Integer linear programming branch and bound method operation research (Lecture.22)

[@shreyajain6622]

Very well explained sir..thnxx a lot sir apne mri bht saari prblms clarify krdi saara kuch itna ache se explain krke...🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻

[@Cartooz0111]

Hence Prove that , Only one Example can Explain all the concept of Particular Method , Only if teacher teach like you sir. Thank you sir..❤❤

[@swatisaini4857]

Thank you very much sir! You are solve my problem.(Integer Programming Problem). Now,I can solve it.🙏

[@mohdkaifsalmani4513]

Thankyou so much sir for clearing this method... Tomorrow is my exam

[@SandeepKumarGour]

Welcome

[@shahrozmukhtar8235]

Thanks a lot...❤️ When someone does any work simply then almost everything becomes easy to learn and to see..

[@soniyadav2639]

Very nice &easy way explanation sir ......bhut achhe se smjh aa gya h si.. Time to jyada lga h bt concept 💯% clear ho gya h ......... Thank you very much sir🙏🙏

[@SandeepKumarGour]

welcome..keep watching my videos.

[@ArshadKhan-ts1gp]

patience are must important for this video .....because question is too lengthy ....btw your teaching skills are good .....thank you

[@SandeepKumarGour]

Welcome.☺

[@shivangijha6373]

@@SandeepKumarGour sir I have a problem ..pls share Ur phn no

[@tamannamishra8236]

@@shivangijha6373 whatsapp me on 7972647602 I m doing MSc in maths from NIT surat

[@agooglepage1400]

At 13:48 why didn't you placed value of x1 as 4 in x1+x2

[@kingsleysuccessikani3695]

Thank you so much sir. It was neatly and accurately explained. Even without understanding the language, I was still able to fathom everything you explained.

[@rohandevaki4349]

at 25:48 , for subproblem-6 it is infeasible. please correct it, remaining things are correct.

[@Algomadeeasy]

U r correct

[@kalaimathip8224]

I am from tamilnadu .. I don't know hindi.. Even I too understand tis concept by ur clear explanation step by step.. Tq vry much sir.. I'll suggest this video to my frnds.. Best tutorial ever..

[@SandeepKumarGour]

Thank you so much for your support..☺️

[@sudhir_2086]

Neatly and accurately explained, thank you Sir!!

[@SandeepKumarGour]

Thank you,☺ Keep watching my videos.

[@shivangijha6373]

How sir has placed thr value (3,3)and value of z in sub problem ..AAP explain karsakte ho

[@gulabpatel3454]

@@SandeepKumarGour Plz explain,Point B par Z ki value 22.5 aa rahi hai

[@studystuffskills5564]

@@gulabpatel3454 aree 8x1 +5x2 equation hai

[@prarthanapathak8100]

ur technique of teaching is too good...keep it up sir and save our life...🤗

[@SandeepKumarGour]

Thank you very much..😊

[@shashankrawat3228]

Thanku sir 🙏 apne bhut acche se explain kiya hai ab ye method samjh a gya.

[@ShivamKumar-ci1yt]

Really marvelous 😍👍 Way of ur teaching

[@myounas4456]

Beautifully explained.....

[@agooglepage1400]

Have seen a lot of videos, this is the best one

[@binooprajapati71]

Sir l do understand how point lies b/w 2&3 then eq become x1greater then 2 And x1 is greater 3

[@AnkitYadav-lf4ys]

Thank you so much sir for explaining branch and bound method

[@vikashbharadwaj1542]

Thank you thank you thank you sir for this lovely explanation ❤️🙏

[@SandeepKumarGour]

thank you so much😊

[@artisahu4605]

Thank you so much sir ji aapka sabhi video bahut achcha hai ake bar me samjh aa jata hai 💫🙏✍️

[@SandeepKumarGour]

Thank you for your support.

[@rhishikeshdadsena8058]

Very nice explanation sir my all doubts is clear ....🙏

[@SandeepKumarGour]

Thank you😊

[@prashantsingh-lf5db]

Thankyou very much sir. Books seto ye topics smjh hi nhi aate. I will be passed in operations research only due to you

[@sripriyanka]

Very nicely explained thank you

[@SandeepKumarGour]

thank you so much😊

[@ahmadhammad5375]

Great explanation ❤

[@vivekkrupa1481]

At 11:07 how did you get (3,3) using x1

[@dikshantsharma6518]

elimination method bro

[@sandeepvishwakarma572]

jiska koi jawab n ho use lajawab kahate hai lajawab sir

[@SandeepKumarGour]

thank you so much...😊

[@phonglehong2300]

Thanks you very much, sir! Best respect from Vietnam!

[@mayamikarmakar6838]

Clearly explained. Thank you. All my doubts are cleared.

