comment
@user-vj5wd6wq1v4 жыл бұрын
@@sambenyaakov No one in a world can help me with this question 😭😭😭😭😭😭😭😭😭😭😭😭😭😭😭😭😭😭😭😭😭😭😭😭😭😭😭😭😭😭😭😭😭😭😭😭🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏 Why we don't consider Miller effect in Common Gate configuration when we study high frequency response
@pingoleonfernandez4985 жыл бұрын
The best explanation on this subject I have ever seen on youtube. Thank you very much.
@sanankhan68123 жыл бұрын
Cannot thank you enough for this video. I pay thousand's of dollars to my university and didn't get a single concept from my professor with 1 week of lectures. And here you are explaining it in 30 mins and now I have crystal clear concepts about buck converter. I m very grateful to you for this video. Thank you
@sambenyaakov3 жыл бұрын
Thanks for kind words. Comments Iike yours keep me going.
@EdwinFairchild6 жыл бұрын
by far the clearest explanation i have encountered in video or text . it is very much appreciated
@sambenyaakov6 жыл бұрын
Thanks for comment.
@MusicLibre9992 жыл бұрын
Thank you. I took this course with an extremely incompetent "professor" at Cairo university. There's a world of difference here. Thank you again.
@sambenyaakov2 жыл бұрын
😊I missed you in class while I was teaching at the university.
@AbuSous2000PR3 жыл бұрын
I have been searching for the derived equations for hours... Thanks Sam.. Now it is so simple...
@sambenyaakov3 жыл бұрын
😊🙏
@sharbatoo6 жыл бұрын
Best video on buck converters that I have ever see. Thanks
@sambenyaakov6 жыл бұрын
Thanks for comment
@iliassfe6 жыл бұрын
Big thank you from Thessaloniki Greece!
@sambenyaakov6 жыл бұрын
Thanks. AS you might know, we Israelis, have a worm spot in our heart for Thessaloniki
@FuzzlordEffects7 жыл бұрын
Thank you Professor Ben-Yaakov! Very clear explanation and video.
@sambenyaakov7 жыл бұрын
Thanks for comment.
@gurgul33 жыл бұрын
The best explanation I saw about buck converters. Great lecture!
@sambenyaakov3 жыл бұрын
Thanks.
@sujithnair56722 жыл бұрын
What a difference it makes learning from an educator who really understands the subject!!! Thank you Sir.
@sambenyaakov2 жыл бұрын
🙏😊
@kaino19904 жыл бұрын
Thank you very much professor. This is a great video and has helped me to understand my textbook a lot better.
@sambenyaakov4 жыл бұрын
Thanks.
@krishnasrinivasan75413 жыл бұрын
Very clear explanations. Thanks a lot. Before watching this video, I had very little understanding of the Buck converter. But I have a much better understanding now.
@sambenyaakov3 жыл бұрын
Thanks. Commits like yours keep me going.
@HDLyricsshapemesh6 жыл бұрын
You are an amazing professor. God bless you
@sambenyaakov6 жыл бұрын
Thanks for comment.
@anmolshah68382 жыл бұрын
From undergrad to grad school to working as an fae, your videos have been really helpful. Thank you :)
@sambenyaakov2 жыл бұрын
Wow. Thanks for sharing.🙏😊
@tonderaimatsungo55404 жыл бұрын
i have been going thru power electronics material since 2018. this is best I have seen
@sambenyaakov4 жыл бұрын
Thanks for taking the time to write the comment.
@robertthompson59082 жыл бұрын
This is an excellent lecture. It cleared up some confusion I had. Thank you.
@sambenyaakov2 жыл бұрын
Thanks
@srudeeppatil2 жыл бұрын
Excellent lecture. Thank you for your time in clearing out many doubts surrounding inductor voltage/current behavior.
@sambenyaakov2 жыл бұрын
Thanks for note
@MinhuChen4 жыл бұрын
Excellent analysis for Inductor and Buck Converter. Thank you!
