Introduction to Line Integrals - Focus on Parameterizing Curves

  Рет қаралды 29,504

Nakia Rimmer (CalcCoach.com)

Nakia Rimmer (CalcCoach.com)

Күн бұрын

Пікірлер: 22
@NakiaRimmer
@NakiaRimmer 2 жыл бұрын
@12:20 : r(t) should have 3-4t in the first component
@sophiebaird3400
@sophiebaird3400 9 ай бұрын
Thank you SO much! Things that have confused me for a long time finally click when I hear you explain them!
@NakiaRimmer
@NakiaRimmer 9 ай бұрын
Thank you‼️
@CaptainBobSim
@CaptainBobSim 2 жыл бұрын
You are an outstanding teacher! Thank you for this video!
@adithyarajapakshe3791
@adithyarajapakshe3791 3 жыл бұрын
wow! well explained and helpful, thanks, Mr.Rimmer!!
@anysianas5099
@anysianas5099 2 жыл бұрын
you saved my semester I was about to drop my class because it did not understand parametrization
@louismotte5079
@louismotte5079 3 жыл бұрын
thank you mr Rimmer very helpful, and i am glad to have found your videos :)
@muwongeevanspaul9166
@muwongeevanspaul9166 3 жыл бұрын
Am so greatiful, thanks so so so so much....I have clearly understood line integrals....
@Pozizzle
@Pozizzle 3 жыл бұрын
Fantastic explanation!
@jam9339
@jam9339 10 ай бұрын
sobrang maestra ito
@ryandick7264
@ryandick7264 Жыл бұрын
Fantastic video, I never really understood parameterization from Calc 2, and was clueless when the line integral appeared in Calc 3. You've helped me pass
@gregorypayton8308
@gregorypayton8308 Жыл бұрын
sameeee
@JMissEscobedo
@JMissEscobedo Жыл бұрын
Literally my life right now.
@henriquenunes7196
@henriquenunes7196 11 ай бұрын
Great video😊
@azizkash286
@azizkash286 Жыл бұрын
amazing video sir
@elpatron8375
@elpatron8375 3 жыл бұрын
Great video, very well explained and very helpful as well, thanks!
@toniocartonio572
@toniocartonio572 3 жыл бұрын
Hi, how do you parametrize a vertical line? Great vid btw
@NakiaRimmer
@NakiaRimmer 3 жыл бұрын
Hello! Great question. In 2 dimensions a vertical line has equation x = k for some constant k. There is no mention of y in the equation at all. This means that y is free to be anything you want but x is stuck on k. So you would parametrize it by have x = k and y = t. You would allow t to go from your smallest y to your largest y if it is a line segment. If it is the entire line, then t would go from -infinity to infinity. Let me know if you were asking about a vertical line in 3 dimensions.
@toniocartonio572
@toniocartonio572 3 жыл бұрын
@@NakiaRimmer Yes, I was asking in two dimensions, thanks. And if the parametrized line, for example, starts from (2;2) and ends in (0;2), how would parametrize it? Is it y=2, x=t?
@NakiaRimmer
@NakiaRimmer 3 жыл бұрын
@@toniocartonio572 Yes, but the issue you run into is that t starts at 2 and end at 0. t is going backwards, usually you want t to go forwards. What you can do is let x =-t and then t would go from -2 to 0. The thing with parametrizations is that there is no unique way to do it, so you should parametrize whichever way is easiest for you.
@bgvlogs6601
@bgvlogs6601 2 жыл бұрын
For the ending isn't x=3-4t why did you put 3+4t in your parameterized vector r(t)= < 3+4t, 2+6t, 1+6t > ?
@NakiaRimmer
@NakiaRimmer 2 жыл бұрын
Yes, thank you for catching that mistake. I’ll pin a comment with the correction.
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