Instantaneous Centre Method

Instantaneous Centre Method
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Lecture By: Mr. Er. Himanshu Vasishta, Tutorials Point India Private Limited.

[@TutorialsPoint_]

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[@bca6875]

Easy to understand. Nice pronunciation. Thanks.

[@mohitjoc25]

I never seen channel like this..... Great..awesome . All... From. Management to. Engineering and computer all are there in one channel ......👌 superb

[@just_arjun]

Thank you sir! But please link related videos in the description!

[@dattaborude2286]

English समझ आता है, लेकीन थोडा आसान हिंदी लगता है, इसलीये youtube पर देखते है,लेकिन यहा भी अंग्रेज बैठे हुये है..🤐

[@mads_kyu.t]

Can I ask what is the difference of Instantaneous axis of velocity and the Instantaneous Center or Center of Rotation?

[@guptajicodes]

Sir ,what is your area of expertise?

[@Himanshuratawal]

Uncle ji english m samjh aata to class m hi samjh jate KZbin p ye video nhi dekh rahe hote

[@sarthakbaghel8652]

english ki coaching bhi lagwa le Noobde

[@akhilkrishnahere]

What about non hindi speakers

[@kalamazath9304]

Thanks dude I love your teaching ,😍😍😍😍😍

[@daviddikibo2657]

Legend.

[@shivasmart967]

tq sir

[@pushkarshukla1229]

I like your teaching, but I would like to point out a mistake here. At 5:00. ob/IB = oa/IA .... but this ratio is not equal to omega

[@shivbhawanshivhare8908]

Why Mr. Pushkar you think that it is not equal to omega? It will be equal to omega. Because ob and oa are nothing but properly scaled values of velocities Vb and Va respectively. I would like to emphasize it more clearly that Va/IA=Vb/IB=Vba/AB=omega, replacing Va=oa, Vb=ob, Vba=ba, provided proper scaling of velocity triangle, we get, oa/IA=ob/IB=ba/AB=omega. I hope you will catch it now.

[@shewagdhanush1391]

@@shivbhawanshivhare8908 Bro you replied to a 2 year old comment😂

[@shivbhawanshivhare8908]

@@shewagdhanush1391 Yes Shewag!! as an interesting doubt, I couldn't stop to clear it out for others who will come ever to this comment.😊

[@edutechguruengineeringlear4280]

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[@kadiryilmaz7378]

thank you, love you

[@ronak226]

great great content !!!

[@endlesslearnwithfun1345]

Nice! Make some more videos on important topics of THEORY OF MACHINE

[@jitendralodhi4570]

Thank u so much sir..

[@aditit306]

Thank you sir 😊

[@safi-ur-rahmankhan4669]

please tell me how v=w(IA) or v=w(IB) produces

[@amit1996tg]

Assume That IB is a Link rotating at w rad/sec and Vb is Velocity of Point B perpendicular to IB. now w = v/r therefor w = Vb/IB (IB = R) so that Vb = w . IB In similar way you can derive for Va by Assuming IA as Rotating link. Va = w. IA .

[@safi-ur-rahmankhan4669]

Thanks a lot Sir

[@vijaydwivedi3193]

Thanks

[@shaikabraarbasha8315]

Very low sound

[@VikashKumar-hw4qe]

Ok sir

[@pankajdochania6791]

You are superrrrrrrrrr

[@henselwilsongoveas9147]

Vector diagram is wrong.. How can a velocity upwards and and a velocity rightward give a velocity that's downwards.. You've joined the tail of two vectors.. Where you're supposed to join the head with tail

[@edutechguruengineeringlear4280]

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[@krishnachandr127]

you are a god

[@Himanshuratawal]

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[@mohammadayub8110]

love from Pakistan thanks

[@lalitnsgpatil4347]

Problem solve karke bathau

[@Mech.Masters]

Explanation is completely based on theory, there is no logic and practical application. Professors need to do more homework.

[@sooradalakshmi5103]

ur english pronunciation and audio quality is ok but ur explanation is bad wasting time on useless points explanation and missing important points of explanation like why Vba is at3:28 and exactly what velocity wrt what os 0 at1:24 it looks like ur just telling what points u remembered before video

[@edutechguruengineeringlear4280]

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[@theelements1588]

bohat ghaatiya padata h

[@bhaskardeb8342]

Mur muratu bujaaiso

[@aadarshmagar98]

Bahot ganda padatha hain tu focus on example theory to hum khud bhi padh lenge

[@aquapisces]

You could have taught it better🥱

[@ajaykumaryadav2365]

Velocity Link ke perpendicular hota hai galat galat mat padha

[@angryengineer2115]

angreji

[@sushyanthsridhar4972]

sounds drunk!