@sambenyaakov4 жыл бұрын
Thanks
@noonefateh32182 жыл бұрын
Very clear explanation .. Great job
@sambenyaakov2 жыл бұрын
Thank you!
@dradexx6 жыл бұрын
excellent fucken video! thanks prof!!
@nikitasergeev18333 жыл бұрын
Great class, that was a great explanation! Thank you.
@sambenyaakov3 жыл бұрын
Thanks.
@malashis2 жыл бұрын
Truly amazing presentation. Thanks.
@sambenyaakov2 жыл бұрын
Thanks
@user-tk8ys2lp4p3 жыл бұрын
amazing lecture. great insight, I learn a lot from you, thank you
@sambenyaakov3 жыл бұрын
Thanks for kind note.
@ajayvaidya65383 жыл бұрын
The Best Explained.Thank you, Sir.
@sambenyaakov3 жыл бұрын
Thanks
@ymym4977 Жыл бұрын
Excellent, easy to understand, Thank you , Professor !
@sambenyaakov Жыл бұрын
🙏🤔
@shashankgaonkar25463 жыл бұрын
One of the best explanations ever
@sambenyaakov3 жыл бұрын
Thanks.
@manur33172 жыл бұрын
Thank you for the content. very insightful and Intuitive.
@sambenyaakov2 жыл бұрын
Thanks.
@henrikjrgensen30994 жыл бұрын
Extremely good explanations. Thank you.
@sambenyaakov4 жыл бұрын
THANKS
@majortom91gsg3 жыл бұрын
Well, I've got my M.Sc. In EE already, but still... WOW! The explanation was amazing!
@sambenyaakov3 жыл бұрын
😊🙏
@andriberel4712 Жыл бұрын
Thanks you, sir. Detail and systematic explaination.
@sambenyaakov Жыл бұрын
Thanks
@swh197 жыл бұрын
Very basic and important concept with well concise explanation!!
@sambenyaakov7 жыл бұрын
Thanks for comment.
@MinhNguyen-qc9dg2 жыл бұрын
Thank you Prof. I have learn a lot from this tutorial video.
@sambenyaakov2 жыл бұрын
Thanks
@TKR911 Жыл бұрын
Very nicely explained, Prof Ben-Yaakov. A request to please arrange your english videos in the form of a playlist (similar to the hebrew ones) so that we can view more of them! Thanks again, clearly explained.
@sambenyaakov Жыл бұрын
Noted
@kabandajamir9844Ай бұрын
The world's best teacher thanks sir
@sambenyaakovАй бұрын
Wow! 😊Thanks
@factorpotencia3 жыл бұрын
Excellent explanation, you are a very good professor.
@sambenyaakov3 жыл бұрын
Thanks
@danielsanchez62762 жыл бұрын
Thanks, you are an excelent teacher !!!!
@sambenyaakov2 жыл бұрын
Thank you! 😃
@arvindgupta48693 жыл бұрын
Excellent explanation. I love your lectures.
@sambenyaakov3 жыл бұрын
Many thanks!
@Absolumify4 жыл бұрын
Very clear explanation, thank you.
@sambenyaakov4 жыл бұрын
Thanks for comment
@kuime13 жыл бұрын
So helpful! I'm taking my own notes when going through this lesson I'm sure when explaining that he is waving and circling on his drawing pad and there is no indicator on the screen to show which part he is talking about 😂
@sambenyaakov3 жыл бұрын
Sorry, in this particular video synchronization to pointer/pen is corrupted.
@joejane99773 жыл бұрын
thanks again very well explained and well worth the time
@sambenyaakov3 жыл бұрын
Thankls
@stevezhou1844 жыл бұрын
wonderful job, professor
@sambenyaakov4 жыл бұрын
Thanks
@JohnDavis_NetSkink_Computing6 жыл бұрын
Thank you! That was great.
@sambenyaakov6 жыл бұрын
Thanks for comment.
