Integral of sqrt(1-x^2) (substitution + trigonometric identities)

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Integrals ForYou

Integrals ForYou

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✍🏼 integralsforyo... - Integral of sqrt(1-x^2) - How to integrate it step by step using integration by substitution!
🔧 𝐔𝐬𝐞𝐟𝐮𝐥 𝐯𝐢𝐝𝐞𝐨s
sin(arccos(x)) = • sin(arccos(x))
cos(arcsin(x)) = • cos(arcsin(x))
✅ 𝐃𝐞𝐫𝐢𝐯𝐚𝐭𝐢𝐯𝐞 𝐭𝐨 𝐜𝐡𝐞𝐜𝐤 𝐭𝐡𝐞 𝐬𝐨𝐥𝐮𝐭𝐢𝐨𝐧
Derivative of (1/2)(arcsin(x) + x*sqrt(1-x^2)) = • Derivative of (1/2)(ar...
🔍 𝐀𝐫𝐞 𝐲𝐨𝐮 𝐥𝐨𝐨𝐤𝐢𝐧𝐠 𝐟𝐨𝐫 𝐚 𝐩𝐚𝐫𝐭𝐢𝐜𝐮𝐥𝐚𝐫 𝐢𝐧𝐭𝐞𝐠𝐫𝐚𝐥? 𝐅𝐢𝐧𝐝 𝐢𝐭 𝐰𝐢𝐭𝐡 𝐭𝐡𝐞 𝐢𝐧𝐭𝐞𝐠𝐫𝐚𝐥 𝐬𝐞𝐚𝐫𝐜𝐡𝐞𝐫:
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Пікірлер: 38
@IntegralsForYou
@IntegralsForYou 3 жыл бұрын
🔍 𝐀𝐫𝐞 𝐲𝐨𝐮 𝐥𝐨𝐨𝐤𝐢𝐧𝐠 𝐟𝐨𝐫 𝐚 𝐩𝐚𝐫𝐭𝐢𝐜𝐮𝐥𝐚𝐫 𝐢𝐧𝐭𝐞𝐠𝐫𝐚𝐥? 𝐅𝐢𝐧𝐝 𝐢𝐭 𝐰𝐢𝐭𝐡 𝐭𝐡𝐞 𝐢𝐧𝐭𝐞𝐠𝐫𝐚𝐥 𝐬𝐞𝐚𝐫𝐜𝐡𝐞𝐫: ► Integral searcher 👉integralsforyou.com/integral-searcher 🎓 𝐇𝐚𝐯𝐞 𝐲𝐨𝐮 𝐣𝐮𝐬𝐭 𝐥𝐞𝐚𝐫𝐧𝐞𝐝 𝐚𝐧 𝐢𝐧𝐭𝐞𝐠𝐫𝐚𝐭𝐢𝐨𝐧 𝐦𝐞𝐭𝐡𝐨𝐝? 𝐅𝐢𝐧𝐝 𝐞𝐚𝐬𝐲, 𝐦𝐞𝐝𝐢𝐮𝐦 𝐚𝐧𝐝 𝐡𝐢𝐠𝐡 𝐥𝐞𝐯𝐞𝐥 𝐞𝐱𝐚𝐦𝐩𝐥𝐞𝐬 𝐡𝐞𝐫𝐞: ► Integration by parts 👉integralsforyou.com/integration-methods/integration-by-parts ► Integration by substitution 👉integralsforyou.com/integration-methods/integration-by-substitution ► Integration by trig substitution 👉integralsforyou.com/integration-methods/integration-by-trig-substitution ► Integration by Weierstrass substitution 👉integralsforyou.com/integration-methods/integration-by-weierstrass-substitution ► Integration by partial fraction decomposition 👉integralsforyou.com/integration-methods/integration-by-partial-fraction-decomposition 👋 𝐅𝐨𝐥𝐥𝐨𝐰 @𝐢𝐧𝐭𝐞𝐠𝐫𝐚𝐥𝐬𝐟𝐨𝐫𝐲𝐨𝐮 𝐟𝐨𝐫 𝐚 𝐝𝐚𝐢𝐥𝐲 𝐢𝐧𝐭𝐞𝐠𝐫𝐚𝐥! 😉 📸 instagram.com/integralsforyou/
@AyooTube
@AyooTube 5 жыл бұрын
2:22 You re lacking a 1/2 multiplying the sin(u) (besides the one outside of the parentheses)
@IntegralsForYou
@IntegralsForYou 5 жыл бұрын
Hi, Ayoo Tube, you're right, I forgot to write it, but in 2:37 I realize it and wrote it ;-D
@lorenzoortiz8966
@lorenzoortiz8966 7 жыл бұрын
you know dude?? i kinda enjoy a little conversation with my math. makes me feel spooned
@wallflower5672
@wallflower5672 Жыл бұрын
Thanks a lot for this.....
@IntegralsForYou
@IntegralsForYou Жыл бұрын
My pleasure! 😊
@KimSeokjinnie-bs5sh
@KimSeokjinnie-bs5sh 4 ай бұрын
Is it wrong if i Pose x=cos(u)???🛑
@IntegralsForYou
@IntegralsForYou 4 ай бұрын
Hi! No, it is not wrong! Your answer will have arccos(x) instead of arcsin(x) since both derivatives are the same except for a constant: Derivative of arccos(x) = -1/sqrt(1-x^2) = -(1/sqrt(1-x^2)) = -Derivative of arcsin(x) Integral of sqrt(1-x^2) dx = Substitution: x = cos(u) ==> 1-x^2 = 1-cos^2(u) = sin^2(u) dx = -sin(u)du Integral of sqrt(sin^2(u)) -sin(u)du = = - Integral of sin(u)*sin(u) du = = - Integral of sin^2(u) du = sin^2(u) = (1/2)(1-cos(2u)) = - Integral of (1/2)(1-cos(2u)) du = = (-1/2)*Integral of (1 - cos(2u)) du = = (-1/2)*[ Integral of 1 du - Integral of cos(2u) du ] = = (-1/2)*[ u - (1/2)sin(2u) ] = sin(2u) = 2sin(u)cos(u) = (-1/2)*[ u - (1/2)2sin(u)cos(u) ] = = (-1/2)*[ u - sin(u)cos(u) ] = sin(arccos(x)) = kzbin.info/www/bejne/b4u0q3qum5itnpY = sqrt(1-x^2) = (-1/2)*[ arccos(x) - sin(arccos(x))cos(arccos(x)) ] = = (-1/2)*[ arccos(x) - sqrt(1-x^2)*x ] = = (1/2)*[ -arccos(x) + x*sqrt(1-x^2) ] + C Hope it helped! 💪
@KimSeokjinnie-bs5sh