[@SandeepKumarGour]

welcome

[@ikramulhoque7642]

Thank you sir from Bangladesh👍

[@tanishkaachaturvedi2173]

sirji youre just toooooo greatttttt. thank you for the brilliant explanation!!!

[@mathlearning2453]

May you live long!

[@Shailendraadesh]

very nice video, concepts are well explained

[@prayagrajchanda1290]

Thanks a lot for this video sir...cannot explain you how much this video helped me... Thanks a lot

[@ksdivya100]

thank you. but what about the the second top x2 value i.e. x2 = 2.25? we wont branch that further?

[@SandeepKumarGour]

we select max value for branching. No need to branch x2 further.

[@mylittlechinnunannuparrot6599]

Bhut acha explain kiya thanks

[@SandeepKumarGour]

thank you..pls like n share😊

[@ishaantonk159]

Thanks, Your this video made me feel confident for my upcoming exam.

[@BTech.Saimon]

7:40 Z at B should be 22.5

[@monirulist]

well explained. Every task understood very easy. Thank you Sir.

[@SandeepKumarGour]

thank you so much😊

[@ridhisingh1165]

Good explanation 👍👍👍👍

[@SandeepKumarGour]

thank you

[@ravindupasan172]

language doesn't matter i understood 100%

[@pragatichauhan7706]

Thanku so much sir,very helpful video Now I can solve branch nd bound method.🙏🧡

[@leenakukreja6444]

Perfectly explaination sir

[@SandeepKumarGour]

thank you

[@skmdibrahimkhalilullah9097]

Thank you, Sandeep

[@sahebking8931]

Superr..sir g.. Maja aa gya ...bahut Achcha samjh aaya .. Kal exam me achche se karenge.... RTU ka..exam me... Superrrr ..

[@SandeepKumarGour]

Best of luck👍

[@TopDownApproach]

Exam 26 ko hai

[@sahebking8931]

@@TopDownApproach ..ha bhai

[@baltwitch8032]

itne din ki chutti de di bc padne ka man hi nahi kr raha.... kal raat ko hi padunga.

[@baltwitch8032]

ek cutting plane ki bhi bana do sir .... usme dikkhat aa rahi h

[@Stevejobs-m4m]

aap to ache padhate ho sir ji

[@SandeepKumarGour]

Thank you😊

[@soorajpal3073]

Thanks sir for proper explanations

[@pankajdongre773]

How u find max z = 41.25 at point B at initial stage....Plz explain

[@SandeepKumarGour]

Watch the following video kzbin.info/www/bejne/qqa7qIyDnNWdbck

[@trilochansahu8498]

nice sir l am solve any branch bound method problem. 🙏🙏🙏🙏

[@fahadikram5459]

super super like thank you so much, our university professor dont teach us this way

[@SandeepKumarGour]

Thank you very much😊 Keep watching my videos.

[@himanshupant1717]

Very helpful video thank you

[@SandeepKumarGour]

welcome..keep watching.

[@EducatorOP]

fabulous teaching ty

[@ZunairAbass-kb1ft]

Great work 🎉

[@SandeepKumarGour]

Thank you😊

[@sailajakavitha3644]

thank u sir 😊😊..very clean and understood 😊

[@SandeepKumarGour]

Thank you for valuable comment..☺

[@sailajakavitha3644]

+Sandeep Kumar Gour 😊😊

[@sarimhussain6095]

Well Explained !

[@SandeepKumarGour]

Thanks

[@Patent_Advisory]

Solve the mixed integer programming model given below by applying the branch-and-bound method step by step. min z = x1 - 2x2 constrains: -4x1 + 6x2

[@ayanokojiD]

Kitna time milega

[@priyanshurajs400]

very VERY nicely explained. Kudos !!

[@kashifsultan2221]

Well define sir!

[@AnkitSaiyan]

It's lengthy but you made it easy ... Thank you sir

[@hafsaislam1307]

This is sooooo helpful,Thank youuuu sooooo much

[@harshittiwari5725]

Thank you so much sir. It was neatly and accurately explained.

[@SandeepKumarGour]

Thank you so much😊

[@prasadbhosale1731]

Thank you sir Very very helpful and effective teaching .

[@SandeepKumarGour]

thank you so much😊

[@abdulahadshaikh2003]

At 24.00 means in sub matrices 5 there is you got (4,1) but I am getting (4,1.8)

[@PavanKumar-ef1yy]

thankyou so much sir. excellent.

[@SandeepKumarGour]

Welcome

[@dr.pragyamishramathsonline4646]

very nice presentation in simple words

[@SandeepKumarGour]

Thank you so much😊

[@kirankhalid9588]

I loved your videos, Your teaching skill is mindblowing... keep it up sir...Love from pakistan

[@misspallavi2642]

Very nice 👍 sir thnku so much sir

[@SandeepKumarGour]

thax

[@sonali5687]

Thank you sir ... Sir pls make a video on dynamic programming to solve lpp , if it's possible

[@jntmukherjee85]

Excellent sir.. hope you will upload more videos on O.R.