@srinivasuv44363 жыл бұрын
Hello Sir, really great video. Thank you very much!!
@sambenyaakov3 жыл бұрын
👍😉
@mmoci813 жыл бұрын
Hi professor, first, thank You for sharing very educational video where we can get back to basics analysis of a electrical circuits. Probably one of the best video I could find so far of this subject and since You have many more of them I decide to subscribe on the channel. But I would like to ask some question which troubles me. Maybe this comment section is not quite appropriate for it, but still I will ask since it's troubles me and I would like to have better understanding. It is about constant voltage that is often shown across inductor in fast switching circuits like buck convertor. In my head I have a physical picture that as soon as inductor is connected on constant voltage source it will start to build magnetic filed and the voltage over inductor will exponentially dropped almost to 0 value. Of course, during short period of time this drop won't be huge, but still voltage is not quite constant during that short switching period. My problem is fit this picture into the model of fast switching circuit where the voltage over inductor is presented as constant voltage which imply linear current rise or drop. Could you please help me understand why we can assume constant voltage on inductor in a short periods of switching?
@sambenyaakov3 жыл бұрын
HI Marko, thanks for interest. An inductor does not control the voltage across it when connected to a voltage source. It will comply with any voltage and adjust dI/dt. (similarly, a capacitor will not control the current when connected to a current source). You can write to me at sby@bgu.ac.il
@madhavrabinbipin2116 Жыл бұрын
I had also thought about this.Usually why Vl is a constant is prolly because the Vo is treated as constant.The possible explanation I can think is that 1)once the circuit reaches steady state , the capacitor say charges to some voltage.The natural time constants involved like RC,LC etc are very large compared to switching time.This implies that capacitor discharge is very less over a switching cycle , hence Vo is almost constant 2)In terms of frequency domain, the Inductor passes lower order harmonic currents(as its impedance is jWL, it offers more impedance to higher harmonics) and the higher harmonics among these lower harmonics itself are mostly absorbed by The filter capacitor as they absorb higher order harmonics easily.Hence the current which passes to the Resistor load is almost dc current (and hence almost constant) due 'a kind of 2-stage' filtering of higher harmonic currents by inductor followed by capacitor.
@SureshChandraMannava5 жыл бұрын
Thank you. Excellent explanation.
@sambenyaakov5 жыл бұрын
😊
@xiaodongcai864 жыл бұрын
awesome tutorial! If at the end you can talk about the ripples at the capacitors and what are the contributing factors that would complete everything
Dear professor, Have you ever made a video about buck converter in discontious conduction mode?
@samimsk41462 жыл бұрын
Dear Sir, Excellent, thank you :)
@sambenyaakov2 жыл бұрын
Thanks
@mbaker3357 жыл бұрын
Interesting and very well explained.
@sambenyaakov7 жыл бұрын
Thanks!
@khedayache16465 жыл бұрын
Thank you for these courses
@sambenyaakov5 жыл бұрын
Thanks. If not a memeber please join www.linkedin.com/groups/13606756/
@ASABBANE3 жыл бұрын
شكرا يا سام بن يعقوب
@sambenyaakov3 жыл бұрын
תודה
@doctoragoing63927 жыл бұрын
Great explanation! Keep on! :-)
@sambenyaakov7 жыл бұрын
Thanks for comment
@DY-oh4ol7 жыл бұрын
thank you ~~ greet from China
@sambenyaakov7 жыл бұрын
Thanks.
@kabandajamilu90363 жыл бұрын
So educative and future life skill
@sambenyaakov3 жыл бұрын
Thanks
@bangadu_billa5 жыл бұрын
Thank you for great video, do u have a website where i can quickly refer notes in video?
@rajneeshbatra24723 жыл бұрын
I am an amateur exploring electronics. I could understand how it worked.. Thanks.
@sambenyaakov3 жыл бұрын
Thnks for taking the time to write the note, I am happy to learn that the video helped.
