Limits on the integral seem slightly mistaken at 18:26. Just below the "bubble" should be phi=-pi+epsilon, just above the bubble should be phi=pi-epsilon. Thus the signs of the epsilons should be opposite of what is used in the video. While this does not affect the ultimate result in practice, the following evaluation is in principle wrong as the path crosses the "bubble" twice with the phis used in the video. Also, upon evaluating the primitive, there is an additional small error of not including the 'i's for the epsilon. Correct would be 2*(pi-epsilon)*i prior to taking the limit. And this also makes sense, as we have taken slightly less than the complete 2*pi trip around the circle.
@noahtaul2 жыл бұрын
Fun fact: if you integrate zbar counterclockwise around any simple loop, you get 2i times the area inside the loop!
@tdchayes2 жыл бұрын
5:49 The integral should be on t*dt not t^2*dt. The result is correct.
@TheLethalDomain2 жыл бұрын
I am only halfway though this video and this is the best introduction to integration in complex analysis I have ever seen.
@iabervon2 жыл бұрын
It's worth noting that you can have a primitive for 1/z with a branch cut anywhere you'd like (connecting 0 and infinity), but you can't have one without any branch cut. So there's no problem integrating along -1+it from t=-1 to 1 with the FToC if you just have your arguments go 0 to 2pi, but you can't do any circle around the origin without a hack.
@lifthrasir16092 жыл бұрын
Great lecture, please keep up the good work! Being a student who didn’t take a complex analysis course at my university, I’m really happy to find such content on KZbin.
@scp31782 жыл бұрын
?? For me as a former math. student at least one complex analysis course was mandatory, normally even a 2nd one (complex analysis II & Riemann surfaces) is usual for a master degree. (You can't understand analytic number theory without complex analysis) I agree with you: Michael's videos are good and inspiring work, that'll help you understanding several maths. sections.
@lifthrasir16092 жыл бұрын
@@scp3178 I’m doing a degree in applied mathematics and we have two specializations here in Ukraine: informatics and applied maths itself. I’d picked the first one, and that’s why some of the common math courses in my program were replaced with various CS courses such as algorithm analysis, cryptography etc. Though complex analysis is perhaps the only major “non pure” math branch I’ve missed.
@half_pixel2 жыл бұрын
Same here - got my master's in math but never took a complex analysis course since I was more focused on discrete stuff and CS. Very nice to have these videos to learn some complex analysis after the fact :)
@sinecurve99992 жыл бұрын
6:00 small error: the integral is integral[t, {t,0,1}] not t^2
@synaestheziac2 жыл бұрын
6:07 PENNultimate step yassss (please tell me this was an Easter egg in response to my comment on the weights/partitions video!)
@tdchayes2 жыл бұрын
18:30 The limits on the integral should be e^i(pi-epsilon) and e^i(-pi+epsilon). Again, the results are correct.
@Karatemaci2 жыл бұрын
Exactly!
@Re-lx1md2 жыл бұрын
I wish I had these videos when I took Complex Variables. Thank you for these!
@GenknownTutorial2 жыл бұрын
Finally, thank you. Hope you make more videos regarding Complex Integration.
@The1RandomFool2 жыл бұрын
Just a small note, when he takes the limit as epsilon goes to zero, it should be from the left, not right. Otherwise it actually crosses the point he's trying to omit. The result is the same, however.
@schweinmachtbree10132 жыл бұрын
at 7:43 you assume without justification (although I suppose it is 'intuitively obvious') that int_{gamma_1 + gamma_2} f(z) dz = int_{gamma_1} f(z) dz + int_{gamma_2} f(z) dz. To compute the integral without this assumption is not that bad; one just has to calculate the explicit parameterization of gamma_1 + gamma_2 (which on [0, 1/2] is gamma_1 at double speed and on [1/2, 1] is gamma_2 at double speed and delayed to be on the interval [1/2, 1])
@PunmasterSTP2 жыл бұрын
Complex integration? More like "Your videos are stoking my imagination." Thanks so much for making and sharing them!
@rogerr42202 ай бұрын
18:20 minor sign error, it should be -pi+epsilon and pi - epsilon
@MathEnthusiast-od8yu Жыл бұрын
i think that analyticty needs the continuity of first partial derivative of u(x,y) and v(x,y) over x and y
@aleksandervadla98812 жыл бұрын
Are you planting to do a video on conformal maps on polygons?
@sergpodolnii39622 жыл бұрын
At 18:00 to avoid the problematic point, should not the boundaries be like exp^(-i(Pi+epsilon)) to exp^(i(Pi-epsilon)) instead of int(1/z, exp^(-i(Pi-epsilon)), exp^(i(Pi+epsilon)))?
@edwardlulofs4442 жыл бұрын
We used Churchill for complex analysis in the mid 1970s and it was an excellent textbook. Is this still in print? Or is there a newer text being used?
@mastershooter642 жыл бұрын
Damn Winston Churchill wrote complex analysis books on top of running the UK? nice
@jimskea2242 жыл бұрын
I use both (Brown &) Churchill and Avila's "Variáveis Complexas e Aplicações" for my course in Complex Analysis.
@edwardlulofs4442 жыл бұрын
@@jimskea224 Between Brown, Churchill, and Dr Penn, you can't go wrong. I have a foreign language disability and so haven't read the other text. Thanks.
@abnereliberganzahernandez6337 Жыл бұрын
Wow this is hoe math must de done congrats
@StratosFair Жыл бұрын
Nice lecture, but it would have been nice if you gave an actual definition of the integral over contour lines. Since there is no definition some of the steps in your calculations feel a bit handwavy at times
@jidebranco2168 Жыл бұрын
At 06:00, how did you get (1+i)-squared / 2. Where did the / 2 come from ?
@jacopozavalloni36009 ай бұрын
Guys is there a way to find the solution of exercises that the professor give us ?
@Noam_.Menashe2 жыл бұрын
Next up would be Laurent series?
@diribigal2 жыл бұрын
I imagine Cauchy Integral Formula comes next
@diribigal2 жыл бұрын
At the very beginning, you said that a "domain" is a simply-connected open set (and you needed that for the given version of Cauchy's Theorem). I know of at least one textbook that would just say "connected" open set. Certainly a connected open set contains a simply-connected open set around each point, but is it more common for "domain" to mean "simply-connected"?
@strikeemblem28862 жыл бұрын
My default definition of "domain"/"region" is non-empty + connected + open, the convention used in PDEs. I would say that the responsibility lies on the author to always make sure that he/she follows-up what is precisely meant by "domain", as part of good math writing and communication, just like how it is done here.
@schweinmachtbree10132 жыл бұрын
for subsets of *C* connectedness and simply-connectedness are equivalent so it doesn't matter ( the same is true for subsets of *R* ^ _n_ )
@diribigal2 жыл бұрын
@@schweinmachtbree1013 what definition of simply-connected do you have in mind? In the definition I'm familiar with, the punctured plane or an annulus would be connected yet not simply-connected.
@schweinmachtbree10132 жыл бұрын
@@diribigal oh silly me, it's connectedness and path-connectedness that are equivalent
@rickdoesmath3945 Жыл бұрын
i can't find a good proof of green's theorem anywhere
@DavidMazhambeАй бұрын
man you move too fast its kindah hard to follow up