Introducing Integration (4 of 4: Concrete examples)

[@AthanCondax]

This is beautiful. I’ve completed advanced differential calculus courses during my engineering degree and have never seen this topic so clearly presented. Eddie, you are a gem.

[@MartonMerritt]

I've been watching Calculus videos for a while now and no one....NO ONE!!!....has explained it better than you, Eddie. IMO, if a teacher cannot relate math to the real world, then they're not an effective one. Thanks so much for this.

[@seanmaclean706]

I'm studying a Bachelor of Education and Eddie is such an amazing resource. 1) He makes learning the content itself easy and, 2) I get a side-by-side comparison between my lecturers' teaching styles (who don't always teach well) and Eddie's (which is always clear and efficient).

[@LOLTRON4000]

I'm studying a bachelor of engineering at uni and your videos have been a life saver

[@avi12]

Level 1: An ordinary math teacher. Goal: Explain *how* Level 1M: Eddie Woo. Goal: Explain *why* and *how it works*

[@Chris-kh4rq]

This guy is an excellent teacher.

[@kye4840]

8:00 do you not put +c at the end as you would just take them away in the next step anyways. Everything that isn’t in terms of x (or any other variable) is irrelevant. Right?

[@carultch]

When finding the indefinite integral, you do put +C at the end. When finding the definite integral between two bounds of integration, you could include the +C, but it will eventually cancel out anyway and become irrelevant to the solution. So to keep it simple, you just assume C=0. There are examples, where you do keep the +C, and eventually use boundary conditions or initial conditions, to solve for what the +C equals. An application of this, is the deflection of beams, where you will generate two constants of integration after integrating a given function twice, and implement deflection=0 at the support points, to solve for the constants of integration. Sometimes a problem statement is phrased in a certain way, that you don't need to include the +C to be technically correct. Such as "find a function g(x), such that g'(x) = f(x)", where f(x) is given. The fact that the problem statement said "find *a* function", means that you are correct whether you included the +C or not, or whether you assigned your own value to C instead of just leaving it as an unspecified constant.

[@doctorcatnip2551]

Great class! Well done Mr Woo! Always a pleasure.

[@ArhamKhan05]

Thats marvelous sir you explained integration which is considered most difficult in a great and easy way, hats off to you. ❤ Thanks sir.

[@Qongrat]

Magic - I love these video series!

[@JavierBonillaC]

Eddie Woo is. Genius techer

[@razinreazabedin7404]

I had to figure it our for myself that integration means calculating the area. It was like "Wait, if you Integrate 2πr with respect to r, you get πr².... and if you do the same to 4πr², you get (4πr³)/3..." (0.0)

[@potatadiggary1125]

Sir, please come to england

[@simonebalducci8376]

Finally! I love your videos

[@ericsills6484]

How long will it take your peach schnapps to take effect? Oh, about 6-1/2 minutes :-)

[@LemonTreeNOTfree]

🤦 it is easier understanding then I got in my University, moreover, I doesn't speak English very well.

[@prabhatsharma3551]

Sir you are awesome teacher😃 Love the way to teach 😍 Keep doing 👍

[@varunsingh5317]

Super duper

[@fahimkarim9261]

Five stars bro✌🏼✌🏼✌🏼✌🏼✌🏼

[@JohnM...]

Integration is wonderful. But, try calculating Fourier Series without tic tac toe! It's especially tiresome and time consuming if doing PDE'S. Or, be really lazy and use mathematica.

[@carultch]

What do you mean by "tic tac toe"? Is this a mnemonic to do integration by parts?

[@Trev0r98]

The term "dx" is *NOT* "the width of the rectangle"; the term "dx" is *the arbitrary change of the width of the rectangle* .

[@robert19]

🤓 ok

[@nigaraliyeva7607]

I don't want my classmates find this video

[@apoorvchauhan7338]

I feel you

[@qualquan]

much too roundabout not direct enough