@muntu20083 жыл бұрын
Thank you Prof. Ben-Yaakov for the excellent lectures. I have been following them and they have been very helpful. Just a question on this lecture: at 3:17 when you showed the real LR circuit. You explained that the decay of current will be exponential. Shouldn't the rise of the current be also exponential? In your diagram however the current has a constant rising slope. Is there anything I am missing here? Thanks
@sambenyaakov3 жыл бұрын
Good point. You have a keen eye. I should have explained it better. When the battery is connected and duration is short you are at the beginning of exponential which is approximately to straight line. The discharge section should have been longer. Thanks for pointing this out.
@muntu20083 жыл бұрын
Thank you very much for explaining this point👍🙂.
@PlayboyHZ4 жыл бұрын
Thanks for the explanation. I wish you would have covered the DCM, just as you did in the buck converter.
@sambenyaakov4 жыл бұрын
Good point. Thanks.
@PlayboyHZ4 жыл бұрын
@@sambenyaakov I will definitely subscribe. I just have one question, which is related to converters in the discontinuous conduction mode. Would you ever want to operate a converter in DCM? Does it give any advantage for certain applications? Thanks, best regards
@sambenyaakov4 жыл бұрын
There are advantage running Flyback at DCM . See www.linkedin.com/feed/update/urn:li:activity:6671448579661529088
@spykespark84773 жыл бұрын
Thank you Sir!
@sambenyaakov3 жыл бұрын
You are welcome!
@annukaushik9721 Жыл бұрын
Splendid
@sambenyaakov Жыл бұрын
👍🙏
@eurosetvk2 жыл бұрын
very helpful. thanks
@sambenyaakov2 жыл бұрын
Thanks
@user-mj3ef5 жыл бұрын
Dear Professor, you have an amazing talent to teach these topics. It would be great to follow your lectures in an order. Is there such order or link or are these random uploads? I saw your lectures in Hebrew are in order but couldnt figure out the English ones. And one question: in simulations a linear voltage regulator at the output of a dc dc converter or smps attenuates the differential switching noise a lot. Is this way also used in practice? I tried LC cascaded by a linear voltage regulator at the output of a noisy ripple voltage source and was amazed with he result. Would be glad if you have comment on it.
@sambenyaakov5 жыл бұрын
Thanks. See index at www.advicepoweracademy.com/video-tutorials Yes, LDOs are used successfully in low power applications.
@khedayache16465 жыл бұрын
I love you professor
@sambenyaakov5 жыл бұрын
😊 If not a memeber please join www.linkedin.com/groups/13606756/
@cexploreful10 ай бұрын
wonderful explanation Liked + subsribed! thx ❤
@sambenyaakov10 ай бұрын
🙏👍
@myhobbies12882 жыл бұрын
Just loved the explanation 🙏... Thanks for educating the world 🙏👏 Only the sudden introduction of DCM is little confusing to me... I couldn't understand how for the same circuit both CCM and DCM concept came.. please clarify
@sambenyaakov2 жыл бұрын
Please indicate the relevant minute in video
@pradheep.g38557 жыл бұрын
Excellent lecture
@sambenyaakov7 жыл бұрын
Thanks.
@Praveen19919176 жыл бұрын
Thank you so much, sir.please make a video on capacitor behavior as well.
@sambenyaakov6 жыл бұрын
Hi Prince, see my channel for capacitor related videos such as switched capacitor converters and voltage dependent capacitors. .
@Praveen19919176 жыл бұрын
Sam Ben-Yaakov thank you sir
@sathyapalreddy21573 жыл бұрын
Thank you sir
@sambenyaakov3 жыл бұрын
Thnks
@TSulemanW4 жыл бұрын
very nicely explaination
@sambenyaakov4 жыл бұрын
Thanks
@lenazahron17656 жыл бұрын
Dear Mr Yaakov The video is very clear and helpful thanks a lot , but I have a question do you have more videos ?
