Inductors and Current - Answers to Questions

[@SaintAngerFTW]

This channel deserves a million subs.....

[@Anilyadav-rb8ft]

Excellent lecture. Watching your channel from India

[@Thoughtflux]

I had the same exact doubt. Thank you for your lectures. I think i will watch all of 'em.

[@dabay200]

Excellent video, but I don't understand how the voltage across the inductor when "charging" it in a DC circuit can ever be higher than the source voltage, as for energy to be "pumped" into an inductor the source voltage must be higher, otherwise the inductor is the one supplying the energy and is thus "discharging".

[@magical261]

When the inductor 'charges', the voltage across it is limited by the source voltage. It cannot, therefore, exceed the source voltage. When the switch is opened, the sudden collapse of the magnetic flux induces a voltage 'spike' that can exceed the source voltage. It is only in this 'discharging' state that a high voltage occurs. Nb Despite the high voltage, the inductor generates slightly less power than it receives, as there are always losses.

[@SaintAngerFTW]

Thank you..... SIR!

[@56r56ful]

Is there any video on how capacitors and inductors interact with each other?

[@gregorykotoch5045]

I know there can be voltage without current, but how can there be current without voltage? Doesn't this contradict ohms law?

[@jboy6944]

Voltage is the potential between two point. High voltage means high potential. At 0v there’s still potential. In the real world it’ll be something like 0.12v, but if you probe a battery from negative to positive you’ll have negative voltage. So there’s always potential to do work. The question is at which rate.