@KimSeokjinnie-bs5sh 4 ай бұрын
@@IntegralsForYou omg thank you so much 💖 yeah it's really helpful ☺️iam so grateful that you answered me accurately and in a short time 🙂‍↕️✨
@IntegralsForYou
@IntegralsForYou 4 ай бұрын
@@KimSeokjinnie-bs5sh It is my pleasure! ❤ If you subscribe to this channel and to the new one about derivatives it would be a huge help! Thank you! www.youtube.com/@DerivativesForYou ❤
@KimSeokjinnie-bs5sh
@KimSeokjinnie-bs5sh 4 ай бұрын
@@IntegralsForYou💖 iam already a subscriber for this channel hhh And of course I will support your new channel 🩷 you deserve it
@IntegralsForYou
@IntegralsForYou 4 ай бұрын
@@KimSeokjinnie-bs5sh Thank you very much! ❤
@giftadiawa1887
@giftadiawa1887 7 жыл бұрын
how did we get to arcsin in number 3?
@IntegralsForYou
@IntegralsForYou 7 жыл бұрын
Hi Gift Adiawa! You can consider the first expression x=sin(u) and apply arcsin on both sides: x=sin(u) arcsin(x)=arcsin(sin(u)) arcsin(x)=u
@christophsilva6816
@christophsilva6816 3 жыл бұрын
mais um inscrito
@IntegralsForYou
@IntegralsForYou 3 жыл бұрын
Obrigado! 💪
@daniellenel7118
@daniellenel7118 7 жыл бұрын
HOW DOES THIS VIDEO NOT HAVE ANY SOUND?!?!?!?!?
@dan55800
@dan55800 6 жыл бұрын
It is not needed.
@erinmeyers-t9w
@erinmeyers-t9w 4 жыл бұрын
tank!!
@IntegralsForYou
@IntegralsForYou 4 жыл бұрын
You're welcome! 😉
@kaoutharmaarafi4962
@kaoutharmaarafi4962 7 жыл бұрын
thankss
@IntegralsForYou
@IntegralsForYou 7 жыл бұрын
:-D
@nuryohan1511
@nuryohan1511 5 жыл бұрын
Writing too small
@paulagabrielarojasmontejo5374
@paulagabrielarojasmontejo5374 4 жыл бұрын
Thank you so much. This channel is great.
@IntegralsForYou
@IntegralsForYou 4 жыл бұрын
Thank you! I am very proud of my channel, and I am prouder of it every time I read comments like yours! 😊
@陈佳铭-g7y
@陈佳铭-g7y 5 жыл бұрын
thank you!!!! this channel is so underrated!!!
@IntegralsForYou
@IntegralsForYou 5 жыл бұрын
Thank you very much! ;-D
@jagdishtiwari9254
@jagdishtiwari9254 3 жыл бұрын
Can I get a solution of underoot 1-x^3
@IntegralsForYou
@IntegralsForYou 3 жыл бұрын
Hi! I'm sorry but I think it is a non-elementary integral...
@lalgerielibre9519
@lalgerielibre9519 2 жыл бұрын
Best integration channel ever
@IntegralsForYou
@IntegralsForYou 2 жыл бұрын
Thank you very much! 😊😊
@googoo8462
@googoo8462 6 жыл бұрын
How come i see inconsistencies?
@antoinesicot3879
@antoinesicot3879 6 жыл бұрын
Sqrt(cos(u)^2) is not always equal to cos(u)
@IntegralsForYou
@IntegralsForYou 6 жыл бұрын
Hello Antoine Sicot, you will find a good explanation in this link: math.stackexchange.com/questions/1118400/trig-substitution-why-can-we-ignore-the-absolute-value
@weamt8562
@weamt8562 3 жыл бұрын
Et si on a les bornes de notre intégrale de 0 à 2
@IntegralsForYou
@IntegralsForYou 3 жыл бұрын
Le domaine de sqrt(1-x^2) est [-1,1]: Intégrale de sqrt(1-x^2) dx de 0 à 2 = = Intégrale de sqrt(1-x^2) dx de 0 à 1 = = (1/2)(arcsin(1)+1*sqrt(1-1^2)) - (1/2)(arcsin(0)+0*sqrt(1-0^2)) = = (1/2)(pi/2+1*sqrt(0)) - (1/2)(0+0*sqrt(1)) = = (1/2)(pi/2) - (1/2)(0) = = pi/4
@weamt8562
@weamt8562 3 жыл бұрын
@@IntegralsForYou thank you so much 😊😊
@IntegralsForYou
@IntegralsForYou 3 жыл бұрын
@wéã MT Avec plaisir! 😉
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