@sambenyaakov6 жыл бұрын
Look for Sam Ben-Yaakov channel on KZbin
@elwafi20015 жыл бұрын
Very good lecture
@sambenyaakov5 жыл бұрын
😊
@souheybmohammedbelhadj5189 Жыл бұрын
Thank you
@sambenyaakov Жыл бұрын
You're welcome, Thanks
@marvinvelasquez77912 жыл бұрын
professor do you mean the the DC current goes to the resistor and the AC goes to the capacitor?
@sambenyaakov2 жыл бұрын
Yes. No DC via capacitor. Resistor will have some AC current depending on ripple voltage.
@moniftormos6881 Жыл бұрын
Great
@sambenyaakov Жыл бұрын
🙏👍
@sarigubonsri20917 жыл бұрын
Excellence good explaination Great !
@sambenyaakov7 жыл бұрын
Thanks for comment. I appreciate it.
@sam-pd6zi2 жыл бұрын
thankyou...
@sambenyaakov2 жыл бұрын
Thanks
@Dreamerick974 жыл бұрын
Hi, i have problems understanding which minimum value of capacitor i have to use, thanks and excelent video.
@sambenyaakov4 жыл бұрын
Voltage ripple and loss (due to ESR) are the limiting factor
@jeebannayak84499 ай бұрын
Very nice video sir but my doubt is, what should be the critical (max) value of the load resistance for CCM operation?
@sambenyaakov9 ай бұрын
The answer is here kzbin.info/www/bejne/fqXamnx_hcqenNU
@intheshell35ify Жыл бұрын
I used the voltage forcing current equation in a presentation. I felt good about it. The audience was a little lost.
@sambenyaakov Жыл бұрын
Why? Thanks for sharing.
@intheshell35ify Жыл бұрын
@@sambenyaakov its the end of the semester. The kids have other things on their mind and didn't really share my excitement about why the current through the inductor doesn't have an exponential slope. That's ok, I'm excited enough for all of us about V/L forcing dI/dt and vice versa.
@sambenyaakov Жыл бұрын
@@intheshell35ify 😊😊👍👍
@martinwoodhouse38382 жыл бұрын
Please confirm that the load in the final example ( 31.23 min) is 5V/10A= 0.5 ohm. Time constant is L/R 1.2microH /0.5 ohm= 2.4 micro Seconds to 63% of peak. So frequency should be about 300kHz ( not 100kHZ) with a duty cycle of 0.5. Only correct if you ignore the capacitor. Where have I gone wrong or am I completely wrong
@sambenyaakov2 жыл бұрын
WE assume a large cap so the output is like a battery of 5V.
@user-pn9be1zt7n6 жыл бұрын
Hi, Professor I have a question. The waveform of current of an inductor at the second slice, it should be pass through origin. Why doesn't it pass through? In the beginning, iL(0) = 0? It that wrong? Thank you so much!
@sambenyaakov6 жыл бұрын
THis is a general case (as you will find in a PWM converter) in which the initial inductor current is not zero.
@user-pn9be1zt7n6 жыл бұрын
Thank you for your feedback. ^ ^ I knew that it's the steady -state result. The current camp of an inductor would act like that, when converter goes to steady- state response with a fixed switching frequency. So, if we talk about at very beginning, which means I turn on a dc source at the first time, the current of an inductor should rise from zero amp, and after the system goes to the steady state(after several cycles), We just see the common waveform(general case) in the slide. Is that right? Thank you so much.
@subbusiva6014 Жыл бұрын
Dear sir your lectures are excellent.I would like to listen all lectures regarding converter design,but I couldn’t find lectures in sequence,kindly suggest me Where can found all these lectures in sequence. Thanks a lot sir .
@sambenyaakov Жыл бұрын
Sorry, they are not arranged. You can search in the KZbin search box for a given subject e.g. " Sam ben yaakov control"
@naidukishore322010 ай бұрын
Hlo sir,good explanation. I have a doubt why we are drawing inductor (i min to max)and capacitor (-ve side onwards)charging waveforms
@sambenyaakov10 ай бұрын
It a convention; in Germany they do it differently
@rampoudel6602 жыл бұрын
Why current across inductor increases linearly instead of being exponential with time? Is it because of constant Vout?
