Introduction to Frobenius Method Part 2

[@fiazB]

Your videos contain the best explanations for the Frobenius Method. Thank you.

[@joywanjiku2317]

Brilliant explanation✅ I finally understand this method.

[@asumakims3954]

Thank you sooo much sir ! You did answers all my mysterious wizardly questions i had before 😂❤

[@Alice-yg9de]

Thank you so much! Wished I have you as my lecturer

[@hudaamer7404]

Thank you! Its very helpful!!

[@abigailcarlson8994]

Extremely helpful series, taking math methods rn.

[@idrisadesina4962]

you helped me a lot! Thank you!

[@PauloHenrique-fk7oo]

Obrigado professor!

[@TinTin-fv4qc]

You're the best!

[@TinTin-fv4qc]

Your students are so lucky!

[@RilahiMMM]

Good explanation ❤... And I have a doubt, In some other videos they added the answers from the both r values to the final answer. Is that correct?

[@daniel_an]

Yes, correct. What I show in the video is only half the solution. At the end, the final solution is the linear combination (i.e. added with coefficients) of the two solutions corresponding to each r value.

[@bonbonpony]

So, if we disregard the xʳ part, and focus only on the power-series part, what would be the differential equation that gives just that part, and how would it be related to the original equation?

[@daniel_an]

Try plugging in x^r*f(x) into the original diff eq. You will see that the d.e. for f still has a singularity (since you only get 1 frobenius solution for each value of r.)

[@Sanoj7261]

Very nice video

[@amarulp]

Thank you so much! :D

[@scitwi9164]

So what is that function in the parenthesis? y(x) = a₀ · √x · f(x) where: f(x) = 1 + x²/(2·7) + x⁴/(2·7)/(4·11) + x⁶/(2·7)/(4·11)/(6·15) + x⁸/(2·7)/(4·11)/(6·15)/(8·19) + … I can see some factorial-like stuff going on in there in the denominator: f(x) = 1 + x²/(2·7) + x⁴/(2·4)/(7·11) + x⁶/(2·4·6)/(7·11·15) + x⁸/(2·4·6·8)(7·11·15·19) + … so it seems to contain the products of even numbers. Can it be rewritten in terms of factorials? Hmm... But how can we make factorial of only _even_ numbers and exclude the odd numbers from the product?.. :|

[@AM-ts4ln]

7:13 scared the s** in me hahhahaha

[@knagaraju8521]

Thankyou bro

[@anudeepg8479]

Than q sirr

[@万柏江]

还是KZbin大学管用

[@Kon03-z3b]

in n=1. A1(2r^2+5r+3). Am i correct or wrong? 2:39