[@SandeepKumarGour]

thank you so much...😊 For more videos watch playlist Operations Research in hindi | Computer Oriented Optimization Technique (COOT): kzbin.info/aero/PLEjRWorvdxL6ZDh5HbigDyuwgeW2WW0zs pls like, share and subscribe my channel.

[@tayyabashaikh7294]

very helpful۔۔۔Thanks۔۔۔

[@mathematicsadda1184]

Thank you so much sir,such a thankful video🙏🙏🙏🙏🙏🙏🙏

[@SandeepKumarGour]

welcome..pls like n share my videos

[@mathematicsadda1184]

@@SandeepKumarGour okk sir🙏🙏

[@oneminutewatch1056]

Subhan Allah Bahut khoob bhai

[@SandeepKumarGour]

Thank you very much brother..☺ Keep watching my videos.

[@mrrajendra1757]

Very nice 👍👍👍👍👌👌👌👌 Sir ji

[@brainfortinstitute77]

Thank you sir very helpful video for me

[@krishankumarswami9034]

Sir please video for simplex method for bounded variable

[@cool_mithlesh1615]

Thanku sir for solving doubt free well done sir ..... 👍 👍

[@SandeepKumarGour]

Thank you for your support. Please like and share my videos.

[@haroonnaeem6826]

best video❤

[@simranthakur7038]

Tq so much sir Awsm explanation

[@SandeepKumarGour]

Thank you☺

[@MohdIrfan-pi5fr]

Very suitable mja aaya thankyou so much you

[@jyotikumawat7254]

Explain very nice

[@SandeepKumarGour]

thank you so much😊

[@mathlearning2453]

Mashallah . Well explained

[@ChinmoyKumarRoy]

x2 lies betwee 1&2 Then how it could be x2 2....little bit confusing 15:06

[@SandeepKumarGour]

Es method me hm variable ki value ko integer consider krte h, solution me " 1 < x2 < 2 " aaya h, that means yha se solution nhi nikla h, esly es region k alava dusra region dekhne k ly x2 ≤1 and x2 ≥ 2 liya h. Thax for watching☺️

[@deepjyotichakraborty8739]

Well explained.

[@mananchoudhary9896]

Thanks for teaching🙏

[@sadiabhatti6323]

U r excelent sir

[@SandeepKumarGour]

Thank you😊

[@karunachandrakar8498]

Very nice sir👍

[@SandeepKumarGour]

Thank you😊

[@lampbearer851]

Sir kya ye possible ha ki Z ke jis maximum value k liye branching kar rahe ha usse koi v optimal solution na nikle?? Aise me kya karna chahiye? Second maximum ke liye solve karna chahiye?

[@Dk0712-2k]

If x1 and x2 both are non integer then we can branch only x1 or x2 also???

[@MaTLuB13120]

Suppose we choose 2.25 then the interval becomes 2

[@sanjaydavande7708]

If in this problem given for "min" form.so same procedure for solving & we have choose Xb fraction value minimum or maximum?here max problem so choose max fraction value right.so if for min which fraction value we have to choose.

[@SandeepKumarGour]

Process remain same. Note: value of objective function as lower bound for minimization problem ( value of objective function in the subsequent steps can not be less than lower bound) and upper bound for maximization problem( value of objective function in the subsequent steps can not be more than upper bound)

[@harsimransingh3895]

Thankyou very much sirji

[@trilokinath_sambhu]

Make video on kuhn Tucker conditions for non linear programming

[@prathameshshelke4234]

Last sub prob. Me agar x2=1 lete to wo z=45 hota he phir soln me kya likhte????

[@SandeepKumarGour]

Tab yah infeasible solution ho jata or hmara optimal answer Max Z=39 ho jata

[@prathameshshelke4234]

Thanks 😃

[@rahulcharan4122]

Maximi Z= X1 + X2 Subject to- 3X1 +2X2

[@danishanjum5763]

mind blowing sir

[@SandeepKumarGour]

welcome..keep watching my videos.

[@chandrimad5776]

thank you so much... you saved me before exam!

[@SandeepKumarGour]

Welcome😊 Thank you for your support.

[@radigitech745]

Great explanation

[@subhankhan9877]

Sir agar constraints three variable ke ho to branch and bound method less apply hoga

[@tc_jat]

sp4 have the higer value of z,then why it's not selected at the last of solution?

[@SandeepKumarGour]

for the maximization problem, we select value of objective function as upper bound. In this case value of objective function in subsequent steps can not be greater (or excess) than this obtained upper bound. thax☺️

[@sumantakarmakar1679]

Nice explanation

[@ro2a.eslam.]

Great .. Thank you

[@SandeepKumarGour]

thank you so much for your support..like n share my videos.