@sambenyaakov2 жыл бұрын
Two reasons: vout is approximately constant voltage and the resistance of L is low so the time constant is very long and we are are just at the beginning of the exponential curve
@AltayBrusan4 жыл бұрын
thanks
@sambenyaakov4 жыл бұрын
👍
@sudhanshutelrandhe58575 жыл бұрын
great
@sambenyaakov5 жыл бұрын
Thanks
@kotarakotara2362 жыл бұрын
WHAT IS the effect of entilrely removing the inductor ....the rule of vout = d* vin is still completely valid even if no inductor exist ??? or just the inductor ensures large amounts of current supply ??
@sambenyaakov2 жыл бұрын
Without the inductor there will be no regulation The output cap will be charged to input voltage
@kotarakotara2362 жыл бұрын
@@sambenyaakov dr as if you stating that as long as we run our converter in the continous mode we wont need regulation (ices and feedback networkds) as it can be done by the inductor(with proper design ) ?
@srinivasuv44363 жыл бұрын
Hello Sir, I have question In the Buck convertor , If Inductor value is more than calculated value what will be impact on Vout? For example: calculated value is 68uH and I will use 300uH Inductor.
@sambenyaakov3 жыл бұрын
In general, there is not much change as far as voltage regulation. But: on the pro side: ripple will be lower. On the con: slew rate will be slower (the ability to ramp up the inductor current in case of large load change)
@srinivasuv44363 жыл бұрын
@@sambenyaakov hello Sir, thank you very much for answer, sorry for the late reply.
@lenazahron17656 жыл бұрын
Sir do you have a video about Full bridge DC-DC converter ?, or could you please recommend to me a book with a lot of exercises about Power electronic ( AC-DC, DC-DC, DC-AC) thank you for the videos
@sambenyaakov6 жыл бұрын
Thanks for comment. There are good power electronics books. I am not sure which include exercises.
@anant8146 жыл бұрын
Power electronics by D. Hart, Fundamentals of Power electronics by R.Erickson, Elements of Power electronics by P.T.Krein
@abhishekdwivedi5566 жыл бұрын
Dear Professor, can this be another explanation of negative spike? This is before the buck converter explanation. " since inductor current can't change instantaneously. So current will continue to flow and keep on sucking charge out of the right side of the switch node. So the switch node will see a negative spike."
@sambenyaakov6 жыл бұрын
Hi Abhishek, please send me the time coordinate (minute) of the location you are referring to.
@abhishekdwivedi5566 жыл бұрын
Sir, I was referring to time around 9:00 minutes.
@sambenyaakov6 жыл бұрын
"keep on sucking charge out of the right side" Current can flow only exist in a closed loop.
@abhishekdwivedi5566 жыл бұрын
But sir, as you explained , assume some imaginary resistor, which is actually not present. So I think current can't flow. Then I don't understand it intuitively. Mathematically since di/dt = towards minus infinity so Voltage across the inductor will also be towards minus infinity.
@sambenyaakov6 жыл бұрын
The mathematical explanation is is V= L dI/dt/ The intuitive is indeed the the inductor's " attempt to keep the current flowing. I was somewhat uneasy by "sucking charge" since it has the connotation of just charge moving while we need to look for the current loop.
@crestedeagle47406 жыл бұрын
Dear Sir when the switch is Open, the charges from output capacitor wont flow through Load,R? If it does then how does the output voltage remain constant as charges stored on capacitor are that from ripple? I am confused about capaitor role
@sambenyaakov6 жыл бұрын
I am not sure I followed you question. The role of the output capacitor is to keep attenuate the ripple so the load sees a DC voltage with some ripple on it. In a CCM Buck the inductor current always flows to the output. Does this answer your question?
@crestedeagle47406 жыл бұрын
Thank you sir for your response. When switch S is opened, the inductor tries to maintain the current and therefore provides current to the load. The same way charges are also stored on capacitor, will the capacitor try to discharge itself through load aswell? what happens to the charges on capacitor? Because I watched a video where it was stated that the capacitor grounds the high ripple current, the term grounding was quite ambiguos to me. Can you please shed light on what happens to capacitor as regarded to the charges on it?
@sambenyaakov6 жыл бұрын
At steady state, the average inductor current is equal to the load current while the inductor ripple current is passing through the low impedance of the capacitor which is "shorting" it. This is why the ripple voltage is low.
@crestedeagle47406 жыл бұрын
Thank You sir :)
@nibzlegend996 жыл бұрын
What if I have an output power instead of current , in my case it's 5 watts. Do I use Vout/R as my Average to find the minimum inductance?
@sambenyaakov6 жыл бұрын
Yes, but R for the maximal expected.
@nibzlegend996 жыл бұрын
Thank you sir for the reply. Can you give me tips on how to approximate the values for R , C and L. I am trying to simulate and build an open loop buck converter, stepping down 25 volts to 15 volts. Can you give me tips ? How can i choose a capacitor that would guarantee me a ripple voltage of less than 0.5%? Appreciate your sir most useful video I found on youtube on Buck converters is your video
@sambenyaakov6 жыл бұрын
First thing is to choose the frequency and decide on current ripple of L this gives you the value of L. You choose then C for desired ripple voltage given the ripple current. Good luck.
@nibzlegend996 жыл бұрын
Ok sir, I have found another formula similar to your formula for approximating C minimum. The problem is both use Ioutput which I am not given in my design problem. Instead I was given Poutput to be 5 Watts. I found out the resistor rated load value by P = Voutput^2 / R and got a certain number for R. Then I used Vouput/ R to get the value of I output. I am not sure If I did the right steps to get I output. But many values rely on it and It is cruicial that I get it right. Could you tell me if this is the right way to compute it? Appreciate you sir
@willlove99633 жыл бұрын
It was better to mention that this is during transition period
@sambenyaakov3 жыл бұрын
?
@colin551112 жыл бұрын
A few important points have been missed. Here is a much clearer, easier-to-understand explanation: Forget about the capacitor. It is only present to smooth the output but it has no control over the output voltage. The output voltage is entirely determined by the inductor. When the MOSFET turns ON, the inductor acts like a low resistance and the voltage on the load rises. At the same time the inductor produces magnetic line of force - called magnetism - and this magnetism is stored in the ferrite material surrounding the inductor. When the voltage across the load reaches a certain voltage (this voltage is actually LESS than 5v for a 5v output!!)the MOSFET turns OFF. Now, when the supply to an inductor turns off INSTANTLY, the magnetic lines of force stop being produced (this is called EXPANDING FLUX)and the magnetism stored in the ferrite material delivers magnetism to the turns of wire in the inductor to produce a high voltage in the opposite direction to that supplied by the MOSFET. Now, here's the amazing part. The left-hand end of the inductor produces a negative voltage and the right-hand lead produces a positive voltage. The inductor will now deliver energy to the load to give the load a little more voltage to raise it to 5v. But for the inductor to be able to "push-out" its energy from the right-hand lead, it must have the left-hand lead "fixed" At this pert of the cycle the MOSFET is turned-OFF and so it does not provide any "fixation point" for the left-hand lead. This is where the high-speed diode comes in. The left-hand lead produces a negative voltage and this voltage "flips the diode over" and its cathode(k) drops to -0.3v and it cannot drop any further. This gives the inductor a "stopping point" and the magnetic energy in the inductor can now be delivered to the load. Now you know how the circuit REALLY works. Colin Mitchell www.talkingelectronics.com
@sambenyaakov2 жыл бұрын
Sorry but your explanations are incorrect. E.g. the capacitor is essential and the energy us stored in the air gap and in the ferrite.